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Câu a:
(4 5/37 - 3 4/5 + 8 15/29) - (3 5/37 - 6 14/29)
= (4 5/37 - 3 5/37) + (8 15/29 + 6 14/29) - 3 4/5
= 1 + 15 - 3 4/5
= 16 - 3 - 4/5
= 13 - 4/5
= 61/5
Câu b:
(2\(\frac56\) + 1\(\frac49\)) : (10\(\frac{1}{12}\) - 9\(\frac12\))
= (17/6 + 13/9) :(121/12 - 19/2)
= (51/18 + 26/18) :(121/12 - 114/2)
= 77/18 : 7/12
= 77/18 x 12/7
= 22/3
\(\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\left(\frac{9}{24}+-\frac{18}{24}+\frac{14}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}.\frac{6}{5}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{2}{4}\)
\(=\frac{3}{4}\)
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\left(\frac{15}{20}-\frac{16}{20}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\frac{-1}{20}\)
\(=\frac{10}{20}+\frac{15}{20}-\frac{-1}{20}\)
\(=\frac{25}{20}-\frac{-1}{20}\)
\(=\frac{26}{20}\)
\(=\frac{13}{10}\)
#)Giải :
a) \(A=\frac{4^5.9^4-2^6.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=-\frac{1}{3}\)
\(a,A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{-1}{3}\)
Học tốt!!!!!!!!!!!!!






\(A=45+\frac{1}{2}-\left(2+\frac{3}{8}\right)-\left(5+\frac{5}{6}+6+\frac{3}{4}\right)+\left(10+\frac{2}{3}-5-\frac{5}{8}\right)\)
\(A=45+\frac{1}{2}-2-\frac{3}{8}-5-\frac{5}{6}-6-\frac{3}{4}+10+\frac{2}{3}-5-\frac{5}{8}\)
\(A=\left(45-2-5-6+10-5\right)+\left(\frac{1}{2}-\frac{3}{8}-\frac{5}{6}-\frac{3}{4}+\frac{2}{3}-\frac{5}{8}\right)\)
\(A=37+\left(\frac{1}{2}-\frac{3}{4}\right)+\left(-\frac{3}{8}-\frac{5}{8}\right)+\left(-\frac{5}{6}+\frac{2}{3}\right)=37-\frac{1}{4}-1-\frac{1}{6}\)
\(A=36-\frac{5}{12}=\frac{427}{12}\)