\(\left(18,6.\frac{16x-3}{2}+\frac{139,5-238,25x}{5}\right):\left(1+8+15+...+281+288\right)=\frac{1}{3}\)

\(\Rightarrow\left(\frac{297,6x-55,8}{2}+\frac{139,5-238,25x}{5}\right):\left(\frac{\left(288+1\right).\left[\left(288-1\right):\left(8-1\right)+1\right]}{2}\right)=\frac{1}{3}\)

\(\Rightarrow\left(\frac{1488x-279}{10}+\frac{279-476,5x}{10}\right):6069=\frac{1}{3}\)

\(\Rightarrow\frac{1488x-279+279-476,5x}{10}=2023\)

\(\Rightarrow1488x-476,5x=20230\)

\(\Rightarrow1011,5x=20230\)

\(\Rightarrow x=20\)

             Bài làm :

Ta có :

\(\left(18,6.\frac{16x-3}{2}+\frac{139,5-238,25x}{5}\right)\div\left(1+8+15+...+281+288\right)=\frac{1}{3}\)

\(\Leftrightarrow\left(\frac{297,6x-55,8}{2}+\frac{139,5-238,25x}{5}\right)\div\left(\frac{\left(288+1\right).\left[\left(288-1\right):\left(8-1\right)+1\right]}{2}\right)=\frac{1}{3}\)

\(\Leftrightarrow\left(\frac{1488x-279}{10}+\frac{279-476,5x}{10}\right)\div6069=\frac{1}{3}\)

\(\Leftrightarrow\frac{1488x-279+279-476,5x}{10}=2023\)

\(\Leftrightarrow1488x-476,5x=20230\)

\(\Leftrightarrow1011,5x=20230\)

\(\Leftrightarrow x=20\)

Vậy x=20

Xét \(22.\left(-6\right)=\left(-132\right)\) :

\(\Rightarrow\left\{{}\begin{matrix}\left(+22\right).\left(+6\right)=\left(+132\right)\\\left(+6\right).\left(-22\right)=\left(-132\right)\\\left(-22\right).\left(+6\right)=\left(-132\right)\end{matrix}\right.\)

(+22).(+6) = 132

(-22).(-6) = 132

(-22).(+6) = -132

(+6).(-22) = -132

22³³ < 33²²

Học tốt!!!

\(22^{33}>33^{22}\)

\(a,b,c\in\left\{1;5;8\right\}\)và \(n⋮5\) \(\Rightarrow\) \(c=5\)

Vậy \(a,b\in\left\{1;8\right\}\)

\(n\) phải nhỏ hơn năm nay (2017) vì ô tô đã ra đời trước đây.

\(\Rightarrow n=\overline{1885}\) với \(a=1\) và \(b=8\)

Vậy \(a=1\) , \(b=8\) và \(c=5\)

So sánh 22⁵⁵ và 55²²

22⁵⁵=(2.11)^5.11=(2⁵.11⁵)¹¹=(32.11⁵)¹¹

55²²=(5.11)^2.11=(5².11²)¹¹=(25.11²)¹¹

Vì (32.11⁵)¹¹ > (25.11²)¹¹

Nên 22⁵⁵ > 55²²

nếu đúng thì tick cho mình nha các bạn

(\(\frac{15}{22}\)-\(\frac{7}{13}\)) x \(\frac{13}{7}\)- \(\frac{15}{22}\) x(\(\frac{6}{7}\)- \(\frac{22}{15}\))

=(\(\frac{15}{22}\)x \(\frac{13}{7}\)- 1) - \(\frac{15}{22}\)x\(\frac{6}{7}\)-1

=\(\frac{15}{22}\)x \(\frac{13}{7}\)-\(\frac{15}{22}\)x\(\frac{6}{7}\)(vì -1+1=0)

=\(\frac{15}{22}\)x(\(\frac{13}{7}\)-\(\frac{6}{7}\))

=\(\frac{15}{22}\)

làm hơi tắt nha

\(\left(\frac{15}{22}-\frac{7}{13}\right).\frac{13}{7}-\frac{15}{22}.\left(\frac{6}{7}-\frac{22}{15}\right)\)

\(=\frac{15}{22}.\frac{13}{7}-\frac{7}{13}.\frac{13}{7}-\frac{15}{22}.\frac{6}{7}+\frac{15}{22}.\frac{22}{15}\)

\(=\frac{15}{22}.\left(\frac{13}{7}-\frac{6}{7}\right)-1+1\)

\(=\frac{15}{22}.1-1+1\)

\(=\frac{15}{22}-\left(1-1\right)\)

\(=\frac{15}{22}-0\)

\(=\frac{15}{22}\)

a) 135 + 360 + 65 + 40 = (135 + 65) + (360 + 40) = 200 + 400 = 600.

b) 463 + 318 + 137 + 22 = (463 + 137) + (318 + 22) = 600 + 340 =940.

c) Nhận thấy 20 + 30 = 50 = 21 + 29 = 22+ 28 = 23 + 27 = 24 + 26.

Do đó 20 + 21 + 22 + ...+ 29 + 30

= (20+ 30) + (21 + 29) + (22 + 28) + (23 + 27) + (24 + 26) + 25

= 5 . 50 + 25 = 275.

BÀI LÀM:

a, 135 + 360 + 65 + 40 = ( 135 + 65 ) + ( 360 + 40 ) = 200 + 400 = 600

b, 463 + 318 + 137 + 22 = ( 463 + 137 ) + ( 318 + 22 ) = 600 + 340 = 940

c, 20 + 21 + 22 + ... + 29 + 30

= ( 20 + 30 ) + ( 21 + 29 ) + ( 22 + 28 ) + ( 23 + 27 ) + ( 24 + 26 ) + 25

= 50 . 5 + 25 = 275

\(\left(\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{1}{30}\right).\left(\dfrac{21}{22}+\dfrac{22}{23}+...+\dfrac{102}{103}\right)\)

\(=0.\left(\dfrac{21}{22}+\dfrac{22}{23}+...+\dfrac{102}{103}\right)\)

\(=0\)

vì \(\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{1}{30}\)=0 nên

(15−16−13015−16−130 ).(2122+2223+......+102103)=0

\(\dfrac{-5}{22}-1+\dfrac{3}{2}-\dfrac{6}{22}\)=\(\left(\dfrac{-5}{22}-\dfrac{6}{22}\right)+\left(-1+\dfrac{3}{2}\right)\)

=\(\dfrac{-11}{22}+\dfrac{1}{2}\)

=\(\dfrac{-11}{22}+\dfrac{11}{22}\)

=\(\dfrac{0}{22}\)=0

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