\(B=3+3^2+3^3+.....+3^{2006}\)

\(\Rightarrow3B=3^2+3^3+....+3^{2007}\)

\(\Rightarrow2B=3^{2007}-3\)

\(\Rightarrow B=\frac{3^{2007}-3}{2}\)

\(2B+3=3^x\)

\(\Rightarrow2.\frac{3^{2007}-3}{2}+3=3^x\)

\(\Rightarrow3^{2007}-3+3=3^x\Rightarrow3^{2007}=3^x\Rightarrow x=2007\)

Câu a:

(x - 5)^2 - 2x - 2^4 = 2x

(x - 5)(x - 5) - 2x - 16 - 2x = 0

x^2 - 5x - 5x + 25 - 2x - 16 - 2x = 0

x^2 - (5x + 5x +2x + 2x) + (25 - 16) = 0

x^2 - 14x + 9 = 0

(x^2 - 7x) - (7x - 49) - 40 = 0

x(x - 7) - 7(x - 7) - 40 = 0

(x - 7)(x - 7) - 40 = 0

(x - 7)^2 = 40

x - 7 = \(\sqrt{40}\) hoặc x - 7 = -\(\sqrt{40}\)

x - 7 = - \(\sqrt{40}\)

x = 7 - \(\sqrt{40}\)

x - 7 = \(\sqrt{40}\)

x = 7+ \(\sqrt{40}\)

Vậy x ∈ {7 - \(\sqrt{40}\) ; 7+ \(\sqrt{40}\))

Câu b:

3^(x -1) - 7^2 = 2^5 + 0^3

3^(x -1) - 49 = 32 + 0

3^(x - 1) - 49 = 32

3^(x -1) = 32 + 49

3^(x -1) = 81

3^(x-1) = 3^4

x - 1 = 4

x = 4 + 1

x = 5

Vậy x = 5

\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\Rightarrow\frac{6x}{11.18}=\frac{9y}{2.18}=\frac{18z}{5.18}\)

\(\Rightarrow\frac{-x}{-33}=\frac{y}{4}=\frac{z}{5}=\frac{-x+y+z}{-33+4+5}=\frac{-120}{-24}=5\)

\(\Rightarrow x=165;y=20;z=25\)

\(2.THPT\)

\(A=\frac{9}{1.2}+\frac{9}{2.3}+\frac{9}{3.4}+...+\frac{9}{98.99}+\frac{9}{99.100}\)

\(A=9\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\right)\)

\(A=9\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\right)\)

\(A=9\left(1-\frac{1}{100}\right)\)

\(A=9.\frac{99}{100}\)

\(A=\frac{891}{100}\)

\(B=\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{93.95}\)

\(B=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{93}-\frac{1}{95}\)

\(B=\frac{1}{5}-\frac{1}{95}\)

\(B=\frac{18}{95}\)

\(D=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(D=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(D=\frac{1}{2}-\frac{1}{28}\)

\(D=\frac{13}{28}\)

ai nhanh k 2 lan

khó quá bn ơi

2b,

Giải:A=72³.54²/(54.2)⁴=72³.54²/54⁴.2⁴=72³/54².2⁴=3⁵.2⁶/3⁵.2⁶=1.            B=3⁹.3.11+3⁹.3.5/3⁹.2⁴=3⁹.(33+15)/3⁹.2⁴=48/16=3.                                    C=2¹⁰.(13+65)/2².104=2⁸.78/104=2⁸.26.3/26.4=2⁸.3/4=2⁶.3=192.              a)->2^x=128:4=32.=>x=5(2⁵=32)                                                                    b)->2x+1=5(5³=125)=>x=2.                                                                          c)Ko có số nào ngoài 1 và 0 tồn tại dưới dạng(x-5)⁴=(x-5)⁶                       ->Nếu x-5=0=>x=5                                                                                       ->Nếu x-5=1=>x=6

0

( 2^3 x 3^2)^3 x ( 2 x 3^3 )^2    =    2^9 x 3^6 x 2^2 x 3^6     =    2^11 x 3^12    

( 2^2 x 3^3 )                           =     2^8 x 3^12                   =     2^8 x 3^12  

=      2^3    = 8   

bài a âu có z âu mà tìm bn ???

\(\frac{x}{a}?\)