\(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^3\cdot3\right)^6}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)

\(=\frac{2^{12}\cdot3^5-2^{12}\cdot3^4}{2^{18}\cdot3^6}-\frac{5^{10}\cdot7_{}^3-5^{10}\cdot7^4}{5^9\cdot7^3+5^9\cdot7^3\cdot2^3}\)

\(=\frac{2^{12}\cdot3^4\left(3-1\right)}{2^{18}\cdot3^6}+\frac{5^{10}\cdot7^3\left(7-1\right)}{5^9\cdot7^3\left(2^3+1\right)}\)

\(=\frac{2}{2^6\cdot3^2}+\frac{5\cdot6}{9}=\frac{1}{2^5\cdot9}+\frac{30}{9}=\frac{1}{32\cdot9}+\frac{960}{32\cdot9}=\frac{961}{288}\)

1)\(\left(-8\right)^2=64\)

2)\(\left(-1,25\right)^2=1,56\)

3) \(3^5=243\)

4) \(2^5:2^3\Leftrightarrow2^{5-3}=2^2\)

5) \(\left(-4\right)^2\times\left(-4\right)=\left(-4\right)^{2+1}=\left(-4\right)^3\)

6) \(\left(\frac{2}{3}\right)^3\times\left(\frac{2}{3}\right)^2=\left(\frac{2}{3}\right)^{3+2}=\left(\frac{2}{3}\right)^5\)

6,1. = 64

2 . = 1,56

3 . =243

4 , = 2² = 4

5  , (-4³) = -12

6, = 2/3 ⁵ = 22 / 213

\(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^3\cdot3\right)^6+8^4\cdot3^5}=\frac{2}{579}\)

\(=\frac{2^{12}\cdot3^5-2^{12}\cdot3^4}{2^{18}\cdot3^6+2^{12}\cdot3^5}=\frac{2^{12}\cdot3^4\left(3-1\right)}{2^{12}\cdot3^5\left(2^6\cdot3+1\right)}=\frac{2^{12}\cdot3^4\cdot2}{2^{12}\cdot3^5\cdot193}=\frac{2}{3\cdot193}=\frac{2}{579}\)

-0,26

p/s: bấm máy tính có thể sai chỗ nào đó nên sai không chịu trách nhiệm đâu nhé @@

=\(-\frac{13}{50}\)=-0,26