\(a=4^5.9^4-2.\dfrac{6^9}{2^{10}}.3^8+6^8.20\)

Đề là như vầy đúng ko bn?

$\textbf{A)}$

$\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}$

$=\dfrac{(2^2)^5(3^2)^4-2(2\cdot3)^9}{2^{10}\cdot3^8+2^2\cdot5(2\cdot3)^8}$

$=\dfrac{2^{10}3^8-2^{10}3^9}{2^{10}3^8+2^{10}\cdot5\cdot3^8}$

$=\dfrac{2^{10}3^8(1-3)}{2^{10}3^8(1+5)}$

$=\dfrac{-2}{6}$

$=-\dfrac{1}{3}.$

/ là dấu gì vậy bạn

Đó là dấu chia(:)đó!

8²⁰+4²⁰/4²⁵+64²⁵

=(2³)²⁰+1/4⁵+(2⁶)²⁵

=2⁶⁰+1/1024+2¹⁵⁰

^{Sorry,mk làm đc đến đây thui!}

8^20 + 4^20 / 4^25 + 64^5

= 2^60 + 2^40 / 2^50 + 2^30

= 2^40 x (2^20 +1) / 2^30 x (2^20 +1)

= 2^10

= 1024

chúc bạn làm zui zẻ + tốt nhé

\(B=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}}{2^{30}}=2^{10}=1024\)

\(=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=2^{10}=1024\)

ta có : \(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)

\(=\dfrac{2^{40}}{2^{30}}=2^{10}=1024\)

đề là gì bn Nguyễn Thị Hồng Ngân

\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{10}+2^{10}}{1+1}=1024\)