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a. \(3.5^2+15.2^2-26:2\)
\(=3.25+15.4-26:2\)
\(=75+60-13\)
\(=122\)
b. \(5^3.2-100:4+2^3.5\)
\(=125.2-100:4+8.5\)
\(=250-25+40\)
\(=265\)
c. \(6^2:9+50.2-3^3.3\)
\(=36:9+50.2-27.3\)
\(=4+100-81\)
\(=23\)
d. \(3^2.5+2^3.10-81:3\)
\(=9.5+8.10-81:3\)
\(=45+80-27\)
\(=98\)
e. \(5^{13}:5^{10}-25.2^2\)
\(=5^3-25.4\)
\(=125-100\)
\(=25\)
f. \(20:2^2+5^9:5^8\)
\(=20:4+5\)
\(=5+5=10\)
sau 58 ,7,50 ,2,-60 là phép tính khác .
mấy b giúp mk nha ?
e) \(5^{13}:5^{10}-25.2^2\)
\(=5^3-5^2.2^2\)
\(=5^2\left(5-2^2\right)\)
\(=25\)
e) 513 : 510 - 25 . 22 f) 20:22+59:58 g) 100+ 52+ 7.32 h) 84:4+39:37+50 i) 29- [16+ 3. (51- 49)]
= 53 - 25 . 4 = 20 :4 + 5 = 100+ 25+ 7.9 = 21+ 32+ 1 = 29- [16+ 3.2 ]
=125 - 100 = 5+ 5 = 125+ 63 = 21+ 9+ 1 = 29- [16+ 6]
=25 = 10 = 188 = 31 = 29 - 22
=7
A = 1 . 3 + 3 . 5 + 5 . 7 + ... + 49 . 51
= 1 . 51
= 51
B = 2 . 4 + 4 . 6 + 6 . 8 + ... + 98 . 100
= 2 . 100
= 200
C = 1 . 4 + 4 . 7 + 7 . 10 + ... + 301 . 304
= 1 . 304
= 304
D = 1 + 1 . 1! + 2 . 2! + 3 . 3! + ... + 100 . 100!
= 1 . 100
= 100
E = 22 + 42 + ... + ( 2n )2
= 22 . ( 2n )2
= 2n4
\(a)47-\left[\left(45.2^4-5^2.12\right):14\right]\)
\(=47-\left[\left(45.16-25.12\right):14\right]\)
\(=47-\left[\left(720-300\right):14\right]\)
\(=47-\left[420:14\right]\)
\(=47-30\)
\(=17\)
\(b)50-\left[\left(20-2^3\right):2+34\right]\)
\(=50-\left[\left(20-8\right)\right]:2+34\)
\(=50-\left[12:2+34\right]\)
\(=50-\left[6+34\right]\)
\(=50-40\)
\(=10\)
\(c)10^2-\left[60:\left(5^6:5^4-3,5\right)\right]\)
\(=10^2-\left[60:\left(5^2-3,5\right)\right]\)
\(=10^2-\left[60:\left(25-3,5\right)\right]\)
\(=10^2-\left[60:21,5\right]\)
\(=100-\dfrac{120}{43}\)
\(=\dfrac{4180}{43}\)
\(d)50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left[10:2+3\right]\)
\(=50-5+3\)
\(=50-8\)
\(=42\)
\(e)10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
\(f)8697-\left[3^7:3^5+2.\left(13-3\right)\right]\)
\(=8697-\left[3^2+2.\left(13-3\right)\right]\)
\(=8697-\left[9+2.10\right]\)
\(=8697-9+20\)
\(=8697-29\)
\(=8668\)
\(g)2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5.\left[300-10^2\right]\)
\(=2011+5.\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
\(h)695-\left[200+\left(11-1\right)^2\right]\)
\(=695-\left[200+10^2\right]\)
\(=695-200+100\)
\(=695-300\)
\(=395\)
\(i)129-5\left[29-\left(6-1\right)^2\right]\)
\(=129-5\left[29-5^2\right]\)
\(=129-5\left[29-25\right]\)
\(=129-5.4\)
\(=129-20\)
\(=109\)
a, 3.5^2+15.2^2-26:2
=3.25+15.4-13
=75+60-13
=135-13
=122
b, 5^3.2-100:4+2^3.5
=125.2-25+8.5
=250-25+40
=225+40
=265
a,3.52 + 15.22 - 26:2
=3.25 + 15.4 -26:2
=75+60-13
=122
b,53.2 - 100:4 + 23.5
=125.2 - 100:4 + 8.5
=250 - 25 +40
=265
c,62:9 + 50.2 - 33.3
=36:9 + 50.2 -27.3
=4 + 100 -81
=23
d,32.5 + 23.10 - 81:3
=9.5 +8.10 - 81:3
=45 + 80 -27
=98
e,513:510 - 25.22
=53 - 25.4
=125 - 100
=25
a) 3.52 + 15.22 - 26:2
=3.25 + 15.4 - 13
=75 + 60 -13
=117
b) 53.2 - 100:4 +23.5
=125.2 -25 + 8.5
=250 - 25 + 40
=265
c)62 : 9 + 50.2 - 33.3
=36:9 + 100 - 37.3
=4 + 100 - 81
=23
d)32.5 + 23.10 - 81:3
=9.5 + 8.10 - 27
=45 + 80 - 27
=98
e)513 : 510 - 25.22
=53 - 25.4
=125 - 100
=25
K NHA
=-7
A = 1 . 3 + 3 . 5 + 5 . 7 + ... + 49 . 51
A=1*51
A=
B = 2 . 4 + 4 . 6 + 6 . 8 + ... + 98 . 100
B=2*100
B=200
C = 1 . 4 + 4 . 7 + 7 . 10 + ... + 301 . 304
C=1*304
C=304
D = 1 + 1 . 1! + 2 . 2! + 3 . 3! + ... + 100 . 100!
D=1*100!
D=100!
E = 22 + 42 + ... + ( 2n )2
E=\(2^2\cdot2n^2\)
E=\(2n^4\)
a)122
b)265
c)7
d)4
a) =148
b) =265
c) =7
d) =4
cho mik sin cách chình bày đk ạ
cho mik xin cách trình bầy được ko ạ
A = 75 +60-13=122.B = 250-25+40=265.C=29-[16+3.2] ➙29-22=7 D= 10-[16.5+88]:28➙ 10-168:28➙10-6=4
cách trình bày đk bn
MÌNh ko xuống dòng được