
\(\left(x-9\right)\left(x-7\right)+1\)
b)\(\left(x^2+x-1\...">
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời. a)\(=\left(x^2-7x-9x+63\right)+1\) \(=x^2-7x-9x+63+1\) =\(x^2-16x+64\) \(=\left(x-8\right)^2\) a: \(=x^2-16x+63+1\) \(=x^2-16x+64=\left(x-8\right)^2\) b: \(=\left(x^2+x\right)^2-2\left(x^2+x\right)+1+4\left(x^2+x\right)\) \(=\left(x^2+x\right)^2+2\left(x^2+x\right)+1\) \(=\left(x^2+x+1\right)^2\) c: \(=\left(x+2y-3-2\right)^2\) \(=\left(x+2y-5\right)^2\) d: \(=\left(x-y\right)^3-1-3\left(x-y\right)^2+3\left(x-y\right)\) \(=\left(x-y-1\right)^3\) Bài 1 : a ) \(2x\left(x+1\right)+2\left(x+1\right)=\left(x+1\right)\left(2x+2\right)=2\left(x+1\right)^2\) b ) \(y^2\left(x^2+y\right)-zx^2-zy=y^2\left(x^2+y\right)-z\left(x^2+y\right)=\left(x^2+y\right)\left(y^2-z\right)\) c ) \(4x\left(x-2y\right)+8y\left(2y-x\right)=4x\left(x-2y\right)-8y\left(x-2y\right)=4\left(x-2y\right)^2\) d ) \(3x\left(x+1\right)^2-5x^2\left(x+1\right)+7\left(x+1\right)=\left(x+1\right)\left(3x^2+3x-5x^2+7\right)=\left(x+1\right)\left(3x-2x^2+7\right)\) e ) \(x^2-6xy+9y^2=\left(x-3x\right)^2\) Bài 1 : f ) \(x^3+6x^2y+12xy^2+8y^3=\left(x+2y\right)^3\) g ) \(x^3-64=\left(x-4\right)\left(x^2+4x+16\right)\) h ) \(125x^3+y^6=\left(5x+y^2\right)\left(25x^2-5xy^2+y^4\right)\) a) \(5x(x-2y)+2(2y-x)^2=5x(x-2y)+2(x-2y)^2\) \(=(x-2y)[5x+2(x-2y)]=(x-2y)(7x-4y)\) b) \(7x(y-4)^2-(4-y)^3=7x(y-4)^2+(y-4)^3=(y-4)^2(7x+y-4)\) c) \((4x-8)(x^2+6)-(4x-8)(x+7)+9(8-4x)\) \(=(4x-8)(x^2+6)-(4x-8)(x+7)-9(4x-8)\) \(=(4x-8)[(x^2+6)-(x+7)-9]=(4x-8)(x^2-x-10)=4(x-2)(x^2-x-10)\) d) \(x^2-xz-9y^2+3yz=(x^2-9y^2)-(xz-3yz)\) \(=(x-3y)(x+3y)-z(x-3y)=(x-3y)(x+3y-z)\) e) \(x^2(x^2-6)-x^2+9=x^4-7x^2+9=(x^4-6x^2+9)-x^2\) \(=(x^2-3)^2-x^2=(x^2-3-x)(x^2-3+x)\) a) \(5x(x-2y)+2(2y-x)^2=5x(x-2y)+2(x-2y)^2\) \(=(x-2y)[5x+2(x-2y)]=(x-2y)(7x-4y)\) b) \(7x(y-4)^2-(4-y)^3=7x(y-4)^2+(y-4)^3=(y-4)^2(7x+y-4)\) c) \((4x-8)(x^2+6)-(4x-8)(x+7)+9(8-4x)\) \(=(4x-8)(x^2+6)-(4x-8)(x+7)-9(4x-8)\) \(=(4x-8)[(x^2+6)-(x+7)-9]=(4x-8)(x^2-x-10)=4(x-2)(x^2-x-10)\) d) \(x^2-xz-9y^2+3yz=(x^2-9y^2)-(xz-3yz)\) \(=(x-3y)(x+3y)-z(x-3y)=(x-3y)(x+3y-z)\) e) \(x^2(x^2-6)-x^2+9=x^4-7x^2+9=(x^4-6x^2+9)-x^2\) \(=(x^2-3)^2-x^2=(x^2-3-x)(x^2-3+x)\) \(a,3x^3y^3-15x^2y^2=3x^2y^2\left(xy-5\right)\) \(b,5x^3y^2-25x^2y^3+40xy^4\) \(=5xy^2\left(x^2-5xy+8y^2\right)\) \(c,-4x^3y^2+6x^2y^2-8x^4y^3\) \(=-2x^2y^2\left(2x-3+4x^2y\right)\) \(d,a^3x^2y-\frac{5}{2}a^3x^4+\frac{2}{3}a^4x^2y\) \(=a^3x^2\left(y-\frac{5}{2}x^2+\frac{2}{3}ay\right)\) \(e,a\left(x+1\right)-b\left(x+1\right)=\left(x+1\right)\left(a-b\right)\) \(f,2x\left(x-5y\right)+8y\left(5y-x\right)\) \(=2x\left(x-5y\right)-8y\left(x-5y\right)=\left(x-5y\right)\left(2x-8y\right)\) \(g,a\left(x^2+1\right)+b\left(-1-x^2\right)-c\left(x^2+1\right)\) \(=\left(x^2+1\right)\left(a-b-c\right)\) \(h,9\left(x-y\right)^2-27\left(y-x\right)^3\) \(=9\left(x-y\right)^2+27\left(x-y\right)^3\) \(=9\left(x-y\right)^2\left(1+3x-3y\right)\) a,3x3y3−15x2y2=3x2y2(xy−5)a,3x3y3−15x2y2=3x2y2(xy−5) b,5x3y2−25x2y3+40xy4b,5x3y2−25x2y3+40xy4 =5xy2(x2−5xy+8y2)=5xy2(x2−5xy+8y2) c,−4x3y2+6x2y2−8x4y3c,−4x3y2+6x2y2−8x4y3 =−2x2y2(
Bài 1: a) \(3x^2-2x(5+1,5x)+10=3x^2-(10x+3x^2)+10\) \(=10-10x=10(1-x)\) b) \(7x(4y-x)+4y(y-7x)-2(2y^2-3,5x)\) \(=28xy-7x^2+(4y^2-28xy)-(4y^2-7x)\) \(=-7x^2+7x=7x(1-x)\) c) \(\left\{2x-3(x-1)-5[x-4(3-2x)+10]\right\}.(-2x)\) \(\left\{2x-(3x-3)-5[x-(12-8x)+10]\right\}(-2x)\) \(=\left\{3-x-5[9x-2]\right\}(-2x)\) \(=\left\{3-x-45x+10\right\}(-2x)=(13-46x)(-2x)=2x(46x-13)\) Bài 2: a) \(3(2x-1)-5(x-3)+6(3x-4)=24\) \(\Leftrightarrow (6x-3)-(5x-15)+(18x-24)=24\) \(\Leftrightarrow 19x-12=24\Rightarrow 19x=36\Rightarrow x=\frac{36}{19}\) b) \(\Leftrightarrow 2x^2+3(x^2-1)-5x(x+1)=0\) \(\Leftrightarrow 2x^2+3x^2-3-5x^2-5x=0\) \(\Leftrightarrow -5x-3=0\Rightarrow x=-\frac{3}{5}\) \(2x^2+3(x^2-1)=5x(x+1)\)
