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\(1\frac{1}{2}+x=\frac{3}{2}-7\)
<=> \(\frac{3}{2}+x=\frac{-11}{2}\)
<=> \(x=-7\)
\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
<=> \(\frac{1}{3}:3x=\frac{-21}{4}\)
<=> \(3x=\frac{-4}{63}\)
<=> \(x=\frac{4}{189}\)
\(\frac{4}{5}.x=\frac{8}{35}\)
<=> \(x=\frac{2}{7}\)
\(\frac{2}{3x}-\frac{1}{4}=\frac{7}{1}\)
<=> \(\frac{2}{3x}=\frac{29}{4}\)
=> \(8=87x\)
<=> \(x=\frac{8}{87}\)
\(\frac{3}{5x}+\frac{1}{2}=\frac{1}{7}\)
<=> \(\frac{3}{5x}=\frac{-5}{14}\)
<=> \(-25x=42\)
<=> \(x=\frac{-42}{25}\)
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16.\frac{2}{3}\right)=0\)
<=> \(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{-32}{3}=0\)
<=> \(\frac{43}{8}+x-\frac{173}{24}=\frac{-32}{3}\)
<=> \(\frac{43}{8}+x=\frac{-83}{24}\)
<=> \(x=\frac{-53}{6}\)
học tốt
\(\dfrac{8}{9}\) : ( 2 - 3 \(\times\) y) = \(\dfrac{5}{3}\)
2 - 3 \(\times\) y = \(\dfrac{8}{9}\) : \(\dfrac{5}{3}\)
2 - 3 \(\times\) y = \(\dfrac{8}{15}\)
3 \(\times\) y = 2 - \(\dfrac{8}{15}\)
3 \(\times\) y = \(\dfrac{22}{15}\)
y = \(\dfrac{22}{15}\) : 3
y = \(\dfrac{22}{45}\)
a) (-4)2 . \(\frac{1}{4}\). |-6| + |-6|3 : 6
= 16 . \(\frac{1}{4}\). 6 + 63 : 6
= 4 . 6 + 62
= 24 + 36
= 60
Mà mik nói này chừng nữa có đăng câu hỏi thì bạn đăng ít câu trong 1 lần thôi, bạn mà đăng nhiều câu thế thì người nhìn vào thấy ngán và ko muốn trả lời đâu đó !
Mik giải từng câu nhé !
=1,4 x\(\dfrac{15}{49}-\) \(\left(\dfrac{4}{5}+\dfrac{2}{3}\right)\) : 2\(\dfrac{1}{5}\)
= \(\dfrac{3}{7}\) - \(\dfrac{22}{15}\) : \(\dfrac{11}{5}\)
= \(\dfrac{3}{7}\) - \(\dfrac{2}{3}\)
= \(-\dfrac{5}{21}\)
( 2\(\dfrac{1}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(x\)) = \(\dfrac{3}{4}\)
\(\dfrac{11}{5}\) + \(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\)
\(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\) - \(\dfrac{11}{5}\)
\(\dfrac{3}{5}\)\(x\) = - \(\dfrac{29}{20}\)
\(x\) = -\(\dfrac{29}{12}\)
3\(\dfrac{1}{3}\) x \(x+16\)\(\dfrac{3}{4}\)= 13,25
\(\dfrac{10}{3}\) x \(x\) + \(\dfrac{67}{4}\) = 13,25
\(\dfrac{10}{3}\) x \(x\) = 13,25 - \(\dfrac{67}{4}\)
\(\dfrac{10}{3}\times x=\) \(\dfrac{103}{28}\)
\(x\) = \(\dfrac{103}{28}:\dfrac{10}{3}\)
\(x=\) \(\dfrac{309}{280}\)
(2.4\(x\) - 36) : 1\(\dfrac{5}{7}\) = -1
(8\(x\) - 36): \(\dfrac{12}{7}\) = - 1
8\(x\) - 36 = - 1 \(\times\) \(\dfrac{12}{7}\)
8\(x\) - 36 = - \(\dfrac{12}{7}\)
8\(x\) = - \(\dfrac{12}{7}\) + 36
8\(x\) = \(\dfrac{240}{7}\)
\(x\) = \(\dfrac{30}{7}\)
=0,25 : (10,3 - 9,8 ) - \(\dfrac{3}{4}\)
=0,25 : 0,5 - 0,75
= 0,5 - 0,75
= -0,25
\(\left(3\dfrac{4}{5}-2\times x\right)\times1\dfrac{1}{3}=5\dfrac{5}{7}\)
\(\left(\dfrac{19}{5}-2\times x\right)\times\dfrac{4}{3}=\dfrac{40}{7}\)
\(\dfrac{19}{5}\times\dfrac{4}{3}-2\times x\times\dfrac{4}{3}=\dfrac{40}{7}\)
\(\dfrac{76}{15}-\dfrac{8}{3}x=\dfrac{40}{7}\)
\(\dfrac{8}{3}x=\dfrac{76}{15}-\dfrac{40}{7}\)
\(\dfrac{8}{3}x=\dfrac{-68}{105}\)
\(x=\dfrac{-68}{105}:\dfrac{8}{3}\)
\(x=\dfrac{-68}{105}\times\dfrac{3}{8}\)
\(x=\dfrac{-17}{70}\)