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\(\frac{55}{22}+\frac{44}{22}\)
\(=\frac{55+44}{22}\)
\(=\frac{99}{22}\)
~~~~~~~~~~~~~~~
\(80-\frac{1}{9}-\frac{2}{10}-\frac{3}{11}-...-\frac{80}{88}=\left(1-\frac{1}{9}\right)+\left(1-\frac{2}{10}\right)+\left(1-\frac{3}{11}\right)+...+\left(1-\frac{80}{88}\right)\)
\(=\frac{8}{9}+\frac{8}{10}+\frac{8}{11}+...+\frac{8}{88}=8.\left(\frac{1}{9}+\frac{1}{10}+\frac{1}{11}+\frac{1}{88}\right)\)
\(\frac{1}{45}+\frac{1}{50}+\frac{1}{55}+...+\frac{1}{440}=\frac{1}{5}\left(\frac{1}{9}+\frac{1}{10}+\frac{1}{11}+...+\frac{1}{88}\right)\)
=>B=8:1/5=40
a) \(\frac{14}{15}+\frac{3}{11}+\frac{1}{15}+\frac{3}{11}+\frac{10}{22}\)
\(=\left(\frac{14}{15}+\frac{1}{15}\right)+\left(\frac{3}{11}+\frac{3}{11}\right)+\frac{10}{22}\)
\(=1+1+\frac{10}{22}\)
\(=2+\frac{10}{22}\)
\(=\frac{27}{11}\)
b) 9,25 + 9,25 x 8 + 9,25
= 9,25 x ( 8 + 1 + 1 )
= 9,25 x 10
= 92,5
a/ 1+4+7+10+....+52+55+58-410=[(58-1):3+1]x(58+1)-410=20x59-410=770
Quên mất, bảo tối hôm đó vào làm :)). May là sang nay có ng k ms vào xem. Sorry
S=\(\frac{92-\left(1-\frac{8}{9}\right)-\left(1-\frac{8}{10}\right)-..-\left(1-\frac{8}{100}\right)}{\frac{1}{5}.\left(\frac{1}{9}+\frac{1}{10}+...+\frac{1}{100}\right)}=\frac{92-92+\left(\frac{8}{9}+\frac{8}{10}+...+\frac{8}{100}\right)}{\frac{1}{5}\left(\frac{1}{9}+\frac{1}{10}+...+\frac{1}{100}\right)}\)
=\(\frac{8\left(\frac{1}{9}+\frac{1}{10}+...+\frac{1}{100}\right)}{\frac{1}{5}\left(\frac{1}{9}+\frac{1}{10}+....+\frac{1}{100}\right)}=\frac{8}{\frac{1}{5}}=\frac{8.5}{1}=40\)
Vậy S=40
10 : 11 + 22 - 2 : 55
= \(\frac{10}{11}\) + 22 - \(\frac{2}{55}\)
= \(\frac{50}{55}\) + \(\frac{1210}{55}\) - \(\frac{2}{55}\)
= \(\frac{1258}{55}\)
7:38