a)SO2,Na2O,CaO,CO2,BaO

SO2+H2O->H2SO3

Na2O+H2O->2NaOH

CaO+H2O->Ca(OH)2

CO2+H2O->H2CO3

BaO+H2O->Ba(OH)2

b)CuO,Na2O,CaO,Al2O3,BaO

CuO+2HCl->CuCl2+H2O

Na2O+2HCl->2NaCl+H2O

CaO+2HCl->CaCl2+H2O

Al2O3+6HCl->2AlCl3+3H2O

BaO+2HCl->BaCl2+H2O

c)SO2,CO2

SO2+2NaOH->Na2SO3+H2O

CO2+2NaOH->Na2CO3+H2O

Bài 2:

a)C+O2->CO2

CO2+CaO->CaCO3

CaCO3+2HCl->CaCl2+CO2+H2O

2CO2+Ca(OH)2->Ca(HCO3)2

b)S+O2->SO2

2SO2+O2->2SO3

SO3+H2O->H2SO4

H2SO4+K2SO3->K2SO4+SO2+H2O

SO2+H2O->H2SO3

2FeS2+6O2-->Fe2O3+4SO2

2SO2+O2-->2SO3(V2O5,to)

SO3+H2O-->H2SO4

b)2Na+2H2O-->2NaOH+H2

2NaOH+H2SO4-->Na2SO4+2H2O

Na2SO4+Ba(OH)2-->BaSO4+2NaOH

2NaOH+CO2-->Na2CO3+H2O

Na2CO3+2HCl-->2NaCl+H2O+CO2

NaCl+AgNO3-->NaNO3+AgCl

C)

4Al+3O2-->2AL2O3

Al2O3+3H2SO4-->Al2(SO4)3+3H2O

Al2(SO4)3+3Ba(OH)2-->3BaSO4+2Al(OH)3

Al(OH)3+NaOH-->NaAlO2+H2O

NaALO2+H2O+CO2-->Al(OH)3+NaHCO3

Al(OH)3+HCl-->AlCl3+H2O

AlCl3+AgNO3-->Al(NO3)3+AgCl

a) 2FeS2 +11/2O2-----> 4SO2 +Fe2O3

2SO2+O2------> 2SO3

SO3+H2O----- -> H2SO4.

b) 2Na +2H2O-----> 2NaOH+H2

2NaOH+H2SO4----> Na2SO4 +2H2O

Na2SO4+Ba(OH)2----> NaOH +BaSO4

2NaOH+CO2----> Na2CO3+H2O

Na2CO3+2HCl----> 2NaCl+H2O+CO2

NaCl+AgNO3--->NaNO3+AgCl

c) 4Al+3O2--- -> 2Al2O3

Al2O3+3H2SO4 -> Al2(SO4)3+3H2O

Al2(SO4)3+6NaOH-> 2Al(OH)3+3Na2SO4

Al(OH)2+NaOH ----> NaAlO2+2H2O

NaAlO2+2H2O+CO2----> Al(OH)3 +NaHCO3

Al(OH)3+3NaOH----> AlCl3+3NaOH

Alcl3+3AgNO3---> Al(NO3)3+3NaCl

CaCO3+HCl-->CaCl2+CO2+H2O

CaCl2+Na2CO3-->CaCO3+NaCl

CaCO3-->CaO+CO2

CaO+H2O-->Ca(OH)2

Ca(OH)2+HNO3-->Ca(NO3)2+H2O

E)

Cu+O2-->CuO

CuO+H2-->Cu+H2O

CuO+..->Cu(Oh)2

Cu(Oh)2+HCl-->CuCl2+H2o

G)Na2SO3+CaCL2-->CaSO3+NaCl

S+O2-->SO2

SO2+H2O-->H2SO3

H2SO3+Ca--->CaSO3+H2

CaSO3+HCl-->CaCL2+SO2+H2O

S₈+O2-->SO3

SO3+H2O-->H2SO4

H2SO4+Fe2O3-->Fe2(SO4)3+H2

Câu 4:

\(n_{H_2SO_4}=\dfrac{200.19,6}{98.100}=0,4mol\)

\(n_{BaCl_2}=\dfrac{50.25}{208.100}\approx0,06mol\)

H₂SO₄+BaCl₂\(\rightarrow\)BaSO₄\(\downarrow\)+2HCl

-Tỉ lệ: \(\dfrac{0,4}{1}>\dfrac{0,06}{1}\rightarrow H_2SO_4dư\)

\(n_{H_2SO_4\left(pu\right)}=n_{BaSO_4}=n_{BaCl_2}=0,06mol\)

\(m_{BaSO_4}=0,06.233=13,98gam\)

\(n_{HCl}=2n_{BaCl_2}=2.0,06=0,12mol\)

\(n_{H_2SO_4\left(dư\right)}=0,4-0,06=0,34mol\)

