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\(9+9^2+9^3+...+9^{100}=\left(9+9^2\right)+\left(9^3+9^4\right)+...+\left(9^{99}+9^{100}\right)\)
\(=100+9^3.100+...+9^{99}.100\)
\(=100.\left(1+9^3+9^5+...+9^{99}\right)\) chia hết cho 100.
Do đó cũng chia hết cho 10.
9+92+93+...+9100
=9.(1+9)+93(1+9)+...+999(1+9)
=10.(9+93+95+...+999)
->9+92+93+...+9100 chia hết cho 10
S100=5+5.9+5.92+5.93+....+5.999
=5(1+9+92+93+....+999)
=>1/5S100=1+9+92+93+...+999
=>9/5S100=9+92+93+...+9100
=>9/5S100-1/5S100=8/5S100=(9+92+93+...+9100)-(1+9+92+93+....+999)
=9100-1
=>S100=(9100-1):8/5
S100=(9100-1).5/8
=\(\frac{5\left(9^{100}-1\right)}{8}=\frac{5.9^{100}-5}{8}\)
\(\left(5.9^{100}-9^{100}\right):9^{99}=4.9^{100}:9^{99}=4\)
=4.9100:9
=4.(9100:999)
=4.9
=36
\(\left(5.9^{100}-9^{100}\right):9^{99}\)
\(=9^{100}\left(5-1\right):9^{99}\)
\(=9^{100}:9^{99}.4\)
\(=9.4\)
\(=36\)
Học tốt
(5×9^100-9^100):9^99
(5-1)×9^100:9^99
4×9^100:9^99
4×9
36
\(\left(5\cdot9^{100}-9^{100}\right):9^{99}\)
\(=\left(5\cdot9^{100}-9^{100}\cdot1\right):9^{99}\)
\(=\left[9^{100}\cdot\left(5-1\right)\right]:9^{99}\)
\(=\left(9^{100}\cdot4\right):9^{99}\)
\(=\left(9^{100-99}\right)\cdot4\)
\(=9^1\cdot4=9\cdot4=36\)