a. \(0,5x-\frac{1}{3}x=\frac{1}{3}\)

 \(\left(0,5-\frac{1}{3}\right)x=\frac{1}{3}\)

                   \(\frac{1}{6}x=\frac{1}{3}\)

                         \(x=\frac{1}{3}:\frac{1}{6}\)

                        \(x=2\)

b. \(x:3\frac{1}{2}=-1,5\)

           \(x=-1,5\times3\frac{1}{2}\)

           \(x=-5,25\)

c. \(1,5x=\frac{11}{5}\)

          \(x=\frac{22}{15}\)

A. 0,5x - 1/3x = 1/3

    (0,5 - 1/3)x = 1/3

              1/6x = 1/3

                  x = 2

B. x : 3 1/2 = -1,5

              x = -1,5 x 3 1/2

              x = -5,25

C. 1,5x = 11/5

        x = 22/15

a, -5/6 -x = 7/12 + -1/3
⇔-10/12 - 12x/12 = 7/12 + -4/12
⇒-10 - 12x = 7 - 4
⇔-12x = 7 - 4 +10
⇔-12x = 13
⇔x = -13/12
b, x+13/-15 = 1/3
⇔-(x+13)/15 = 5/15
⇒ -x - 13 = 5
⇔-x = 5 +13
⇔-x = 18
⇔x = -18
c,-15/x-1 = -3/5
⇔-75/(x-1).5 = -3.(x-1)/5.(x-1)
⇒-75 = -3x + 3
⇔3x = 3 + 75
⇔3x = 78
⇔x = 26
d, (1/2).x + -2/5 = 1/5
⇔5x/10 + -4/10 = 1/10
⇒5x - 4 = 1
⇔5x = 1 + 4
⇔5x = 5
⇔x = 1
e, (-2/3).x + 1/5 = 1/10
⇔-20x/30 + 6/30 = 3/30
⇒-20x + 6 = 3
⇔-20x = 3 - 6
⇔-20x = -3
⇔x = 3/20
f, 4/5 - (1/2).x = 1/10
⇔8/10 - 5x/10 = 1/10
⇒8 - 5x = 1
⇔-5x = 1 - 8
⇔-5x = -7
⇔x=7/5

a)        \(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)

   <=>   \(\frac{2x}{3}-3=\frac{2}{5}.\left(-10\right)\)

   <=>   \(\frac{2x}{3}-3=-4\)

   <=>    \(\frac{2x}{3}=-4+3=-1\)

   <=>     \(2x=-1.3=-3\)

   <=> \(x=\frac{-3}{2}\)

Vậy \(x=\frac{-3}{2}\)

b) \(1,5x-2\frac{1}{3}x=1,5-\frac{2}{3}\)

\(x.\left(1,5-2\frac{1}{3}\right)=\frac{5}{6}\)

\(x.\left(\frac{-5}{6}\right)=\frac{5}{6}\)

\(x=\frac{5}{6}:\left(\frac{-5}{6}\right)=\frac{5}{6}.\left(\frac{-6}{5}\right)=-1\)

Vậy \(x=-1\)

Nếu đúng thì cho mình nhé, chúc bạn học tốt !

Câu a:

(1/5 - 3/4).x - 1,52 = - 0,48

(4/20 - 15/20)x = -0,48 + 1,52

- 11/20x = 1,04

x = 1,04 : (-11/20)

x = - 104/55

Vậy x = - 104/55

Câu b:

|x - 2| - 1,5x = 3/4 + 5/4x -25/7

|x -2| = 5/4x + 1,5x + 3/4

|x -2| = 1,25x + 1,5x + 0,75

|x -2| = 2,75x + 0,75

|x -2| ≥ 0 ∀ x

⇒ 2,75x + 0,75 ≥ 0

2,75x ≥ - 0,75

x ≥ - 0,75 : 2,75

x ≥ -3/11

Với x ≥ -3/11 ta có:

|x - 2| = 2,75x + 0,75

x - 2 = 2,75x + 0,75 hoặc x - 2 = - 2,75x - 0,75

Th1:

x - 2 = 2,75x + 0,75

2,75x - x = - 2 - 0,75

1,75x = - 2,75

x = -2,75 : 1,75

x = - 11/7 < -3/7 (tm)

Th2:

x - 2 = - 2,75x - 0,75

x + 2,75x = 2 - 0,75

3,75x = 1,25

x = 1,75 : 3,75

x = 1/3 (ktm)

