\(\frac{\frac{1}{2\times4}+\frac{1}{4\times6}+\frac{1}{6\times8}+...+\frac{1}{98\times100}}{y}=\frac{147}{50}\)

\(\frac{\frac{1}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{98\times100}\right)}{y}=\frac{147}{50}\)

\(\frac{\frac{1}{2}\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{98}-\frac{1}{100}\right)}{y}=\frac{147}{50}\)

\(\frac{\frac{1}{2}\times\left(\frac{1}{2}-\frac{1}{100}\right)}{y}=\frac{147}{50}\)

\(\frac{\frac{1}{2}\times\frac{49}{100}}{y}=\frac{147}{50}\)

\(\frac{49}{200}:y=\frac{147}{50}\)

\(y=\frac{49}{200}:\frac{147}{50}\)

\(y=\frac{1}{12}\)

a: \(\frac{52}{17}>\frac{51}{17}=3\)

\(3=\frac{121}{41}>\frac{120}{41}\)

Do đó: \(\frac{52}{17}>\frac{120}{41}\)

b: \(\frac34+\frac14:\left(\frac{7}{12}-\frac16\right)\)

\(=\frac34+\frac14:\left(\frac{7}{12}-\frac{2}{12}\right)\)

\(=\frac34+\frac14:\frac{5}{12}\)

\(=\frac34+\frac14\times\frac{12}{5}=\frac34+\frac35=\frac{15}{20}+\frac{12}{20}=\frac{27}{20}\)

c: \(372,463\cdot998+744,926\)

\(=372,463\cdot998+372,463\cdot2\)

\(=372,463\times\left(998+2\right)=372,463\times1000=372463\)

d: Số số hạng trong dãy số 2;4;6;...;100 là:

\(\left(100-2\right):2+1=98:2+1=49+1=50\) (số)

\(2-4+6-8+10-12+\cdots+98-100+102\)

\(=\left(2-4\right)+\left(6-8\right)+\cdots+\left(98-100\right)+102\)

=(-2)+(-2)+...+(-2)+102

\(=-2\cdot\frac{50}{2}+102=-50+102=52\)

e: (y+112)-113=79

=>y+112-113=79

=>y-1=79

=>y=79+1=80

f: \(\frac34-y=\frac12\)

=>\(y=\frac34-\frac12=\frac14\)

g: \(\left(\frac45-2\times y\right)+\frac16=\frac56\)

=>\(\frac45-2\times y=\frac56-\frac16=\frac46=\frac23\)

=>\(2\times y=\frac45-\frac23=\frac{12}{15}-\frac{10}{15}=\frac{2}{15}\)

=>\(y=\frac{2}{15}:2=\frac{1}{15}\)

h: (y+1)+(y+2)+...+(y+50)=1750

=>50y+(1+2+...+50)=1750

=>\(50y+50\times\frac{51}{2}=1750\)

=>50y+1275=1750

=>50y=1750-1275=475

=>\(y=\frac{475}{50}=9,5\)

Đặt \(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+....+\frac{1}{98.100}=A\)

<=> \(A=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+....+\frac{1}{98}-\frac{1}{100}\right)\)

<=> \(A=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{100}\right)\)

<=> \(A=\frac{1}{2}.\frac{49}{100}=\frac{49}{200}\)

lúc đó \(\frac{A}{Y}=\frac{147}{50}\)<=> \(Y=\frac{49}{200}.\frac{50}{147}=\frac{1}{12}\)

a) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 +9

= ( 1+9) + (2+8) + (3+7) + (4+6)+5

= 10.4+5

= 45

b)

Dãy đó có số số hạng là: ( 25-1):1+1= 25 số

Tổng là: 25.( 25+1):2=325

Vậy....

ta có : đề bài

        =1/2*(2/2*4+2/4*6+2/6*8+...+2/96*98+2/98*100)

        =1/2*(1/2-1/4+1/4-1/6+1/6-1/8+...+1/96-1/98+1/98-1/100)

        =1/2*(1/2-1/100)

        =1/2*49/10

        =49/200

Bạn bên trên nhầm 49/100 thành 49/10. Kết quả đúng nhưng bạn ko chú ý dòng thứ 2 từ dưới lên

= 1/2 -1/4 + 1/4 - 1/6 + 1/6 + 1/8 + ... + 1/96 - 1/98 + 1/98 - 1/100
= 1/2 - 1/100
= 49/10