Câu hỏi của Nguyễn Thị My Na

Question

1. Tính giá trị của biểu thức sau:

B = $\frac{8^7.3^9}{6^9.2^{11}}$

Mai Linh Chi · Accepted Answer

B = $\frac{\left(2^3\right)^7.3^9}{2^9.3^9.2^{11}}$

B = $\frac{2^{21}}{2^{20}}$

B = $2$

Câu trả lời:

B = $\frac{\left(2^3\right)^7.3^9}{2^9.3^9.2^{11}}$

B = $\frac{2^{21}}{2^{20}}$

B = $2$

Thùy Ninh · Answer

$B=\frac{8^7.3^9}{6^9.2^{11}}=\frac{\left(2^3\right)^7.3^9}{2^9.3^9.2^{11}}=\frac{2^{21}.3^9}{2^{20}.3^9.}=2$

Câu trả lời:

$B=\frac{8^7.3^9}{6^9.2^{11}}=\frac{\left(2^3\right)^7.3^9}{2^9.3^9.2^{11}}=\frac{2^{21}.3^9}{2^{20}.3^9.}=2$

Hoàng Văn Dũng · Answer

$B=\frac{8^7\cdot3^9}{6^9\cdot2^{11}}=\frac{2^{21}\cdot3^9}{2^9\cdot3^9\cdot2^{11}}=\frac{2^{21}\cdot3^9}{2^{20}\cdot3^9}=\frac{2^{21}}{2^{20}}=2$

Câu trả lời:

$B=\frac{8^7\cdot3^9}{6^9\cdot2^{11}}=\frac{2^{21}\cdot3^9}{2^9\cdot3^9\cdot2^{11}}=\frac{2^{21}\cdot3^9}{2^{20}\cdot3^9}=\frac{2^{21}}{2^{20}}=2$