2/3x - 3/2x = 5/12

=> ( 2/3 - 3/2 )x = 5/12

=> -5/6x = 5/12

=> x = 5/12 : -5/6

=> x = -1/2

( x + 1/2 ) . ( 2/3 - 2x ) = 0

=> x + 1/2 = 0 hoặc 2/3 - 2x = 0

=> x = -1/2 hoặc x = 1/3

Câu 1: 

\(\dfrac{128}{\left(n-3\right)^3}=2\)

\(\Leftrightarrow\left(n-3\right)^3=64\)

=>n-3=4

hay n=7

Câu 2: 

\(\Leftrightarrow x^3+12=57\cdot4=228\)

\(\Leftrightarrow x^3=216\)

hay x=6

a) 80 - [130 - (12 -4)² ] 

= 80 - ( 130 - 8² )

= 80 - 116

= -36

b) 541 + (218 - b) = 735

218 - b = 194

b = 24

c) 5(x + 35) =515

x+35 = 103

x = 68

d) 96 - 3(x + 1) = 42

3(x+1) = 54

x+1 = 18

x = 17

12x - 33 = 3² . 3³

12x - 33 = 243

12x = 276

x = 23

\(2^{x+2}-2^x=96\)

\(\Rightarrow2^x\cdot2^2-2^x=96\)

\(\Rightarrow2^x\left(2^2-1\right)=96\)

\(\Rightarrow2^x\left(4-1\right)=96\)

\(\Rightarrow2^x\cdot3=96\)

\(\Rightarrow2^x=96:3\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

\(5^x+5^{x+1}=750\)

\(\Rightarrow5^x+5^x\cdot5=750\)

\(\Rightarrow5^x\left(1+5\right)=750\)

\(\Rightarrow5^x\cdot6=750\)

\(\Rightarrow5^x=750:6\)

\(\Rightarrow5^x=125\)

\(\Rightarrow5^x=5^3\)

\(\Rightarrow x=3\)

\(2^{x+3}+2^x=144\)

\(\Rightarrow2^x\cdot2^3+2^x=144\)

\(\Rightarrow2^x\left(2^3+1\right)=144\)

\(\Rightarrow2^x\cdot9=144\)

\(\Rightarrow2^x=144:9\)

\(\Rightarrow2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

a) x-12=(-28)

x=(-28)+12

x=(-16)

Vậy x=(-16)

b)20+8|x-3|=5².4

20+8|x-3|=100

8|x-3|=100-20

8|x-3|=80

|x-3|=80:8

|x-3|=10

=>x-3=10 hoặc x-3=(-10)

 x=10+3           x=(-10)+3

x=13                x=(-7)

Vậy x thuộc {13;-7}

c) 96-3(x+1)=42

         3(x+1)=96-42

         3(x+1)54

            x+1=54:3

           x+1=18

           x=18-1

           x=17

Vậy x=17

|x-3|=7-(-2)

|x-3|=9

=>x-3=9    hoặc x-3=(-9)

x=9+3                   x=(-9)+3

x=12                        x=(-6)

Vậy...

e) (2x-1)³=125

(2x-1)³=5³

=>2x-1=5

...

Còn lại tự lm nha

Câu g tương tự câu e

câu này có vẻ khá khó

a)Đặt \(A=3-3^2+3^3-3^4+...+3^{95}-3^{96}\)

\(3A=3^2-3^3+3^4-3^5+...+3^{96}-3^{97}\)

\(3A+A=\left(3^2-3^3+3^4-3^5+...+3^{96}-3^{97}\right)+\left(3-3^2+3^3-3^4+...+3^{95}-3^{96}\right)\)

\(4A=-3^{97}+3\)

\(A=\frac{-3^{97}+3}{4}\)

b)tương tự như câu a

c)\(\left(100-1^2\right)\left(100-2^2\right)\left(100-3^2\right).....\left(100-99^2\right)\)

\(=\left(10^2-1^2\right)\left(10^2-2^2\right)\left(10^2-3^2\right)....\left(10^2-10^2\right)...\left(10^2-99^2\right)\)

\(=\left(10^2-1^2\right)\left(10^2-2^2\right)\left(10^2-3^2\right)...0...\left(10^2-99^2\right)\)

=0

muốn chịch ko

a) (x^3+12):4=60+(-3)

(x^3+12).1/4=57

x^3+12=228

x^3=216

x^3=6^3

=> x=6

b) 2^x+1.3=96

2^x+1.3=2^5.3

2^x+1=2^5.3:3

2^x+1=2^5

=> x+1=5

x=4

a) x=5

b) x=1

c) x=5

d)x=14