Bạn gõ lại đề đi :v

Đọc chả hiểu đề gì cả ... đề k có x

Mà phía dưới có cái đáp số x= ... là sao ??

a)(\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{11.12}\)). x=\(\frac{1}{3}\)

(1-\(\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{11}_{ }+\frac{1}{12}\)).x=\(\frac{1}{3}\)

(1+\(\frac{1}{12}\)).x=\(\frac{1}{3}\)

x=\(\frac{1}{3}:\frac{13}{12}\)

x=\(\frac{4}{13}\)

Bài 1:

a) A=1/1.2+1/2.3+1/3.4+...+1/98.99+1/99.100

A=1-1/2+1/2-1/3+1/3-1/4+...+1/98-1/99+1/99-1/100

A=1-1/100

A=99/100

b) B=1/3.5+1/5.7+1/7.9+...+1/145.147

Ta nhân biểu thức trên với 2 ta được

B=2/3.5+2/5.7+2/7.9+...+2/145.147

B=2.(1/3.5+1/5.7+1/7.9+...+1/145.147)

B=2.(1/3-1/5+1/5-1/7+1/7-1/9+...+1/145-1/147)

B=2.(1/3-1/147)

B=2.16/49

B=32/49

Bài 2:

Ta có: 4/11<x/20<5/11

=> 88/220<11x/220<100/220

=> 80<11x<100

=> 11x thuộc {88;99} 

=> x thuộc {8;9}

bạn thuysvaan ơi làm lại câu A đc ko 

Ta có :\(B=\frac{1^2}{1.2}.\frac{2^2}{2.3}.\frac{3^2}{3.4}.\frac{4^2}{4.5}.....\frac{98^2}{98.99}=\frac{\left(1.2.3.4...98\right).\left(1.2.3.4...98\right)}{\left(1.2.3.4...98\right).\left(2.3.4.5...99\right)}=\frac{1}{99}\)

Lại có A = \(\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{97.99}=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{97}-\frac{1}{99}=1-\frac{1}{99}=\frac{98}{99}\)

Lại có \(A:B=\frac{98}{99}:\frac{1}{99}=98\)

=> A = 98B

các bạn có  về sweet home

Đặt \(A=\frac{4}{3.5}+\frac{4}{5.7}+\frac{4}{7.9}+...+\frac{4}{99.101}\)

\(\Rightarrow\frac{1}{2}A=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{99.101}\)

\(\Rightarrow\frac{1}{2}A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{99}-\frac{1}{101}\)

\(\Rightarrow\frac{1}{2}A=\frac{1}{3}-\frac{1}{101}\)

\(\Rightarrow\frac{1}{2}A=\frac{101}{303}-\frac{3}{303}\)

\(\Rightarrow\frac{1}{2}A=\frac{98}{303}\)

\(\Rightarrow A=\frac{98}{303}\div\frac{1}{2}\)

\(\Rightarrow A=\frac{199}{303}\)

\(x+\frac{3}{22}=\frac{27}{121}.\frac{11}{9}\)

\(\Leftrightarrow x+\frac{3}{22}=\frac{27.11}{121.9}\)

\(\Leftrightarrow x+\frac{3}{22}=\frac{3.1}{11.1}\)

\(\Leftrightarrow x+\frac{3}{22}=\frac{3}{11}\)

\(\Leftrightarrow x=\frac{3}{11}-\frac{3}{22}\)

\(\Leftrightarrow x=\frac{6}{22}-\frac{3}{22}\)

\(\Leftrightarrow x=\frac{3}{22}\)

Có:

\(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{x.\left(x+2\right)}=\dfrac{5}{11}\)

\(\Rightarrow\dfrac{1}{2}.\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{x}-\dfrac{1}{x+2}\right)=\dfrac{5}{11}\)

\(\Rightarrow\dfrac{1}{2}.\left(1-0-0-0...-0-\dfrac{1}{x+2}\right)=\dfrac{5}{11}\)

\(\Rightarrow\dfrac{1}{2}.\left(1-\dfrac{1}{x+2}\right)=\dfrac{5}{11}\)

\(\Rightarrow1-\dfrac{1}{x+2}=\dfrac{5}{11}:\dfrac{1}{2}=\dfrac{10}{11}\)

\(\Rightarrow\dfrac{1}{x+2}=1-\dfrac{10}{11}\)

\(\Rightarrow\dfrac{1}{x+2}=\dfrac{1}{11}\)

\(\Rightarrow x+2=11\)

\(\Rightarrow x=11-2=9\)

Vậy x = 9.

Chúc bạn học tốt!

1/1.3 + 1/3.5 + 1/5.7 + ... +1/x.(x+2)

= 1/2.(1/1 - 1/3) + 1/2.(1/3 - 1/5) + 1/2.(1/5 - 1/7) + ... + 1/2.(1/x -1/x+2)

= 1/2.(1/1 - 1/3 + 1/3 - 1/5 + 1/5 - 1/7 + ... + 1/x - 1/x+2 )

= 1/2.(1/1 - 0 - 1/x+2 )

= 1/2 . ( 1/1 - 1/x+2 )

= 1/2 . ( x+2/x+2 - 1/x+2 )

= 1/2 . x+1/x+2

Mà 1/1.3 + 1/3.5 + 1/5.7 + ... +1/x.(x+2) = 5/11

=> 1/2 . x+1/x+2 = 5/11

=> x+1/x+2 = 5/11 : 1/2

=> x+1/x+2 = 10/11

=> x+1/x+2-1 = 10/11-1

=> x+1/x+1 = 10/10

=> x + 1 = 10

=> x = 10 - 1

=> x = 9

Vậy x = 9

\(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\cdots+\frac{1}{x\left(x+2\right)}=\frac{5}{12}\)

\(\frac12\cdot\left(\frac11-\frac13+\frac13-\frac15+\frac15-\frac17+\cdots+\frac{1}{x}-\frac{1}{x+2}_{}\right)=\frac{5}{12}\)

\(\frac12\cdot\left(\frac11-\frac{1}{x+2}\right)=\frac{5}{12}\)

\(1-\frac{1}{x+2}=\frac{5}{12}:\frac12\)

\(1-\frac{1}{x+2}=\frac{5}{12}\cdot2\)

\(1-\frac{1}{x+2}=\frac56\)

\(\frac{1}{x+2}=1-\frac56\)

\(\frac{1}{x+2}=\frac16\)

\(\Rightarrow x+2=6\Rightarrow x=4\)

dưới mẫu là phép nhân của các số lẻ, nhưng đáp án x lại ra bằng 4, gây mâu thuẫn nên bạn xem lại đề thử có chính xác không