Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9
=7/18
\(1\frac12\cdot1\frac13\cdot1\frac14\)
\(=\frac32\cdot\frac43\cdot\frac54=\frac52\)
\(\frac{1}{2}x\frac{1}{3}+\frac{1}{3}x\frac{1}{4}\)
= \(\frac{1}{3}\)x \(\left(\frac{1}{2}+\frac{1}{4}\right)\)
= \(\frac{1}{3}\) x \(\frac{3}{4}\)
= \(\frac{1}{4}\)
~Hok tốt~
Sửa đề: \(\frac12\cdot1+\frac13\left(1+2\right)+\frac14\left(1+2+3\right)+\cdots+\frac{1}{100}\left(1+2+3+\cdots+99\right)\)
\(=\frac12+\frac13\cdot\frac{2\cdot3}{2}+\frac14\cdot\frac{3\cdot4}{2}+\cdots+\frac{1}{100}\cdot\frac{99\cdot100}{2}\)
\(=\frac12+\frac22+\frac32+\cdots+\frac{99}{2}=\frac12\left(1+2+\cdots+99\right)\)
\(=\frac12\cdot99\cdot\frac{\left(99+1\right)}{2}=\frac12\cdot99\cdot50=25\cdot99=2475\)
\(\frac{1}{1}\cdot\frac{1}{2}+\frac{1}{2}\cdot\frac{1}{3}+\frac{1}{3}\cdot\frac{1}{4}+...+\frac{1}{79}\cdot\frac{1}{80}\)
\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{79\cdot80}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}+...+\frac{1}{79}-\frac{1}{80}\)
\(=1-\frac{1}{80}\)
\(=\frac{79}{80}\)