a) (12-46)+(46+88)

= 12-46+46+88

= (12+88)+[(-46)+46]

= 100+0

=100.

b) (14+67)+(33-14+100)

= 14+67+33-14+100

=[ [14+(-14)]+[(67+33)+100]

= 0+200

= 200.

c) (35+12-47)-(12+53+65)

= 35+12-47-12-53-65

=[12+(-12)]+[(-47)+(-53)]+[35+(-65)]

=0+(-100)+(-30)

=(-100)+(-30)

=-130.

Chúc bạn học tốt !!!

a) (12-46)+(46+88)=12-46+46+88

=(12+88)-(46-46)=100

b) (14+67)+(33-14+100)=14+67+33-14+100

=(14-14)+100+(67+33)=100+100=200

c) (35+12-47)-(12+53+65)=35+12-47-12-53-65

=(12-12)-(47+53)-(65-35)= -100-30

=-130

46+(88-4.x):4=65

(88-4.x):4=65-46

(88-4.x):4=19

88-4.x=19.4

88-4.x=76

4.x=88-76

4.x=12

x=12:4

x=3

912-(476-16.x):7=69

(476-16.x):7=912-69

(476-16.x):7=843

476-16.x=843.7

476-16.x=5901

16.x=476-5901

16.x=(-5425)

x=(-5425):16

x=(-339,0625)

li-ke cho mình nha mình đang cần li-ke

46 + ( 88 - 4x ) : 4 = 65

( 88 - 4x ) : 4= 65- 46

( 88 - 4x ) = 19

( 88 - 4x ) = 19x 4

88-4x = 76

4x = 88- 76

4x = 8

x = 8 : 4

x = 2

c) - 34 + 54 - ( 157 + 43 ) = - 180

d ) 1+ 99 -(2 + 98) + 3 + 97 - (4 + 96) + .....+ (- 100 ) = - 100

a) 154 + 46 - ( 12 + 88 ) = 100

b) 2011 + 1989 - ( 596 + 404 ) = 3000

(3x-1)^6+746=810

(3x-1)^6=810-746

(3x-1)^6=64

(3x-1)^6=2^6

3x-1=2

3x=2+1

3x=3

x=3:3

x=1 

Vậy x=1

chẳng biết đúng hay sai

(3x-1)^6+746=810

(3x-1)^6=64

(3x-1)^6=2^6

TH1:3x-1=2                                            TH2:3x-1=-2

3x=3 => x=1                                                   3x=-1 => x=-1/3

Vậy x\(\in\) {-1;1}

Xin 1 k nha.

5.20598352035547e+19

a, Hình như câu a SBC phải là 756 hay sao ấy, lúc đó x=27

b, 1014

c, 17

d, 42

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ủng hộ mk

tk mk

kb rồi nhé

\(< \)

Code : Breacker

a, 4,5 - 2x . 147 = 1114

2x . 147 = 4,5 - 1114

2x . 147 = -1109,5

2x = -1109,5 / 147

2x = \(-\dfrac{317}{42}\)

x = \(-\dfrac{317}{42}:2\)

x = \(-\dfrac{317}{84}\)

b, ( x + 14 - 13 ) : ( 2 + 16 - 14 ) = 746

( x + 1 ) : 4 = 746

x + 1 = 746 . 4

x + 1 = 2984

x = 2984 - 1

x = 2983

c, \(\dfrac{13}{15}-\left(\dfrac{13}{21}+x\right).\dfrac{7}{12}=\dfrac{7}{10}\)

\(\left(\dfrac{13}{21}+x\right).\dfrac{7}{12}=\dfrac{13}{15}-\dfrac{7}{10}\)

\(\left(\dfrac{13}{21}+x\right).\dfrac{7}{12}=\dfrac{1}{6}\)

\(\dfrac{13}{21}+x=\dfrac{1}{6}:\dfrac{7}{12}\)

\(\dfrac{13}{21}+x=\dfrac{2}{7}\)

\(x=\dfrac{2}{7}-\dfrac{13}{21}\)

\(x=-\dfrac{1}{3}\)