KQ =7

=480:[75+(49-8.3):5]+1

=480:[75+(49-24):5]+1

=480:[75+25:5]+1

=480:[75+5]+1

=480:80+1

=6+1

=7

a: =545x80-80x445

=8000

\(480:\left(75+7^2-8.3:5\right)+2021^0\)

\(=480:\left(75+49-\dfrac{24}{5}\right)+1\)

\(=480:\left(124-\dfrac{24}{5}\right)+1\)

\(=480:\dfrac{596}{5}+1\)

\(=\dfrac{600}{149}+1=\dfrac{749}{149}\)

=480:[75+(49-8.3):5]+1

=480:[75+(49-24):5]+1

=480:[75+25:5]+1

=480:[75+5]+1

=480:80+1

=6+1

=7

a: Sửa đề: \(2^3\cdot2^2-\left(5^6:5^4-2010^0-24\right)^3-14\)

\(=2^5-\left(5^2-1-24\right)^3-14\)

\(=32-\left(25-1-24\right)^3-14\)

=32-14

=18

b: \(\left(-480\right):\left\lbrack75+\left(7^2-8\cdot3\right):5\right\rbrack+2021^2\)

\(=\left(-480\right):\left\lbrack75+\frac{_{}\left(49-24\right)}{5}\right\rbrack+2021^2\)

\(=-480:\left(75+\frac{25}{5}\right)+2021^2\)

\(=-480:80+2021^2=2021^2-6=4084435\)

Phần trong ngoặc.........phân tích cơ số ra thừa số nguyên tố:

\(125^3\cdot7^5-175^5:5=\left(5^3\right)^3\cdot7^5-\left(5^2\cdot7\right)^5:5=5^9\cdot7^5-5^9\cdot7^5=0\)

1) ( 125³ . 7⁵ - 175⁵ : 5 ) : 2016²⁰¹⁷ = 0: 2016^2017 = 0 

2)

a)5* 3^x = 8*3^9 + 8* 27^3 

3^x = 59049

x=10

\(\frac{7.1^2-7.9}{98}=\frac{7\left(1-9\right)}{98}=\frac{-8}{14}=\frac{-4}{7}\)

\(\frac{3^2}{8.11+8.3}=\frac{9}{8\left(11+3\right)}=\frac{9}{8.14}=\frac{9}{112}\)

7574675