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16 tháng 6 2023

|5.6 - \(x\)| = 4.6

|30 - \(x\)| = 24

\(x< 30\) ⇒ 30 - \(x\) = 24 ⇒ \(x\) =  30 - 24  = -6

\(x>30\) ⇒ -(30 - \(x\)) = 24 ⇒ -30 + \(x\) = 24   ⇒ \(x\) = 24 + 30 = 54

Vậy \(x\) \(\in\) {  -6; 54}

`@` `\text {Ans}`

`\downarrow`

\(\left|5\cdot6-x\right|=4\cdot6\)

`\Rightarrow`\(\left|5\cdot6-x\right|=24\)

`\Rightarrow`\(\left[{}\begin{matrix}5\cdot6-x=24\\5\cdot6-x=-24\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}30-x=24\\30-x=-24\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=30-24\\x=30-\left(-24\right)\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=6\\x=54\end{matrix}\right.\)

Vậy, `x={6; 54}.`

\(30-24\) phải là \(=6\) mới đúng chứ ạ?

\(M=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^5.2^7.3^7+2^7.2^3.3^{10}}\)

\(=\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{10}.3^7\left(2^2+3^3\right)}\)

\(=\frac{2}{3}\)

\(M=\frac{2.\left(2^3\right)^4.\left(3^3\right)^2+2^2.\left(2.3\right)^9}{2^5.\left(2.3\right)^7+2^7.2^3.\left(3^2\right)^5}\)

\(M=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^5.2^7.3^7+2^7.2^3.3^{10}}\)

\(M=\frac{2^{13}.3^6+2^{11}.3^9}{2^{12}.3^7+2^{10}.3^{10}}\)

\(M=\frac{2^{11}.3^6\left(2^2.1+1.3^3\right)}{2^{10}.3^7\left(2^2.1+1.3^3\right)}\)

\(M=\frac{2.31}{3.31}\)

\(M=\frac{2}{3}\)

Study well 

24 tháng 10 2019

\(6^x+4\cdot6^x=180\)

\(6^x\cdot\left(1+4\right)=36\cdot5\)

\(6^x\cdot5=36\cdot5\)

\(6^x=36\)

\(6^x=6^2\)

\(x=2\)

6 tháng 8 2017

\(-4.6-1.53-5.4x=8.47\)

\(\Leftrightarrow-24-53-20x=376\)

\(\Leftrightarrow-77-20x=376\)

\(\Leftrightarrow20x=-77-376=-453\)

\(\Leftrightarrow x=\dfrac{-453}{20}\)

7 tháng 8 2016

\(\frac{1}{3.4}+\frac{1}{3.4}+...+\frac{1}{x\left(x+1\right)}=\frac{1}{3}-\frac{1}{x+1}\)

7 tháng 8 2016

\(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{x\left(x+1\right)}\)

\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+.....+\frac{1}{x}-\frac{1}{x+1}\)

\(=\frac{1}{3}-\frac{1}{x+1}\)

7 tháng 8 2016

1/3.4+1/4.5+1/5.6+1/6.7+....+1/x(x+1)=3/10

<=> \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{\left(x+1\right)x}=\frac{1}{3}-\frac{1}{x+1}=\frac{3}{10}\)

<=> \(\frac{1}{x+1}=\frac{1}{3}-\frac{3}{10}=\frac{1}{30}\)=> x+1=30=>x=29

7 tháng 8 2016

\(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+...+\frac{1}{x\left(x+1\right)}=\frac{3}{10}\)

\(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{3}{10}\)

\(\frac{1}{3}-\frac{1}{x+1}=\frac{3}{10}\)

\(\frac{1}{x+1}=\frac{1}{3}-\frac{3}{10}\)

\(\frac{1}{x+1}=\frac{1}{30}\)

\(\Rightarrow x+1=30\)

\(x=30-1=29\)

 

1 tháng 10 2025

\(\frac{4^5.4}{3^5.3}.\frac{6^5.6}{2^5.2}\)

= \(\frac{4^6}{3^6}.\frac{6^6}{2^6}\)

= \(\left(\frac{4.6}{3.2}\right)^6\)

= \(4^6\)

=> \(4^6\) = \(8^{x}\)

\(2^{12}\) = \(2^{3x}\)

12= 3.x

x= 12:3

x= 4