bài 1

a,\(\frac{x}{5}\)=\(\frac{2}{3}\)

b,\(\frac{x}{3}\)-\(\frac{1}{2}\)=\(\frac{1}{5}\)

c,\(\frac{x}{5}\)+\(\frac{1}{2}\)=\(\frac{6}{10}\)

d,\(\frac{x+3}{15}\)=\(\frac{1}{3}\)

e,\(\frac{x-12}{4}\)=\(\frac{1}{2}\)

h,\(\frac{4}{5}\)+x=\(\frac{2}{3}\)

i,\(\frac{3}{4}\)-x=\(\frac{1}{3}\)

k,\(\frac{-5}{6}\)-x=\(\frac{2}{3}\)

l,x-\(\frac{5}{9}\)=\(\frac{-2}{3}\)

m,\(\frac{1}{2}\)x+\(\frac{1}{2}\)=\(\frac{5}{2}\)

n,\(\frac{-2}{3}\)-\(\frac{1}{3}\)(2x-5)=\(\frac{3}{2}\)

p,(3x-1)(\(-\frac{1}{2}\)x+5)=0

q,\(3\frac{1}{3}\)+\(\frac{5}{6}\)x=\(3\frac{1}{2}\)

s,\(\frac{1}{2}\)-\(\frac{2}{3}\)x=\(\frac{7}{12}\)

t,\(\frac{3}{4}\)x+\(\frac{1}{5}\)=\(\frac{1}{6}\)

u,\(\frac{3}{8}\)-\(\frac{1}{6}\)x=\(\frac{1}{4}\)

mn ơi'-' xin hãy giúp mk với ạ>^<,mk cần rất gấp,mai nộp r ạ,mong mn giúp mk với ạ:(( huhuhu r mk tik cho:<<

Tìm x:

a) 5\(\frac{4}{7}\): x =13

b) \(\frac{4}{7}\)x=\(\frac{9}{8}\)-0,125

c) \(\frac{2}{3}\)x-\(\frac{1}{2}\)=\(\frac{1}{10}\)

d) \(\frac{1}{3}\)x-0,5x = -1\(\frac{1}{4}\)

e) \(\frac{-5}{6}\)- x = \(\frac{7}{12}\)+ \(\frac{-1}{3}\)

f) \(\frac{x+2}{3}\)=\(\frac{x-2}{2}\)

g) \(\frac{2}{5}\)- \(\frac{1}{5}\): x = -25%

h) (2\(\frac{4}{5}\)x - 50): \(\frac{2}{3}\)= 51

i) \(\frac{2}{3}\)x -\(\frac{1}{2}\)x =\(\frac{5}{12}\)

j) \(\frac{7}{2}\)- |2x -\(\frac{3}{4}\)| = -\(\frac{7}{4}\)

k) (x : 6\(\frac{2}{7}\)+\(\frac{3}{7}\)) :2\(\frac{1}{5}\)-\(\frac{3}{7}\)= -2

l) (x +\(\frac{1}{5}\))² +\(\frac{17}{25}\)=\(\frac{26}{25}\)

m) (x +\(\frac{1}{2}\))(\(\frac{2}{3}\)- 2x) =0

Mọi người ơi giúp mình nhanh nha.

Ai giúp mình thì mình sẽ tick cho.

câu 1:thực hiện phép tính (tính nhanh nếu có thể): 

a, \(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

b,\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}\)

c,\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)

d,\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2\)

câu 2:tìm x biết:

a, \(x+\frac{1}{6}=\frac{-3}{8}\)

b, \(\frac{1}{2}x+\frac{1}{8}x=\frac{3}{4}\)

c,\(2-\left|\frac{3}{4}-x\right|=\frac{7}{12}\)

d,\(\left(2x-4,5\right):\frac{3}{4}-\frac{1}{3}=1\)

GIÚP MIK VS MAI MIK PHẢI NỘP BÀI RỒI!

bài 2 tìm x

a,\(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)

b,\(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)

c,\(\frac{2}{3}.x-\frac{1}{2}=\frac{1}{10}\)

d,\(\frac{3}{5}+\frac{4}{9}:x=\frac{2}{3}\)

e,\(\left|x+75\%\right|=2\frac{1}{5}\)

i,\(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2.x\right)=0\)

k,\(\frac{4}{7}.x-\frac{2}{3}=\frac{1}{5}\)

l,\(\frac{2}{3}.x-\frac{3}{2}.x=\frac{5}{12}\)

m,\(\left|2.x-\frac{1}{3}\right|+\frac{5}{6}=1\)

n,\(\frac{1}{3}-\frac{7}{8}.x=\frac{1}{3}\)

11,\(\frac{x+2}{5}=\frac{7}{12}-1\frac{1}{4}\)

12,\(\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)

13,\(\frac{2}{5}+\frac{3}{5}.\left(3.x-3,7\right)=-\frac{53}{10}\)

14,\(\frac{7}{9}:\left(2+\frac{3}{4}.x\right)+\frac{5}{9}=\frac{23}{27}\)

Bài 1: 

A=0,7 . \(2\frac{2}{3}\). 20 . 0,375 . \(\frac{5}{28}\)

B=( 9,75 .\(21\frac{3}{7}\) + \(\frac{39}{4}\). \(18\frac{4}{7}\)) 

Bài 2

a)(x + \(\frac{1}{2}\)) . (\(\frac{2}{3}\)- 2x ) = 0

b)\(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)

c) x .\(3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)

d)\(5\frac{8}{17}:x+\left(\frac{-4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}\)= \(\frac{4}{11}\)

Tìm x \(\in\)Z biết 

a, \(\frac{1}{3}\)+ \(\frac{-2}{5}\)+ \(\frac{1}{6}\)+ \(\frac{-1}{5}\)\(\le\)x < \(\frac{-3}{4}\)+\(\frac{2}{7}\)+ \(\frac{3}{5}\)+ \(\frac{5}{7}\)+ \(\frac{-1}{4}\)

b, \(\frac{5}{17}\)+ \(\frac{-4}{9}\)+ \(\frac{-20}{31}\)+ \(\frac{12}{17}\)+ \(\frac{-11}{31}\)< x < \(\frac{-3}{7}\)+ \(\frac{7}{15}\)+ \(\frac{4}{-7}\)+ \(\frac{8}{15}\) + \(\frac{2}{3}\)