\(m_{dd}=200+50-13,98=236,02gam\)

C%HCl=\(\dfrac{0,12.36,5}{236,02}.100\approx1,9\%\)

C%H₂SO₄=\(\dfrac{0,34.98}{236,02}.100\approx14,12\%\)

Câu 1:\(\%O=\dfrac{48}{2R+48}.100=47\rightarrow\)(2R+48).47=4800

\(\rightarrow\)94R+2256=4800\(\rightarrow\)94R=2544\(\rightarrow\)R=27(Al)

Bài 1:

a) K: 2K + 2HCl---> 2KCl+ H2

2K + 2H2O ---> 2KOH + H2 (nếu K dư)

Zn: Zn+ 2HCl--> ZnCl2 + H2

Cu: ko có pứ

AgNO3: AgNO3+ HCl ---> AgCl + HNO3

CuO : CuO + 2HCl --> CuCl2 + H2O

NaOH: NaOH + HCl --> NaCl + H2O

Na2SO4: ko có pứ

Mg(OH)2: Mg(OH)2 + 2HCl--> MgCl2 + 2H2O

K2CO3: K2CO3 + 2HCl --- > 2KCl + CO2 + H2O

Al2O3: Al2O3 + 6HCl --> 2AlCl3 + 3H2O

b) Na: 2Na + 2H2O --> 2NaOH

CO2: CO2 + Ba(OH)2 ---> BaCO3 + H2O (nếu Ba(OH)2 dư)

2CO2 + Ba(OH)2 ---> Ba(HCO3)2 (nếu CO2 dư)

H2SO4: Ba(OH)2 + H2SO4 --> BaSO4 + 2H2O

HCl: Ba(OH)2 + 2HCl ---> BaCl2 + H2O

MgSO4: MgSO4 + Ba(OH)2 --> Mg(OH)2 + BaSO4

Al2O3: Al2O3 + 3H2SO4 --> Al2(SO4)3 + 3H2O

NaCl: ko pứ

CuCl2: CuCl2 + Ba(OH)2 ---> Cu(OH)2 + BaCl2

c) K: 2K + 2H2O --> 2KOH + H2

Mg: ko pứ

H2SO4: Na2CO3 + H2SO4 --> Na2SO4 + CO2 + H2O

KOH: ko pứ

Ca(OH)2: Ca(OH)2 + Na2CO3 --> 2NaOH + CaCO3

BaCl2: BaCl2 + Na2CO3 --> 2NaCl + BaCO3

KCl: ko pứ

Bài 2: A: Fe2O3 B: FeCl3

D: Fe(OH)3 E: Fe2O3

4Fe + 3O2 ---> 2Fe2O3

Fe2O3 + 6HCl---> 2FeCl3+ 3H2O

FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl

2Fe(OH)3 ----> Fe2O3 + 3H2O

a,

Phải là FeCl3--->Fe(OH)3

\(\text{FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl }\)

\(\text{2Fe(OH)3 - to--> Fe2O3 + 3H2O}\)

\(\text{Fe2O3 + 3H2SO4 -> Fe2(SO4)3 + 3H2O}\)

\(\text{Fe2(SO4)3 + 3BaCl2 -> 2FeCl3 + 3BaSO4}\)

\(\text{2FeCl3 + 3Ca(OH)2 -> 2Fe(OH)3 + 3CaCl2}\)

b,

\(\text{SO2 + 2NaOH -> Na2SO3 + H2O}\)

\(\text{Na2SO3 + H2SO4 -> Na2SO4 + SO2 + H2O}\)

\(\text{Na2SO4 + Ba(OH)2 -> BaSO4 + 2NaOH}\)

\(\text{2NaOH + ZnCl2 -> Zn(OH)2 + 2NaCl}\)

\(\text{Zn(OH)2 --to--> ZnO + H2O}\)

Câu 5 : a) \(2NaCl+Ba\left(OH\right)_2\rightarrow2NaOH+BaCl_2\downarrow\)

\(2NaOH+BaCO_3\rightarrow Na_2CO_3+Ba\left(OH\right)_2\downarrow\)

\(Na_2CO_3+H_2O\rightarrow2NaOH+CO_2\uparrow\)

\(Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O\)

\(CaCO_3+2HNO_3\rightarrow Ca\left(NO_3\right)_2+H_2O+CO_2\uparrow\)

òm hjhj

X;CO

Y:CO2

z:Ca(Oh)2

==>ý C

Cho sơ đồ phản ứng hóa học sau:

Cacbon+ O2 -------> X + CuO ------> Y+ z ------> T +nung ------> CaO + Y

=> Chọn C. CO, CO2, Ca(OH)2, CaCO3.

\(2C+O_2-^{t^o}\rightarrow2CO\)

\(CuO+CO-^{t^o}\rightarrow Cu+CO_2\)

\(CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\)

\(CaCO_3-^{nung}\rightarrow CaO+CO_2\)