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a, (476-324)-(124+524)
= 476-324-124-524
=476-(324+124+524)
= -496
b, -(127-2013)+(-1013-372)
=-127+2013+(-1013)-372
=(-127-372)+[2013+(-1013)]
=-499+100
=501
Bài 1 :
a, 2013 - 79 -1013 - 21
= (2013 -1013 ) + (-79 -21 )
=1000 - 100
=900
b, 135 - 591 -409 +437
= ( 135 + 437 ) +(-591 -409 )
= 572 -1000
= -428
c, -46 - 135 +35 +146
= 100 -100
= 0
a) 2013-79-1013-21
=(2013-1013)-(-79-21)
=1000-100
=900
b) 135-591-409+437
=(135+437)-(-591-409)
= 572-1000
= -428
c) -46-135+35+146
= (-46+146)+(-135+35)
=100+(-100)
=0
a: \(101^3=\left(100+1\right)^3\)
\(=100^3+3\cdot100^2\cdot1+3\cdot100\cdot1^2+1^3\)
=1000000+30000+300+1
=1030301
b: \(98^3+6\cdot98^2+12\cdot98+8\)
\(=98^3+3\cdot98^2\cdot2+3\cdot98\cdot2^2+2^3\)
\(=\left(98+2\right)^3=100^3=1000000\)
c: \(99^3=\left(100-1\right)^3\)
\(=100^3-3\cdot100^2\cdot1+3\cdot100\cdot1^2-1^3\)
=1000000-30000+300-1
=970299
d: \(13^3-9\cdot13^2+27\cdot13-27\)
\(=13^3-3\cdot13^2\cdot3+3\cdot13\cdot3^2-3^3\)
\(=\left(13-3\right)^3=10^3=1000\)
Ta có: \(B=\frac12+\frac13-\frac14+\frac15-\frac16+\cdots-\frac{1}{2022}+\frac{1}{2023}\)
=>\(B=\frac12+\frac13+\frac14+\frac15+\frac16+\cdots+\frac{1}{2022}+\frac{1}{2023}-2\left(\frac14+\frac16+\cdots+\frac{1}{2022}\right)\)
\(=\frac12+\frac13+\frac14+\frac15+\cdots+\frac{1}{2022}+\frac{1}{2023}-\frac12-\frac13-\cdots-\frac{1}{1011}\)
\(=\frac{1}{1012}+\frac{1}{1013}+\cdots+\frac{1}{2022}+\frac{1}{2023}\)
=C
=>B-C=0
a: =476-324-124-524
=-172-324
=-496
b:=-127+2013-1013-372
=1000-449=501