Bài 1:

\(\frac{3}{5}+\frac{4}{15}=\frac{9}{15}+\frac{4}{15}=\frac{13}{15}\)

\(\frac{5}{6}:\frac{-7}{12}=\frac{5}{6}.\frac{-12}{7}=\frac{-60}{42}=\frac{-10}{7}\)

\(\frac{-21}{24}:\frac{-14}{8}=\frac{-21}{24}.\frac{-8}{14}=\frac{168}{336}=\frac{1}{2}\)

\(\frac{4}{5}:\frac{-8}{15}=\frac{4}{5}.\frac{-15}{8}=\frac{-60}{40}=\frac{-3}{2}\)

\(\frac{5}{12}-\frac{-7}{6}=\frac{5}{12}+\frac{7}{6}=\frac{5}{12}+\frac{14}{12}=\frac{19}{12}\)

\(\frac{-15}{16}.\frac{8}{25}=\frac{-120}{400}=\frac{-3}{10}\)

Bài 2 :

\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)

\(=\frac{34}{5}-\left(\frac{5}{3}+\frac{19}{5}\right)\)

\(=\frac{34}{5}-\frac{5}{3}-\frac{19}{5}\)

\(=\left(\frac{34}{5}-\frac{19}{5}\right)-\frac{5}{3}\)

\(=3-\frac{5}{3}\)

\(=\frac{4}{3}\)

\(6\frac{5}{7}-\left(1\frac{2}{3}+2\frac{5}{7}\right)\)

\(=\frac{47}{7}-\left(\frac{5}{3}+\frac{19}{7}\right)\)

\(=\frac{47}{7}-\frac{5}{3}-\frac{19}{7}\)

\(=\left(\frac{47}{7}-\frac{19}{7}\right)-\frac{5}{3}\)

\(=4-\frac{5}{3}\)

\(=\frac{7}{3}\)

\(\frac{4}{19}.\frac{-3}{7}+\frac{-3}{7}.\frac{15}{19}+\frac{5}{7}\)

\(=\left(\frac{4}{19}+\frac{15}{19}\right).\frac{-3}{7}+\frac{5}{7}\)

\(=1.\frac{-3}{7}+\frac{5}{7}\)

\(=\frac{-3}{7}+\frac{5}{7}\)

\(=\frac{2}{7}\)

\(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)

\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)

\(=\frac{5}{9}.1\)

\(=\frac{5}{9}\)

35 . 18 - 5 . 7 . 28

= 35.18-5.7.28

= 35 . 18 - 35 . 28

= 35 . ( 18 - 28 )

= 35 . ( - 10 )

= -350

D. 24.(16-5)-16.(24-5)

= 24 . 11 - 16 . 19

= 264 - 304

= -30

?1=16-2=14

?2=21-3=18 hoặc =20-2=18

?3=15-2=13

a)1+(-2)+3+(-4)+...+19+(-20)

=[1+(-2)]+[3+(-4)]+...+[19+(-20)]

=(-1)+(-1)+...+(-1)=(-1)x10=-10

b)1-2+3-4+....+99-100

=(1-2)+(3-4)+...+(99-100)

=(-1)+(-1)+...+(-1)

=(-1)x50=-50

18a:

(a + b) - (-a + b - c) + (c - a - b) = a - b + 2c

= a + b + a - b + c + c - a - b

= (a + a - a) + (b - b - b) + (c + c)

= (2a - a) + (0 - b) + 2c

= a - b + 2c

18b:

a(b - c) - a(b + d)

= ab - ac - ab -ad

= (ab - ab) - (ac + ad)

= 0 - a(c - d)

= -a(c - d)