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Câu a:
1 + {-2 - [-3 + (-4 + |x|)]} = 1 - 2 + [(-3 - 4)]
1 + {-2 -[-3 - 4 + |x|]} = 1 - 2 + [-7]
1 + {-2 - [- 7 + |x|]} = 1 - 2 - 7
1 + {- 2 + 7 - |x|} = - 1 - 7
1 + {5 - |x|} = - 8
5 - |x| = - 8 - 1
5 - |x| = - 9
|x| = 5 + 9
|x| = 14
x = - 14 hoặc x = 14
Vậy x ∈ {-14; 14}
Câu b:
34 + (9 - 21) = 3417 - (x + 3417)
34 + (-12) = 3417 - x - 3417
34 - 12 = 3417 - 3417 - x
22 = - x
x = 22 : (-1)
x = - 22
Vậy x = - 22
a: =>15-(x-2)=-13-27=-40
=>x-2=15+40=55
hay x=57
b: =>5-x=-114+12=-102
=>x=107
c: \(\Leftrightarrow\left|x\right|=-1-5=-6\)(vô lý)
d: \(\Leftrightarrow\left|x-3\right|=3\)
=>x-3=3 hoặc x-3=-3
=>x=6 hoặc x=0
Câu a:
18 - |x - 1| = 2^2
18 - |x - 1| = 4
|x - 1| = 18 - 4
|x - 1| = 14
x - 1 = -14 hoặc x - 1 = 14
Th1: x - 1 = -14
x = - 14 + 1
x = -13
Th2: x - 1 = 14
x = 14 + 1
x = 15
Vậy x ∈ {-13; 15}
Câu b:
x - {55 - [49 + (-28 - x)]} = 13 - {47 + [25 - (32 - x)]}
x - {55 - [49 - 28 - x]} = 13 - {47 + [25 - 32 + x]}
x - {55 - 49 + 28 + x} = 13 - {47 + 25 - 32 + x}
x - {6 + 28 + x} = 13 - {72 - 32 + x}
x - {34 + x} = 13 - {40 + x}
x - 34 - x = 13 - 40 - x
(x - x) + x = 13 - 40 + 34
0 + x = - 27 + 34
x = 7
Vậy x = 7
g) \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{1}{3}\end{cases}}\)
Vây \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\)
\(a\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\\ =>\left(x-\frac{1}{2}\right)=\frac{1}{3}\\ =>x=\frac{1}{3}+\frac{1}{2}\\ =>x=\frac{5}{6}\)
b) \(\left(x+\frac{1}{2}\right)^2=\frac{4}{25}\\ =>\left(x+\frac{1}{2}\right)=\frac{2}{5}\\ =>x=\frac{-1}{10}\)
d) (2x+3)2016=(2x+3)2018 khi 2x+3=0 hoặc 1
Nếu 2x+3=0
=2x=-3 ( loại )
Nếu 2x+3=1
=>2x=-2
=>x=-1 ( thỏa )
a) \(\dfrac{2}{3}x-\dfrac{3}{2}x=\dfrac{5}{12}\)
\(-\dfrac{5}{6}x=\dfrac{5}{12}\)
\(x=-\dfrac{1}{2}\)
b) \(\dfrac{2}{5}+\dfrac{3}{5}\cdot\left(3x-3.7\right)=-\dfrac{53}{10}\)
\(\dfrac{3}{5}\left(3x-3.7\right)=-\dfrac{57}{10}\)
\(3x-3.7=-\dfrac{19}{2}\)
\(3x=-5.8\)
\(x=-\dfrac{29}{15}\)
c) \(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)+\dfrac{5}{9}=\dfrac{23}{27}\)
\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{8}{27}\)
\(2+\dfrac{3}{4}x=\dfrac{21}{8}\)
\(\dfrac{3}{4}x=\dfrac{5}{8}\)
\(x=\dfrac{5}{6}\)
d) \(-\dfrac{2}{3}x+\dfrac{1}{5}=\dfrac{3}{10}\)
\(-\dfrac{2}{3}x=\dfrac{1}{10}\)
\(x=-\dfrac{3}{20}\)




a, <=>(-5)x=(-5)3
<=> x=3
b, <=> 52x=522
<=> x=11
c, 32x=317.315
<=> 32x=332
<=> x=16
d,2x+1=225
<=> x+1=25
<=> x=24
Chúc hok tốt!!!
a)x=3
b)x=11
c)x=16
d)x=24
\(\left(-5\right)^x.5^4=\left(-5\right)^7\)
\(\left(-5\right)^x=\frac{\left(-1\right)^7.5^7}{5^4}\)
\(\left(-5\right)^x=\left(-1\right).5^3\)
\(\left(-5\right)^x=\left(-1\right)^3.5^3\)
\(\left(-5\right)^x=\left(-5\right)^3\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
\(25^x:5^{10}=5^{12}\)
\(5^{2x}:5^{10}=5^{12}\)
\(5^{2x-10}=5^{12}\)
\(\Rightarrow2x-10=12\)
\(2x=22\)
\(x=11\)
Vậy \(x=11\)