Câu a:

5^3 và 3^5

5^3 = 125

3^5 = 243 > 125

Vậy 5^3 < 3^5

Câu b:

16^19 và 8^25

16^19 = (2^4)^19 = 2^76

8^25 = (2^3)25 = 2^75 < 2^76

Vậy 16^19 > 8^25

Câu c:

27^11 và 81^8

27^11 = (3^3)^11 = 3^33

81^8 = (3^4)^8 = 3^32 < 3^33

Vậy 27^11 > 81^8

a,

Ta có:

16¹⁹ = (2⁴)¹⁹ = 2⁷⁶

8²⁵ = (2³)²⁵ = 2⁷⁵

Vì 2⁷⁶ > 2⁷⁵

Nên 16¹⁹ > 8²⁵.

b,

Ta có :

3^{10 =} 3^{2 .5} = (3²)⁵ = 9⁵

2¹⁵ - 2^{3 .5} = (2³)⁵ = 85
Vì 9^{5 >} 8⁵
Nên 3²⁰ > 2¹⁵

16¹⁹=(2⁴)¹⁹=2^4x19=2⁷⁶

8²⁵=\(\left(2^3^{ }\right)^{25}=2^{2.35}=2^{70}\)

vì \(2^{76}>2^{70}=>16^{19}>8^{25}\)

tt nhé

good!

Phạm Ninh Đan: cảm ơn

a/ \(\left(-19\right)+5+\left(-8\right)+19+\left(-3\right).\left(-2\right)^3\)

\(\left(-19\right)+5+\left(-8\right)+19+\left(-3\right).\left(-8\right)\)

\(\left(-19\right)+5+\left(-8\right)+19+24\)

\(\left(-14\right)+11+24\)

\(\left(-3\right)+24=21\)

b/ \(\left(-5\right)^3-\left(3^3+4\right).\left(-2\right)+\left(3-27\right):4\)

\(\left(-125\right)-\left(27+4\right).\left(-2\right)+\left(3-27\right):4\)

\(\left(-125\right)-\left(31\right).\left(-2\right)+\left(-24\right):\text{4}\)

\(\left(-125\right)-\left(-62\right)+\left(-6\right)\)

\(\left(-63\right)+\left(-6\right)=-69\)

c/ \(\left[504-\left(5^2.8+70\right):3^2+6\right]:\left(-20\right)\)

\(\left[504-\left(25.8+70\right):9+6\right]:\left(-20\right)\)

\(\left[504-270:9+6\right]:\left(-20\right)\)

\(\left[504-30+6\right]:\left(-20\right)\)

\(480:\left(-20\right)=-24\)

d/ \(\left(-7\right)-\left[\left(-19\right)+21\right].\left(-3\right)-\left[32+\left(-7\right)\right]\)

\(\left(-7\right)-2.\left(-3\right)-25\)

\(\left(-7\right)-\left(-6\right)-25\)

\(\left(-1\right)-25=-26\)

\(\)