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Bài 1 :
a) 5x = 125
=> 5x = 53
=> x = 3
b) 34 . 3x = 37
=> 4 + x = 7
=> x = 7 - 4
=> x = 2
5x+1 = 125 = 53
x + 1 = 3 => x = 2
b) 3x-1 = 81 = 34
x - 1 = 4 => x= 5
c) (x - 6)2 = 9 = 32
x - 6 = 3 => x = 9
(2x - 7)2 = 169 = 132
2x - 7 = 13 => x = 10
d) x3 = 216 = 23.3
x3 = (2.3)3 = 63
Vậy x = 6
a) 2.3x+2 + 4.3x+1 = 10.32019
<=> 3x+1(6 + 4) = 10.32019
<=> 10.3x+1 = 10.32019
<=> 3x+1 = 32019
<=> x = 2018.
b) (9-4x)3 = 125 = 53
<=> 9 - 4x = 5
<=> 4 = 4x
<=> x = 1
c) 2.22.23....2x = 1024 = 210
<=> 2(1+2+3+...+x) = 210
<=> 1+2+3+...+x = 10
<=>x.(x+1)/2 = 10
<=> x(x+1) = 20 = 4.5
<=> x = 4.
a)23 .2x=128
=>23+x=128
=>23+x=27
=>3+x=7
=>x=4
b)2x+2x+3=144
=>2x(1+23)=144
=>2x*9=144
=>2x=16
=>2x=24
=>x=4
c)x-287:285=125
=>x-287-85=125
=>x-4=125
=>x=129
d)3x+4-3x=720
=>3x(34-1)=720
=>3x*80=720
=>3x=9
=>3x=32
=>x=2
e)812x:27x=95
=>(34)2x:(33)x=95
=>38x:33x=95
=>38x-3x=(32)5
=>35x=310
=>5x=10
=>x=2
a) (4x - 1)2 = 25.9
=> (4x - 1)2 = 52 . 32 = 152
=> 4x - 1 = 15
=> 4x = 16
=> x = 4
b) 2x + 2x+3 = 144
=> 2x + 2x . 23 = 144
=> 2x (1 + 23) = 144
=> 2x . 9 = 144
=> 2x = 16
=> x = 4
c) đề chắc chắn đúng chứ :v
d) (2x + 1)3 - 12 = 15
=> (2x + 1)3 = 27
=> (2x + 1)3 = 33
=> 2x + 1 = 3 => 2x = 2 => x = 1
2. 2x = 16 => 2x = 24 => x = 4
3x = 81 => 3x = 34 => x = 4
x3 = 64 => x3 = 43 => x = 4
x2 =81 => x2 = 92 => x = 9
a) \(2^x+2^{x+1}=96\Leftrightarrow2^x+2\cdot2^x=96\Leftrightarrow2^x\cdot3=96\Leftrightarrow2^x=48\)
Không có x nguyên thỏa mãn.
b) \(3^{4x+4}=81\Leftrightarrow3^4\cdot3^x=3^4\Leftrightarrow3^x=1\Leftrightarrow x=0\)
a. (7x+2)^2=13^2
7x+2=13
7x=11
x=11/7
b.(4x-2)^3=5^3
4x-2=5
4x=7
x=7/4
c.(2x)^4=3^4
2x=3
x=3/2
a,(7x+2)2=169
(7x+2)2=132
7x+2=13
7x=13-2
7x=11
x=11/7
b(4x-2)3=125
(4x-2)3=53
4x-2=5
4x=5+2
4x=7
x=7/4
c(x+x)4=81
(x+x)4=34
x+x=3
2x=3
x=3:2
x=1,5
a. \(\left(7x+2\right)^2=169\) \(\Rightarrow\left(7x+2\right)^2=13^2\Rightarrow7x+2=13\Rightarrow7x=11\Rightarrow x=\frac{11}{7}\)
b . \(\left(4x-2\right)^3=125\Rightarrow\left(4x-2\right)^3=5^3\Rightarrow4x-2=5\Rightarrow4x=7\Rightarrow x=\frac{7}{4}\)
c. \(\left(x+x\right)^4=81\Rightarrow\left(x+x\right)^4=3^4\Rightarrow x+x=3\Rightarrow2x=3\Rightarrow x=\frac{3}{2}\)
a) (7x+2)2 = 169
<=> 7x+2 = 13
7x = 13 - 2
7x = 11
x = 11:7
\(x=\frac{11}{7}\)
b) (4x-2)3 = 125
<=> 4x-2 = 5
4x = 5+2
4x = 7
x = 7:4
\(x=\frac{7}{4}\)
c) (x+x)4 = 81
<=> 2x = 3
x = 3:2
\(x=\frac{3}{2}\)
a, \(\left(7x+2\right)^2=169\)
\(\Leftrightarrow\orbr{\begin{cases}\left(7x+2\right)^2=13^2\\\left(7x+2\right)^2=\left(-13\right)^2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}7x+2=13\\7x+2=-13\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}7x=13-2\\7x=-13-2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}7x=11\\7x=-15\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{11}{7}\\x=\frac{-15}{7}\end{cases}}\)
b, \(\left(4x-2\right)^3=125\)
\(\Leftrightarrow\left(4x-2\right)^3=5^3\)
\(\Leftrightarrow4x-2=5\)
\(\Leftrightarrow4x=5+2=7\)
\(\Leftrightarrow x=\frac{7}{4}\)
c,\(\left(x+x\right)^4=81\)
\(\Leftrightarrow\orbr{\begin{cases}\left(2x\right)^4=3^4\\\left(2x\right)^4=\left(-3\right)^4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=3\\2x=-3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{-3}{2}\end{cases}}\)
\(a,\left(7x+2\right)^2=169\)
\(\left(7x+2\right)^2=13^2\)
\(7x+2=13\) \(7x+2=-13\)
\(x=\frac{11}{7}\) còn 1 TH nữa
\(b,\left(4x-2\right)^3=125\)
\(4x-2=5\)
\(x=\frac{7}{4}\)