\(A=\frac{4116-14}{10290-35}=\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)

\(B=\frac{2929-101}{2.1919+404}=\frac{101\left(29-1\right)}{101\left(38+4\right)}=\frac{28}{42}=\frac{2}{3}\)

Bài toán được giải như sau :

H = 4116-14/10290-35 = 4102/10255 = 2/5

K = 2/3 ( làm như trên nhưng mình làm vậy cho nó nhanh )

L = -4/3

M = -432/17

Oke xong rồi nhé

hi ko nhớ anh à

A = \(\frac{4116-14}{10290-35}\)

A = \(\frac{14.\left(294-1\right)}{35.\left(294-1\right)}\)

A = \(\frac{14}{35}\)

A = \(\frac25\)

Câu b:

B = \(\frac{2929-101}{2.1919+404}\)

B = \(\frac{101.\left(29-1\right)}{101\left(2.19+4\right)}\)

B = \(\frac{28}{38+4}\)

B = \(\frac{28}{42}\)

B = 2/3

A=4116-14/10290-35
=[14 x ( 294 -1 )]/[35 x (294-1)]
= 14/35

B =2929-101/2.1919+404
= [101 x (291-1)] / [101 x 38 + 101 x 4)]
= [ 101x (29 -1)] / [ 101 x (38+4)
= (29-1) / (38+4)
= 28/42 = 2/3

A=4116-14/10290-35=14.294-14.1/35.294-35.1=14.(291-1)/35.(294-1)=14/35=14:7/35:7=2/5

B=2929-101/2.1919+404=101.29-101.1/2.19.101+4.101=101.(29-1)/101.(2.19+4)=28/42=28:14/42:14=2/3

\(A=\frac{2}{5};B=\frac{2}{3}\)