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8 ) | x + 12 | - 12 = 1
\(|x+12|=13\)
\(\Rightarrow\orbr{\begin{cases}x+12=13\\x+12=-13\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=-25\end{cases}}\)
Vậy \(x\in\left\{1;-25\right\}\)
9) 135 -\(|9-x|=35\)
\(|9-x|=135-35\)
\(|9-x|=100\)
\(\Rightarrow\orbr{\begin{cases}9-x=100\\9-x=-100\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-91\\x=109\end{cases}}\) Vậy x\(\in\left\{-91;109\right\}\) 10) 17+x-(352-400)=-32 17+x-352+400=-32 17+x-352 =(-32) - 400 17+x-352 =-432 17+x =(-432) + 352 17+x =-80 x =(-80) - 17 x =-97 Vậy x =-97 11) 2130 - (x+136) + 72 =-64 2130 - (x+136) =(-64) -72 2130 - (x+136) =-136 (x +136) = 2130 -(-136) x+136 =2266 x =2266 - 136 x =2130 Vậy x=2130 do sap an cơm nên chiều mình sẽ giải tiếp nha! sorryy
12) (x-2) - (-8) = -137
(x-2) +8 =-137
(x-2) =(-137) - 8
x-2 =-145
Vậy x=-145
13) 10-\(|x+3|=-4.\left(-10\right)\) 10- \(|x+3|=40\) \(|x+3|=\) 40+10 \(|x+3|=50\)
\(\Rightarrow\orbr{\begin{cases}x+3=50\\x+3=-50\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=50-3\\x=\left(-50\right)-3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=20\\x=-53\end{cases}}\)
Vậy x\(\in\left\{20;-53\right\}\)
\(D=\left(\dfrac{32}{15}.\dfrac{9}{17}.\dfrac{3}{32}\right):\left(\dfrac{-3}{17}\right)\)
\(D=\dfrac{9}{85}:\left(\dfrac{-3}{17}\right)\)
\(D=\dfrac{9}{85}.\left(\dfrac{-17}{3}\right)\)
\(D=-\dfrac{3}{5}\)
1: \(\left(-\frac{25}{13}\right)+\left(-\frac{19}{17}\right)+\frac{12}{13}+\left(-\frac{25}{17}\right)\)
\(=\left(-\frac{25}{13}+\frac{12}{13}\right)+\left(-\frac{19}{17}-\frac{15}{17}\right)\)
\(=-\frac{13}{13}-\frac{34}{17}=-1-2=-3\)
2: \(\frac12-\left(-\frac13\right)+\frac{1}{23}+\frac16\)
\(=\left(\frac12+\frac13+\frac16\right)+\frac{1}{23}\)
\(=1+\frac{1}{23}=\frac{24}{23}\)
3: \(\left(-\frac37\right)\cdot\frac{5}{11}+\left(-\frac{5}{14}\right)\cdot\frac{5}{11}\)
\(=\frac{5}{11}\left(-\frac37-\frac{5}{14}\right)\)
\(=\frac{5}{11}\cdot\left(-\frac{6}{14}-\frac{5}{14}\right)=\frac{5}{11}\cdot\frac{-11}{14}=\frac{-5}{14}\)
4: \(\left(-\frac{5}{11}\right)\cdot\frac{7}{15}\cdot\frac{11}{-5}\cdot\left(-30\right)=-30\cdot\frac{7}{15}=-14\)
5: \(\left(-\frac59\right)\cdot\frac{3}{11}+\left(-\frac{13}{18}\right)\cdot\frac{3}{11}\)
\(=\frac{3}{11}\left(-\frac59-\frac{13}{18}\right)\)
\(=\frac{3}{11}\cdot\frac{-23}{18}=\frac{-23\cdot1}{11\cdot6}=-\frac{23}{66}\)
6: \(2\frac{2}{15}\cdot\frac{9}{17}\cdot\frac{3}{32}:\left(-\frac{3}{17}\right)\)
\(=\frac{32}{15}\cdot\frac{3}{32}\cdot\frac{9}{17}\cdot\frac{-17}{3}=\frac{3}{15}\cdot\frac{-9}{3}=\frac{-9}{15}=-\frac35\)
7: \(\left(-\frac34+\frac25\right):\frac37+\left(\frac35-\frac14\right):\frac37\)
\(=\left(-\frac34+\frac25+\frac35-\frac14\right):\frac37\)
\(=\left(-1+1\right):\frac37=0\)
8: \(\left(-\frac13\right)\cdot\left(-\frac{15}{19}\right)\cdot\frac{38}{45}=\frac{15}{45\cdot3}\cdot\frac{38}{19}=2\cdot\frac{1}{3\cdot3}=\frac29\)
9: \(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\cdots+\frac{1}{19\cdot20}\)
\(=\frac12-\frac13+\frac13-\frac14+\cdots+\frac{1}{19}-\frac{1}{20}\)
\(=\frac12-\frac{1}{20}=\frac{9}{20}\)
10: \(\frac{1}{9\cdot10}-\frac{1}{8\cdot9}-\frac{1}{7\cdot8}-\cdots-\frac{1}{2\cdot3}-\frac{1}{1\cdot2}\)
\(=\frac{1}{9\cdot10}-\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\cdots+\frac{1}{8\cdot9}\right)\)
\(=\frac19-\frac{1}{10}-\left(1-\frac12+\frac12-\frac13+\cdots+\frac18-\frac19\right)\)
\(=\frac19-\frac{1}{10}-\left(1-\frac19\right)=\frac19-\frac{1}{10}-\frac89=-\frac79-\frac{1}{10}=\frac{-79}{90}\)
-1/5 . (9/8 + 16/32 - 12/46) - 9/17
= -1/5 . (9/8 + 1/2 - 6/23) - 9/17
= -1/5 . (9/8 + 4/8 - 6/23) - 9/17
= -1/5 . (13/8 - 6/23) - 9/17
= -1/5 . 251/184 - 9/17
= -251/920 - 9/17
= -4267/15640 - 8280/15640
= -12547/15640
(12/5.9/17.3/32):(3/17)
=81/680:3/17
=27/40