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Câu a:
{3849 - 2.[146 - (2.14 + 6: 2)]} : 32
= {3849 - 2.[146 - (28 + 3)]} : 32
= {3489 - 2.[146 - 31]} : 32
= {3489 - 2.115} : 32
= {3489 - 230} : 32
= 3259 : 32
= 3259/32
Câu b:
134 - 2.{156 - 6[54 - 2.(9 + 6)]}
= 134 - 2.{156 - 6.[54- 2. 15]}
= 134 - 2.{156 - 6.[54 - 30]}
= 134 - 2.{156 - 6.24]
= 134 - 2.12
= 134 - 24
= 110
a,-3/5.2/7+-3/7.3/5+-3/7
=-3/7.2/5+(-3/7).3/5+(-3/7)
=-3/7(2/5+3/5+1)
=-3/7.2
=-6/7
a) A = \(\frac{101}{19}.\) \(\frac{61}{218}-\frac{101}{218}.\frac{42}{19}+\frac{117}{218}\)
= \(\frac{101}{218}.\frac{61}{19}-\frac{101}{218}.\frac{42}{19}+\frac{117}{218}\)
=\(\frac{101}{218}.\left(\frac{61}{19}-\frac{42}{19}\right)+\frac{117}{218}\)
=\(\frac{101}{218}.\frac{19}{19}+\frac{117}{218}\)
=\(\frac{101}{218}.1+\frac{117}{218}\)
=\(\frac{101}{218}+\frac{117}{218}\)
=\(\frac{218}{218}\)\(=1\)
b) B = \(\left(\frac{5}{2011^2}+\frac{7}{2012^2}-\frac{9}{2013^2}\right).\left(\frac{4}{5}-\frac{3}{4}-\frac{1}{20}\right)\)
= \(\left(\frac{5}{2011^2}+\frac{7}{2012^2}-\frac{9}{2013^2}\right)\)\(.\left(\frac{1}{20}-\frac{1}{20}\right)\)
= \(\left(\frac{5}{2011^2}+\frac{7}{2012^2}-\frac{9}{2013^2}\right).0\)
= \(0\)
a) \(\frac{2}{5}+\left(\frac{3}{4}-\frac{7}{10}\right)\)
\(=\frac{2}{5}+\frac{1}{20}\)
\(=\frac{9}{20}\)
b) \(\frac{-1}{8}-\left(\frac{2}{3}-\frac{11}{12}\right)\)
\(=-\frac{1}{8}-\left(-\frac{1}{4}\right)\)
\(=\frac{1}{8}\)
c) \(\frac{7}{5}-\left(\frac{1}{6}+\frac{9}{10}\right)\)
\(=\frac{7}{5}-\frac{16}{15}\)
\(=\frac{1}{3}\)
d) \(\frac{2}{3}+\left(-\frac{1}{4}\right)+\frac{7}{12}-\left(-\frac{1}{4}\right)-\frac{5}{6}\)
\(=\left(\frac{2}{3}+\frac{7}{12}-\frac{5}{6}\right)+\left(-\frac{1}{4}+\frac{1}{4}\right)\)
\(=\left(\frac{5}{4}-\frac{5}{6}\right)+0\)
\(=\frac{5}{12}\)
e) \(2-\left\{\frac{1}{2}-\left[2-\left(\frac{1}{2}+2\right)-\frac{1}{2}\right]+2\right\}\)
\(=2-\left[\frac{1}{2}-\left(2-\frac{5}{2}-\frac{1}{2}\right)+2\right]\)
\(=2-\left[\frac{1}{2}-\left(-1\right)+2\right]\)
\(=2-\frac{7}{2}\)
\(=-\frac{3}{2}\)


