\(\frac{1}{8}\div\frac{27}{-20}+\left(75\%-\frac{5}{16}\right)\div\frac{7}{2}\)

\(=\frac{1}{8}\times\frac{-20}{27}+\left(\frac{75}{100}-\frac{5}{16}\right)\times\frac{2}{7}\)

\(=\frac{-10}{108}+\left(\frac{12}{16}-\frac{5}{16}\right)\times\frac{2}{7}\)

\(=\frac{-5}{54}+\frac{7}{16}\times\frac{2}{7}\)

\(=\frac{-5}{54}+\frac{2}{16}\)

\(=\frac{-5}{54}+\frac{1}{8}\)

\(=\frac{-20}{216}+\frac{27}{216}\)

\(=\frac{7}{216}\)

\(=\frac{8}{11}.\frac{14}{23}+\frac{8}{11}.\frac{9}{23}-\frac{8}{11}.1\)

\(=\frac{8}{11}.\left(\frac{14}{23}+\frac{9}{23}-1\right)\)

\(=\frac{8}{11}.0=0\)

Ai thấy tớ đúng k nha

Online Math là nhất

em yêu Online Math

a hâm ak ?? :)

Ta có: 4= 2²

          8=2³

          16=2⁴

           11=11

          20=5.4=5.2²

Lại có: \(2^2,2^3\inƯ\left(2^3\right)\)

           \(11\inƯ\left(11\right)\)

           \(5.2^2\inƯ\left(2^3.5^2\right)\)

Vậy \(4;8;11;20\inƯ\left(a\right)\)

Mới vào lớp 6 nên e  ko bt, sr nhìu !^^

a) \(\dfrac{2}{5}.\left(\dfrac{2}{3}-\dfrac{1}{4}\right)+\dfrac{1}{2}\\ =\dfrac{2}{5}.\left(\dfrac{8}{12}-\dfrac{3}{12}\right)+\dfrac{1}{2}\\ =\dfrac{2}{5}.\dfrac{5}{12}+\dfrac{1}{2}\\ =\dfrac{1}{6}+\dfrac{1}{2}\\ =\dfrac{1}{6}+\dfrac{3}{6}\\ =\dfrac{2}{3}\)

b) \(1,8:\dfrac{27}{-20}+\left(75\%-\dfrac{5}{16}\right):3\dfrac{1}{2}\\ =\dfrac{9}{5}:\dfrac{-27}{20}+\left(\dfrac{3}{4}-\dfrac{5}{16}\right):\dfrac{7}{2}\\ =\dfrac{9}{5}.\dfrac{-20}{27}+\left(\dfrac{12}{16}-\dfrac{5}{16}\right):\dfrac{7}{2}\\ =\dfrac{-4}{3}+\dfrac{7}{16}:\dfrac{7}{2}\\ =\dfrac{-4}{3}+\dfrac{7}{16}.\dfrac{2}{7}\\ =\dfrac{-4}{3}+\dfrac{1}{8}\\ =\dfrac{-32}{24}+\dfrac{3}{24}\\ =\dfrac{-29}{24}\)

a)

\(\frac{8}{11}.\frac{14}{23}+\frac{9}{23}:\frac{11}{8}-\frac{8}{11} \)

\(=\frac{8}{11}.\frac{14}{23}+\frac{9}{23}.\frac{8}{11}-\frac{8}{11}\)

\(=\frac{8}{23}.(\frac{14}{23}+\frac{9}{23}-1)\)

\(=\frac{8}{23}.0\)

=0

b)

\(1,8.\frac{-20}{27}\)+(75%\(-\frac{5}{16}):3\frac{1}{2}\)

=\(\frac{9}{5}.\frac{-20}{27}+(\frac{3}{4}-\frac{5}{16}):\frac{7}{2}\)

=\(\frac{-4}{3}+\frac{1}{8}\)

=\(\frac{-29}{24}\)

1. => 3x+6 = -6 hoặc 3x+6 = 6

=> x = -4 hoặc x=0

2. => (4-2x)^2 = 7+9 = 16

=> 4-2x=-4 hoặc 4-2x = 4

=> x=4 hoặc x=0

3. => 3x-5 = -4

=> x = 1/3

Tk mk nha

1) \(\left(3x+6\right)^2=36\)

\(\left(3x+6\right)^2=\orbr{\begin{cases}\left(-6\right)^2\\6^2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}3x+6=-6\\3x+6=6\end{cases}}\Rightarrow\orbr{\begin{cases}3x=-12\\3x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-4\\x=0\end{cases}}\)

những câu sau tương tự 

\(A=\left(\frac{21}{5}-\frac{3}{5}\right):\frac{16}{8}:\frac{9}{10}\)

\(A=\frac{18}{5}:\frac{16}{8}:\frac{9}{10}\)

\(A=\frac{18}{5}\times\frac{8}{16}\times\frac{10}{9}\)

\(A=\frac{9}{5}\times\frac{8}{8}\times\frac{10}{9}\)

\(A=\frac{72}{40}\times\frac{10}{9}\)

\(A=\frac{8}{4}\times\frac{1}{1}\)

\(A=\frac{8}{9}\)

\(B=\left(1\frac{1}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(2+\frac{14}{16}\right)\)

\(B=\left(\frac{21}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(\frac{32}{16}+\frac{14}{16}\right)\)

\(B=\left(\frac{105}{100}+\frac{36}{100}\right):\frac{84}{25}:\frac{46}{16}\)

\(B=\frac{141}{100}:\frac{84}{25}:\frac{46}{16}\)

\(B=\frac{141}{100}\times\frac{25}{84}\times\frac{16}{46}\)

\(B=\frac{141}{4}\times\frac{1}{84}\times\frac{16}{46}\)

\(B=\frac{141}{336}\times\frac{16}{46}\)

\(B=\frac{141}{21}\times\frac{1}{46}\)

\(B=\frac{141}{966}\)