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A=(9-3/5+2/3)-(7+7/5-3/2)-(9/5+5/2)
A=9 -3/5 +2/3-7-7/5+3/2-9/5-5/2
A=(9-7)-(3/5+7/5 +9/5)+(3/2-5/2)+2/3
=2-19/5-1+2/3= -32/15
\(A=9-\frac{3}{5}+\frac{2}{3}-7-\frac{7}{5}+\frac{3}{2}-3+\frac{9}{5}-\frac{5}{2}\)
\(=\left(9-7-3\right)+\left(\frac{9}{5}-\frac{7}{5}-\frac{3}{5}\right)+\left(\frac{3}{2}-\frac{5}{2}\right)\)
\(=-2-\frac{1}{5}=-\frac{11}{5}\)
a) \(-1\frac{5}{7}.15+\frac{2}{7}.\left(-15\right)+\left(-105\right).\left(\frac{2}{3}-\frac{4}{5}+\frac{1}{7}\right)\)
\(=1\frac{5}{7}.\left(-15\right)+\frac{2}{7}.\left(-15\right)+\left(-105\right).\left(\frac{70}{105}-\frac{84}{105}+\frac{15}{105}\right)\)
\(=\left(-15\right)\left(1+\frac{5}{7}+\frac{2}{7}\right)+\left(-105\right).\frac{1}{105}\)
\(=-30-1=-31\)
b) \(\frac{2}{3}+\frac{3}{4}.\left(-\frac{4}{9}\right)\)
= \(=\frac{2}{3}+\frac{3.\left(-4\right)}{4.9}=\frac{2}{3}+\frac{-1}{3}=\frac{1}{3}\)
c) \(\left(\frac{3}{4}-0,2\right).\left(0,4-\frac{4}{5}\right)\)
\(=\left(\frac{3}{4}-\frac{1}{5}\right).\left(\frac{2}{5}-\frac{4}{5}\right)=\frac{11}{20}.\left(\frac{-2}{5}\right)=\frac{11.\left(-1\right).2}{2.10.5}=\frac{-11}{50}\)
1)
a) \(-\frac{9}{34}:\frac{17}{4}\)
\(=-\frac{18}{289}.\)
b) \(1\frac{1}{2}.\frac{1}{24}\)
\(=\frac{3}{2}.\frac{1}{24}\)
\(=\frac{1}{16}.\)
c) \(-\frac{5}{2}:\frac{3}{4}\)
\(=-\frac{10}{3}.\)
d) \(4\frac{1}{5}:\left(-2\frac{4}{5}\right)\)
\(=\frac{21}{5}:\left(-\frac{14}{5}\right)\)
\(=-\frac{3}{2}.\)
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\(A=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)
\(=\left(\frac{1}{5}-\frac{1}{5}\right)+\left(-\frac{3}{7}+\frac{3}{7}\right)+\left(\frac{5}{9}-\frac{5}{9}\right)+\left(-\frac{2}{11}+\frac{2}{11}\right)+\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{9}{16}\)
\(=0+0+0+0+0+\frac{9}{16}=\frac{9}{16}\)
TH1: \(A=\left(9-\frac35+\frac23\right)-\left(7+\frac75-\frac32\right)-\left(3-\frac95+\frac52\right)\)
\(=\left(\frac{135}{15}-\frac{9}{15}+\frac{10}{15}\right)-\left(\frac{70}{10}+\frac{14}{10}-\frac{15}{10}\right)-\left(\frac{30}{10}-\frac{18}{10}+\frac{25}{10}\right)\)
\(=\frac{136}{15}-\frac{69}{10}-\frac{37}{10}=\frac{136}{15}-\frac{106}{10}=\frac{272}{30}-\frac{318}{30}=-\frac{46}{30}=-\frac{23}{15}\)
TH2: \(A=\left(9-\frac35+\frac23\right)-\left(7+\frac75-\frac32\right)-\left(3-\frac95+\frac52\right)\)
\(=9-\frac35+\frac23-7-\frac75+\frac32-3+\frac95-\frac52\)
\(=\left(9-7-3\right)+\left(-\frac35-\frac75+\frac95\right)+\left(\frac32-\frac52\right)+\frac23=-1-\frac15-1+\frac23\)
\(=-2-\frac15+\frac23=-\frac{30}{15}-\frac{3}{15}+\frac{10}{15}=-\frac{23}{15}\)