no bạn ơi

a: \(160-\left(2^3\cdot5^2-6\cdot25\right)\)

\(=160-\left(8\cdot25-150\right)\)

=160-(200-150)

=160-50

=110

\(=2\cdot5\cdot11\)

b: \(4\cdot5^2-32:2^4=4\cdot25-32:16=100-2=98=2\cdot7^2\)

c: \(5871:\left\lbrack928-\left(247-82\cdot5\right)\right\rbrack\)

\(=5871:\left\lbrack928-\left(247-410\right)\right\rbrack\)

=5871:[928-247+410]

=5871:1091

d: \(777:7+1331:11^3=111+1=112=2^4\cdot7\)

e: \(6^2:4\cdot3+2\cdot5^2=36:4\cdot3+2\cdot25\)

=27+50

=77

\(=7\cdot11\)

g: \(5\cdot4^2-18:3^2=5\cdot16-18:9=80-2=78=2\cdot3\cdot13\)

h: \(80-\left(4\cdot5^2-3\cdot2^3\right)=80-\left(4\cdot25-3\cdot8\right)\)

=80-(100-24)

=80-76

=4

=2^2

i: \(23\cdot75+25\cdot23+180\)

\(=23\left(75+25\right)+180\)

=2300+180

=2480

\(=2^4\cdot5\cdot31\)

k: \(2^4\cdot5-\left\lbrack131-\left(13-4\right)^2\right\rbrack\)

\(=16\cdot5-\left\lbrack131-81\right\rbrack\)

=80-50

=30

=2*3*5

m: 100:{250:[450-\(\left(4\cdot5^3-2^2\cdot25\right)\) ]}

=100:{250:[450-\(\left(4\cdot125-4\cdot25\right)\) ]}

=100:{250:[450-500+100]}

=100:{250:50}

=100:5

=20

=2^2*5

\(5871:\left[928-\left(247-82.5\right)\right]\\ =5871:\left[928-\left(247-410\right)\right]\\ =5871:\left[928-\left(-163\right)\right]\\ =5871:1091\\ =\dfrac{5871}{1091}\)

5871/1091

\(=\dfrac{5871}{928-\left(247-410\right)}=\dfrac{5871}{928-247+410}\)

\(=\dfrac{5871}{1091}\)

\(5871:\left[928-\left(247-82\cdot5\right)\right]\)

\(=5871:\left[928-\left(247-410\right)\right]\)

\(=5871:\left(928+163\right)\)

\(=5871:1091\)

\(=\dfrac{5871}{1091}\)

a, \(\left[2^3.\left(2+3\right)^3-3^2.111-1000^0\right]:15^0+1^3\)

\(=\left[8.5^3-9.111-1\right]:1+1\)

\(=\left[1000-999-1\right]:1+1=1\)

b, \(5871:\left\{928-\left[\left(-82\right)+247\right].5\right\}\)

\(=5871:\left[928-165.5\right]=5871:\left(928-825\right)\)

\(=5871:103=57\)

c, \(2^7:2^3+2^3.2^0+3^2.3^0.2-1^{20}\)

\(=2^4+2^3+9.2-1\)

\(=16+8+18-1=41\)

d, \(36.27+36.73-249\)

\(=36.\left(27+73\right)-249=36.100-249\)

\(=3600-249=3351\)

Chúc bạn học tốt!!!

mơn bn

\(=5871:\left[928-\left(247-410\right)\right]\)

\(=5871:\left(928+163\right)\)

\(=5871:1091\)

\(=\frac{5871}{1091}\)

tíc mình nha

247-410 sao chia được

5871:{928-[(-82)+247].5}

=5871:{928-165.5}

=5871:{928-825}

=5871:103

=57

 5871:{928-[(-82)+247)].5}

=5871:{928-165}.5

=5871:763.5

=5871:3816

=???????

\(=5871:\left[928-165\cdot5\right]\\ =5871:\left[928-825\right]=5871:103=57\)

\(=5871:\left[928-165.5\right]=5871:\left[928-825\right]=5871:103=57\)