a. x³+5x²+3x-9

= x³-x²+6x²-6x+9x-9

= x²(x-1)+6x(x-1)+9(x-1)

= (x²+6x+9)(x-1)

= (x+3)²(x-1)

b. x³+9x²+11x-21

= x³-x²+10x²-10x+21x-21

= x²(x-1)+10x(x-1)+21(x-1)

= (x²+10x+21)(x-1)

= (x+7)(x+3)(x-1)

c. x³-7x+6

= x³-x²+x²-x-6x+6

= x²(x-1)+x(x-1)-6(x-1)

= (x²+x-6)(x-1)

= (x+3)(x-2)(x-1)

d. x³-5x²+8x-4

= x³-x²-4x²+4x+4x-4

= x²(x-1)-4x(x-1)+4(x-1)

= (x²-4x+4)(x-1)

= (x-2)²(x-1)

e. x³-3x+2

= x³+2x²-2x²-4x+x+2

= x²(x+2)-2x(x+2)+(x+2)

= (x²-2x+1)(x+2)

= (x-1)²(x+2)

f. x³+8x²+17x+10

= x³+5x²+3x²+15x+2x+10

= x²(x+5)+3x(x+5)+2(x+5)

= (x²+3x+2)(x+5)

= (x+1)(x+2)(x+5)

g. x³+3x²+6x+4

= x³+x²+2x²+2x+4x+4

= x²(x+1)+2x(x+1)+4(x+1)

= (x²+2x+4)(x+1)

h. x³-2x-4

= x³-2x²+2x²-4x+2x-4

= x²(x-2)+2x(x-2)+2(x-2)

= (x²+2x+2)(x-2)

k. x³+x²+4

= x³+2x²-x²-2x+2x+4

= x²(x+2)-x(x+2)+2(x+2)

= (x²-x+2)(x+2)

l. x³-12x+7x-2

= x³+2x²-2x²-4x-x-2

= x²(x+2)-2x(x+2)-(x+2)

= (x²-2x-1)(x+2)

thansk you

a. x³+4x²-29x+24

a) =x³-2x²+x²-2x+x-2

=x²(x-2)+x(x-2)+(x-2)

=(x-2)(x²+x+1)

\(a.=x^3-2x^2+x^2-2x+x-2=x^2\left(x-2\right)+x\left(x-2\right)+\left(x-2\right)=\left(x-2\right)\left(x^2+x+2\right)\)

b.\(=2x^3+x^2-2x^2-x-2x-1=x^2\left(2x+1\right)-x\left(2x-1\right)-\left(2x-1\right)\)\(=\left(2x-1\right)\left(x^2-x-1\right)\)

c.\(3x^3-x^2+6x^2-2x-12x+4=x^2\left(3x-1\right)+2x\left(3x-1\right)-4\left(3x-1\right)\)\(=\left(3x-1\right)\left(x^2+2x-4\right)\)

d.\(3x^3-x^2-6x^2+2x+15x-5=x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)\(=\left(3x-1\right)\left(x^2-2x+5\right)\) 

t i c k cho mình nha

a)

\(A=\dfrac{x^2\left(x^2+5x-3\right)-2x\left(x^2+5x-3\right)-4\left(x^2+5x-3\right)+14x-12+ax+y\left(b\right)}{x^2+5x-3}\)\(A=x^2-2x-4+\dfrac{14x-12+ax+y\left(b\right)}{x^2+5x-3}\)

nếu b=y

\(\left\{{}\begin{matrix}a=-14\\b=12\end{matrix}\right.\)

nếu b khác y

a =-14 ; y =12 với mọi b

Hãy tích cho tui đi

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tui không tích lại bạn đâu

THANKS

a, 3x³-8x²+8x-5

= x²(3x-5)-x(3x-5)+3x-5

=(3x-5)(x²-x+1)

b, 4x³-3x²+5x-21

= x²(4x-7) +x(4x-7)+3(4x-7)

=(4x-7)(x²+x+3)