6^x . 6 = 2016

6^x = 2016 : 6

6^x = 336

=> x \(\in\varnothing\)

4^2x+3 : 4 = 256

4^2x+3 = 256 x 4

4^2x+3 = 1024

4^2x+3 = 4⁵

2x + 3 = 5

2x = 5 - 3

2x = 2

  x = 2 : 2

  x = 1

[ x - 2 ]² = 16

[ x - 2 ]² = 4²

x - 2 = 4

      x = 4 + 2

      x = 6

[ 2x - 1 ]³ = 27

[ 2x - 1 ]³ = 3³

2x - 1 = 3

2x = 3 + 1

2x = 4

  x = 4 : 2

  x = 2

[ 2x - 1 ]¹⁰⁰ = [ 2x - 1 ]¹⁰⁰

=> x \(\in N\)

bạn tính đi..... dụa vào t/c á....

XÀM

a) 2^x+1 : 4 = 16

    2^x+1 = 16 . 4 = 64 = 2⁶

=> x + 1 = 6

     x = 6 - 1 = 5

b) (x - 2)³ = 27 = 3³

=> x - 2 = 3

     x = 3 + 2 = 5

c) 101⁰ + x = 100

    1 + x =100

    x = 100 - 1 = 99

d) (18 - 2³) + 2x = 2² . 15 = 4 . 15 = 60

    (18 - 8) + 2x = 60

    10 + 2x = 60

    2x = 60 - 10 = 50

    x = 50 : 2 = 25

tick nha

a. 2^x+1:4=16

=> 2^x+1=16.4

=> 2^x+1=64

=> 2^x+1=2⁶

=> x+1=6

=> x=5

b. (x-2)³=27

=> (x-2)³=3³

=> x-2=3

=> x=3+2

=> x=5

c. 101⁰+x=100

=> 1+x=100

=> x=100-1

=> x=99

d. (18-2³)+2x=2².15

=> (18-8)+2x=4.15

=> 10+2x=60

=> 2x=60-10

=> 2x=50

=> x=50:2

=> x=25.

                  Bài làm :

\(1\text{)}...\Leftrightarrow\orbr{\begin{cases}\left(1+3x\right)^4=4^4\Leftrightarrow1+3x=4\Leftrightarrow3x=3\Leftrightarrow x=1\\\left(1+3x\right)^4=\left(-4\right)^4\Leftrightarrow1+3x=-4\Leftrightarrow3x=-5\Leftrightarrow x=-\frac{5}{3}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=1\\x=-\frac{5}{3}\end{cases}}\)

\(2\text{)}...\Leftrightarrow720\div\left(x-140\right)=-5\Leftrightarrow x-140=-144\Leftrightarrow x=-4\)

\(3\text{)}...\Leftrightarrow\left(2^4\right)^x.\left(2^2\right)^3=2^9\Leftrightarrow2^{4x}.2^6=2^9\Leftrightarrow2^{4x}=2^3\Leftrightarrow4x=3\Leftrightarrow x=\frac{3}{4}\)

\(4\text{)}...\Leftrightarrow\orbr{\begin{cases}\left(2x-1\right)^4=3^4\Leftrightarrow2x-1=3\Leftrightarrow2x=4\Leftrightarrow x=2\\\left(2x-1\right)^4=\left(-3\right)^4\Leftrightarrow2x-1=-3\Leftrightarrow2x=-2\Leftrightarrow x=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-1\end{cases}}\)

Nếu bài dễ thì cố gắng tự làm bạn nhé.

Bài 1:

a) \(2x+3=5\)

\(\Leftrightarrow2x=5-3=2\)

\(\Leftrightarrow x=2:2=1\)

Vậy: x=1

b) \(\left(2x-3\right)^2=9\)\(=3^2=\left(-3\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\left(3+3\right):2=3\\x=\left(-3+3\right):2=0\end{matrix}\right.\)

Vậy: \(x\in\left\{3;0\right\}\)

c) \(3x+4=2x-7\)

\(\Leftrightarrow2x-3x=7+4\)

\(\Leftrightarrow-1x=11\)

\(\Leftrightarrow x=-11\)

Vậy: x=-11

d) \(\left(4x-1\right)^3=27\)\(=3^3\)

\(\Rightarrow4x-1=3\)

\(\Leftrightarrow4x=3+1=4\)

\(\Leftrightarrow x=4:4=1\)

Vậy: x=1

e) \(\left(x-7\right).2=3.\left(2x+4\right)\)

\(\Leftrightarrow2x-14=6x+12\)

\(\Leftrightarrow2x-6x=12+14\)

\(\Leftrightarrow-4x=26\)

\(\Leftrightarrow x=\frac{26}{-4}=\frac{13}{-2}\)

Vậy: \(x=\frac{13}{-2}\)

c)(2x-3)^2 = 25

   (2x-3)^2 = 5^2 

=> 2x-3 = 5

    2x = 8

  x= 4

a) ( x-2)³ = 27

(x-2)^3 = 3^3

x-2 = 3

x= 5

b) 2^x + 2^x+3= 144

2^x + 2^x * 8 = 144

2^x (1+8) =144

2^x = 144:9

2^x = 16

2^x = 2^4

x=4

c) ( 2-3)²= 25

Câu c sao ko có x.

d) ( 2x-1)¹⁰= ( 2x-1) ¹⁰⁰

(ko bt)

a. (x-2)³=27

<=> (x-2)³=3³

=> x-2=3 =>x=5

c.(2x-3)²=25

<=> (2x-3)²=5²

=>2x-3=5 => 2x=8 =>x=4

a) ( x-2)³ = 27

(x-2)3 = 3³

x-2 = 3

x = 5

b) 2^x + 2^x+3= 144

2^x ( 1 + 2³ ) = 144

2^x . 9 = 144

2^x = 16

2^x = 2⁴

x = 4

c) ( 2x-3)²= 25

(2x-3)² = 5²

2x-3 = 5

2x = 8

x = 4

d) ( 2x-1)¹⁰= ( 2x-1) ¹⁰⁰

Dễ thấy 2x - 1 = 0 vì 0¹⁰ = 0¹⁰⁰

Vậy x = 0,5

Nếu 2x - 1 \(\ne\)0 

( 2x - 1 )¹⁰ : ( 2x - 1 )¹⁰ = ( 2x - 1 )¹⁰⁰ : ( 2x - 1 )¹⁰

( 2x - 1 )⁹⁰ = 1

Vậy 2x - 1 = 1 hoặc - 1.

Vậy x = 1 ; 0 ; 0,5.