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1. Phân tích các đa thức sau thành nhân tử:
$x^4-12x^3+12x^2-12x+111$ tại $x=11$
$=11^4-12\cdot11^3+12\cdot11^2-12\cdot11+111$
$=14641-15972+1452-132+111$
$=100$
$(6x+1)^2+(6x-1)^2-2(1-6x)(6x-1)$
$=(6x+1)^2+(6x-1)^2+2(6x-1)^2$
$=(6x+1)^2+3(6x-1)^2$
$=36x^2+12x+1+3(36x^2-12x+1)$
$=36x^2+12x+1+108x^2-36x+3$
$=144x^2-24x+4$
$=4(36x^2-6x+1)$
b)$3(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=3\cdot\dfrac{2^4-1}{2^2-1}\cdot\dfrac{2^8-1}{2^4-1}\cdot\dfrac{2^{16}-1}{2^8-1}\cdot\dfrac{2^{32}-1}{2^{16}-1}$
$=3\cdot\dfrac{2^{32}-1}{2^2-1}$
$=3\cdot\dfrac{2^{32}-1}{3}$
$=2^{32}-1$
\(2\left(x+5\right)-x^2-5x\)
\(=2\left(x+5\right)-x\left(x+5\right)\)
\(=\left(x+5\right)\left(2-x\right)\)
\(y^2-6y+9-z^2\)
\(=\left(y-3\right)^2-z^2\)
\(=\left(y-3-z\right)\left(y-3+z\right)\)
k cho tui nha
a) (x + 2)(x + 4). b) 2(x + 6)(x + l).
c) 3(3x + 5)(x + l). d) (6x -7y)(x + y).
a) 15x + 15y = 15(x + y)
b) 6x - 10y = 2(3x - 5y)
c) 2a + 4b - 6c = 2(a + 2b - 3c)
d) 6xy - 12x - 18y = 6(xy - 2x - 3y)
e) 2(x + y) - 5a(x + y) = (2 - 5a)(x + y)
f) 6x(x - y) + 5(y - x) = 6x(x - y) + (-5)(x - y) = (6x - 5)(x - y)
a) \(15x+15y=15\left(x+y\right)\)
b) \(6x-10y=2\left(3x-5y\right)\)
c) \(2a+4b-6c=2\left(a+2b-3c\right)\)
d) \(6xy-12x-18y=6\left(xy-2x-3y\right)\)
e) \(2\left(x+y\right)-5a\left(x+y\right)=\left(2-5a\right)\left(x+y\right)\)
f) \(6x\left(x-y\right)+5\left(y-x\right)=6x\left(x-y\right)-5\left(x-y\right)=\left(6x-5\right)\left(x-y\right)\)
a) \(=3\left(5y+4x\right)\)
b) \(=\left(x-3\right)^2\)
c) \(=y\left(y^2+2y+3\right)\)
d) \(=x\left(x+y\right)+6\left(x+y\right)=\left(x+6\right)\left(x+y\right)\)