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1) \(\left(5x-4\right)^2-49x^2\)
\(=\left(5x-4\right)^2-\left(7x\right)^2\)
\(=\left(5x-4+7x\right)\left(5x-4-7x\right)\)( hằng đẳng thức số 3)
\(=\left(-2x-4\right)\left(12x-4\right)\)
2)\(\left(3x+1\right)^2-4\left(x-2\right)^2\)
\(=\left(3x+1\right)^2-\left(2\left(x-2\right)\right)^2\)
\(=\left(3x+1\right)^2-\left(2x-2\right)^2\)
\(=\left(3x+1-2x+4\right)\left(3x+1+2x-4\right)\)
\(=\left(x+5\right)\left(5x-3\right)\)
3) \(9\left(2x+3\right)^2-4\left(x+1\right)^2\)
\(=\left(3\left(2x+3\right)\right)^2-\left(2\left(x+1\right)\right)^2\)
\(=\left(6x+9\right)^2-\left(2x+2\right)^2\)
\(=\left(6x+9-2x-2\right)\left(6x+9+2x+2\right)\)
\(=\left(4x+7\right)\left(8x+11\right)\)
\(x^8+3x^4+4\)
\(=\left(x^8-x^6+2x^4\right)+\left(x^6-x^4+2x^2\right)+\left(2x^4-2x^2+4\right)\)
\(=x^4\left(x^4-x^2+2\right)+x^2\left(x^4-x^2+2\right)+2\left(x^4-x^2+2\right)\)
\(=\left(x^4+x^2+2\right)\left(x^4-x^2+2\right)\)
\(4x^4+4x^3+5x^2+2x+1\)
\(=\left(4x^4+2x^3+2x^2\right)+\left(2x^3+x^2+x\right)+\left(2x^2+x+1\right)\)
\(=2x^2\left(2x^2+x+1\right)+x\left(2x^2+x+1\right)+\left(2x^2+x+1\right)\)
\(=\left(2x^2+x+1\right)^2\)
a/ x4 +5x3 +10x-4
=(x4- 4)+(5x3 + 10x)
=(x2+2) (x2-2) + 5x(x2 +2 )
=(x2+2)(x2 -2 +5x)
b/x5 - x4 +x3 -x2 +x-1
=x4(x-1)+x3(x-1)+(x-1)
=(x-1)(x4+x3+1)
a) 8x3 + 4x2 - y3 - y2 = (8x3 - y3) + (4x2 - y2)

b) x2 + 5x - 6
= x2 + 6x - x - 6
= x(x + 6) - (x + 6)
= (x + 6)(x - 1)
a. 8x3+4x2-y3-y2
= (2x)3+(2x)2-y3-y2
=(2x)3-y3+(2x)2-y2
=(2x-y).(2x2+2xy+y2)+(2x-y)(2x+y)
=(2x-y)(2x2+2xy+y2+2x+y)
= x^4 + x^3 + 4x^3 + 4x^2 - 11x^2 - 11x -30x - 3
= x^3 ( x + 1) + 4x^2 ( x + 1)- 11x( x + 1) - 30 ( x+ 1)
= ( x + 1)(x^3 + 4x^2 - 11x - 30)
= ( x + 1) [ x^3 - 3x^2 + 7x^2 - 21x + 10x - 30]
= ( x + 1) [ x^2 ( x - 3) + 7x(x - 3) + 10 ( x- 3) ]
= ( x + 1 ) (x - 3 )(x^2 + 7x + 10)
= ( x + 1)(x - 3) [ x^2 + 2x + 5x + 10)
= ( x+ 1)(x-3) [ x(x+2) + 5(x+2) ]
=(x + 1)(x-3)(x+2)(x+5)
a) x2 + xy - 5x - 5y
=x(x+y)-5(x+y)
=(x-5)(x+y)
b) x2 - y2 - 4x + 4
=(x2-4x+4)-y2
=(x-2)2-y2
=(x-2-y)(x-2+y)
a) x2 + xy - 5x - 5y
= x ( x + y ) - 5 ( x + y )
= ( x + y ) ( x - 5 )
b) x2 - y2 - 4x + 4
= ( x2 - 4x + 4 ) - y2
= ( x - 2 )2 - y2
= ( x - 2 + y ) ( x - 2 - y )
\(\left(5x-4\right)^2-49x^2\)
\(=\left(5x-4\right)^2-\left(7x\right)^2\)
\(=\left(5x-4-7\right)\left(5x-4+7\right)\)
\(=\left(5x-11\right)\left(5x+3\right)\)
(5x-4)2-(7x)2
= (5x-4-7x)(5x-4+7x)
= (-2x-4)(12x-4)
= -8(x+2)(3x-1)
(5x-4)2-49x2
=(5x-4)2-(7x)2
=(5x-4-7x)(5x-4+7x)
=(-2x-4)(12x-4)
Chúc bn học giỏi nhoa!!!
Kb vs mik nhé!!!
cám ơn các bạn nhiều lắm
xin lỗi! mình có chút nhằm lẫn, nên đã đánh giá nhằm! dù sao thì các bạn cũng đã giúp mình, cám ơn
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