8^2+8^2

=64+64

=128

654+456

=1110

9/3-4/3=5/3

#vhn#

#k_mk_nha

8²+8²=128

654+456=1110

9/3-4/3=5/3

= 9

kb nha r mk chỉ cho

Bằng 0 nha bạn vì bất kì số nào nhân 0 hoặc chia 0 đều bằng 0 hết nha bạn!!!

Kb nha rúi mình chỉ cho ok!?

Bị rảnh ak

6 + 6 +6 + 6 + 6 + 6 + 6 + 6+ 6 + 6 + 6  = 6x11=66

9 x 9 + 6 x 8 =81+48=129

987 +321 -456 +963 =1815

câu hỏi hay......nhưng tui xin nhường cho các bn khác

Hãy tích đúng cho tui nha

THANKS

1

ko xác định

\(\left(x^2-1\right)\left(x^2+4x+3\right)=192\)

\(\Leftrightarrow\left(x-1\right)\left(x+1\right)\left(x+1\right)\left(x+3\right)=192\)

\(\Leftrightarrow\left(x^2+2x-3\right)\left(x^2+2x+1\right)=192\)

\(\text{Đặt }x^2+2x+1=a\left(a\ge0\right)\)

\(\Rightarrow a\left(a-4\right)=192\)

\(\Leftrightarrow\left(a+12\right)\left(a-16\right)=0\)

\(\Rightarrow a=16\)

\(\Rightarrow x^2+2x+1=16\)

\(\Leftrightarrow\left(x-3\right)\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)

•••••••••••••••••••••••••••••••••••

\(x^4+3x^3+4x^2+3x+1=0\)

\(\Leftrightarrow\left(x^4+2x^3+x^2\right)+\left(x^3+2x^2+x\right)+\left(x^2+2x+1\right)=0\)

\(\Leftrightarrow x^2\left(x+1\right)^2+x\left(x+1\right)^2+\left(x+1\right)^2=0\)

\(\Leftrightarrow\left(x+1\right)^2\left(x^2+x+1\right)=0\)

\(\Rightarrow x=-1\)

3) x⁴ + 3x³ + 4x² + 3x + 1 = 0

x⁴ + x³ + 2x³ + 2x² + 2x² + 2x + x + 1 = 0

x³( x + 1) + 2x²( x + 1) + 2x( x + 1) + x + 1 = 0

( x + 1)( x³ + 2x² + 2x + 1 ) = 0

( x + 1)[ ( x + 1)( x² - x + 1) + 2x( x + 1) ] = 0

( x + 1)( x + 1)( x² - x + 1 + 2x ) = 0

( x + 1)²( x² + x + 1) = 0

Ta thấy : x² + x + 1 = \(\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}>0\)

<=> x + 1 = 0

<+> x = -1

Vậy,...