Giải PT: 23x+1−32−x=3−2x" role="presentation" style="border:0px; color:rgb(40, 40, 40); direction:ltr; display:inline-table; float:none; font-family:helvetica,arial,sans-serif; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-wrap:normal" class="MathJax_CHTML mjx-chtml">2√3x+1−3√2−x=3−2x

giải phương trình x+1+2x+3=x+5x+3" role="presentation" style="border:0px; color:rgb(40, 40, 40); direction:ltr; display:inline-block; float:none; font-family:helvetica,arial,sans-serif; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-wrap:normal" class="MathJax_CHTML mjx-chtml">x+1+2x+3=x+5x+3

Chứng minh aba5+b5+ab+bcb5+c5+bc+cac5+a5+ac≤1" role="presentation" style="border:0px; direction:ltr; display:inline-table; float:none; font-size:30.42px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal" class="MathJax_CHTML mjx-chtml">aba5+b5+ab+bcb5+c5+bc+cac5+a5+ac≤1

Cho a+b+c=1 và a3+b3+c3=1" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:14.04px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">a3+b3+c3=1${\displaystyle a^3+b^3+c^3=1}$

Chứng minh a2005+b2005+c2005=1" role="presentation" style="border:0px; direction:ltr; display:inline-table; float:none; font-size:14.04px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">a2005+b2005+c2005=1

Tìm x biết : ${\left(2x+5\right)}^2+\left(4x+10\right)\left(3-x\right)+x^2-6x+9=0$

Tìm m sao cho với mọi x, ta có: 

x3−3x2+x+m" role="presentation" style="border:0px; color:rgb(0, 0, 0); direction:ltr; display:inline-block; float:none; font-family:arial,tahoma,helvetica,sans-serif; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap" class="MathJax_CHTML mjx-chtml">2x3−3x2+x+m$2x^3-3x^2+x+m$=(x+2)(2x2−7x+15)." role="presentation" style="border:0px; color:rgb(0, 0, 0); direction:ltr; display:inline-block; float:none; font-family:arial,tahoma,helvetica,sans-serif; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap" class="MathJax_CHTML mjx-chtml">=(x+2)(2x2−7x+15)

 

a, (x-1)³ - x(x-1)² = 5(2-x) - 11(x+2)

b, (x-2)³ + (3x-1)(3x+1) = (x+1)³

c, $\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{5}$

d, $\frac{2\left(x-3\right)}{7}+\frac{x-5}{3}=\frac{13x+4}{21}$

e, $\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}$

_Giúp mình với!_

a, (x-1)³ - x(x-1)² = 5(2-x) - 11(x+2)

b, (x-2)³ + (3x-1)(3x+1) = (x+1)³

c, $\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{5}$

d, $\frac{2\left(x-3\right)}{7}+\frac{x-5}{3}=\frac{13x+4}{21}$

e, $\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}$

16" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-table; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal" class="MathJax_CHTML mjx-chtml">1 1−x+11+x+11+x2+11+x4+11+x8+11+x16

- x4−(x+1)x3+(x+1)x2−(x+1)x+4(x>=0)" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-table; float:none; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">x4−(x+1)x3+(x+1)x2−(x+1)x+4(x>=0)

- $x^2-3x^2-4x+12$

$x^4-4-4x^2-x^2$