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\(A=3+3^2+3^3+3^4+...+3^{10}\)
=> \(A=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^9+3^{10}\right)\)
=> \(A=3\left(1+3\right)+3^3\left(1+3\right)+...+3^9\left(1+3\right)\)
=> \(A=3.4+3^3.4+...+3^9.4\)
=> \(A=4\left(3+3^3+...+3^9\right)\)chia hết cho 4 (Đpcm)
A = 3 + 32 + 33 + ... + 39 + 310
=> A = ( 3 + 32 ) + ( 33 + 34 ) + ... + ( 39 + 310 )
=> A = 3( 1 + 3 ) + 33( 1 + 3 ) + ... + 39( 1 + 3 )
=> A = 3 . 4 + 33 . 4 + ... + 39 . 4
=> A = ( 3 + 33 + ... + 39 ) . 4 chia hết cho 4
=> A chia hết cho 4
Vậy...
\(-\left(+51\right);-|-39|;-37;0;|-18|;-\left(-19\right);25\)
a, (18+29) +(158-18-29)
= 18+29+158-18-29
= (18-18) +(29-29)+ 158
= 158
b, (13-135+49)- (13+49)
= 13-135+49-13-49
= (13-13) +(49-49) -135
= 135
a, \(\left(18+29\right)+\left(158-18-29\right)\)
\(=18+29+158-18-29\)
\(=\left(18-18\right)+\left(29-29\right)+158\)
\(=158\)
b,
\(\left(13-135+49\right)-\left(13+49\right)\)
\(=13-135+49-13-49\)
= \(\left(13-13\right)+\left(49-49\right)-135\)
= \(-135\)
13-135+49-13+(-49)
=(13-13)-135[ 49+(-49)]
=0-135+0
=135
hhọc tốt
\(13-135+49-13+\left(-49\right)\)
\(=\left(13-13\right)+\left[\left(-49\right)+49\right]-135\)
\(=0+0-135=-135\)
( 13 - 135 + 49 ) - ( 13 + 49 )
= 13 - 135 + 49 - 13 - 49
= ( 13 -13 ) + ( 49 - 49 ) - 135
= 0 + 0 - 135
= -135
( 13 - 135 + 49 ) - ( 13 + 49 )
= 13 - 135 + 49 - 13 - 49
= ( 13 -13 ) + ( 49 - 49 ) - 135
= 0 + 0 - 135
= -135
(13-135+49)-(13+49)
= 13-135+49-13-49
= 13-13+49-49-135
= 0+0-135
= -135
( 13 + 49) - ( 13 - 135 + 49)
= 13 + 49 - 13 + 135 - 49
= ( 13 - 13) + ( 49 - 49) + 135
= 0 + 0 + 135
= 135
135
= (13 + 49) -13 + 135 - 49
= 13 + 49 - 13 + 135 - 49
= (13 -13) + (49- 49) + 135
=135
135