Vậy x = -11/7

X : \(3\frac{1}{15}\)=\(1\frac{1}{2}\)

X : \(\frac{46}{15}\)=\(\frac{3}{2}\)

X =  \(\frac{3}{2}\)X \(\frac{46}{15}\)

X = \(\frac{23}{5}\)

#)Giải :

\(x\div3\frac{1}{5}=1\frac{1}{2}\)

\(\Leftrightarrow x\div\frac{16}{5}=\frac{3}{2}\)

\(\Leftrightarrow x=\frac{24}{5}\)hay \(4\frac{4}{5}\)

\(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)

\(\Leftrightarrow\left(\frac{2}{3}-\frac{1}{2}\right)x=\frac{5}{12}\)

\(\Leftrightarrow\frac{1}{6}x=\frac{5}{12}\)

\(\Leftrightarrow x=\frac{5}{2}\)

câu a sai đề nha

a, \(\frac{x}{5}=\frac{2}{3}\Leftrightarrow x=\frac{10}{3}\)

b, \(\frac{x}{-24}=\frac{20}{42}\Leftrightarrow x=-\frac{80}{7}\)

c, \(\frac{x+3}{15}=\frac{1}{3}\Leftrightarrow3x+9=15\Leftrightarrow x=2\)

d, \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\Leftrightarrow x\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\Leftrightarrow-\frac{5}{6}x=\frac{5}{12}\Leftrightarrow x=-\frac{1}{2}\)

\(\frac{x}{5}=\frac23\)

\(x\) = \(\frac23\times5\)

\(x=\frac{10}{3}\)

Vậy \(x=\frac{10}{3}\)

\(\frac{x}{3}-\frac12=\frac15\)

\(\frac{x}{3}\) = \(\frac15\) + \(\frac12\)

\(\frac{x}{3}\) = \(\frac{2}{10}+\frac{5}{10}\)

\(\frac{x}{3}=\frac{7}{10}\)

\(x=\frac{7}{10}\times3\)

\(x=\frac{21}{10}\)

Vậy \(x=\frac{21}{10}\)

\(\frac{x}{5}+\frac12=\frac{6}{10}\)

\(\frac{x}{5}=\frac{6}{10}-\frac12\)

\(\frac{x}{5}=\frac{6}{10}-\frac{5}{10}\)

\(\frac{x}{5}=\frac{1}{10}\)

\(x=\frac{1}{10}\times5\)

\(x=\frac12\)

Vậy \(x=\frac12\)

\(\frac{x+3}{15}\) = \(\frac13\)

\(x+3=\frac13\times15\)

\(x+3=5\)

\(x=5-3\)

\(x=2\)

Vậy \(x=2\)

a)    \(\frac{x}{5}=\frac{2}{3}\)

\(\Rightarrow\)\(x=\frac{2.5}{3}=\frac{10}{3}\)

Vậy....

b)   \(\frac{x+3}{15}=\frac{1}{5}\)

\(\Leftrightarrow\)\(5\left(x+3\right)=15\)

\(\Leftrightarrow\)\(x+3=3\)

\(\Leftrightarrow\)\(x=0\)

Vậy....

mấy câu này bạn tích chéo là được 

\(\frac{a}{b}=\frac{c}{d}\Rightarrow a.d=b.c\)  rồi giải bình thường 

a)\(\left(4\frac{5}{37}-3\frac45+8\frac{15}{29}\right)-\left(3\frac{5}{57}-6\frac{14}{29}\right)\)

=\(4\frac{5}{37}-3\frac45+8\frac{15}{29}-3\frac{5}{37}+6\frac{14}{29}\)

=\(\left(4\frac{5}{37}-3\frac{5}{37}\right)+\left(8\frac{15}{29}+6\frac{14}{29}\right)-3\frac45\)

=\(\left\lbrack\left(4-3\right)+\left(\frac{5}{37}-\frac{5}{37}\right)\right\rbrack+\left\lbrack\left(8+6\right)+\left(\frac{15}{29}\right.\right.\)+\(\frac{14}{29})\) -\(\frac{19}{5}\)

=\(1+0+14+1-\frac{19}{5}\)

=\(15+1-\frac{19}{5}\)

=\(16-\frac{19}{5}\)

=\(\frac{80}{5}-\frac{19}{5}\)

=\(\frac{61}{5}\)