a) Ta có: \(-x+\frac{4}{7}=\frac{1}{3}\)

\(\Leftrightarrow-x=-\frac{5}{21}\)

\(\Rightarrow x=\frac{5}{21}\)

b) Ta có: \(x\div\left(-\frac{1}{3}\right)^2=-\frac{1}{3}\)

\(\Rightarrow x=\left(-\frac{1}{3}\right)^3=-\frac{1}{27}\)

c) \(\left(\frac{3}{5}\right)^5.x=\left(\frac{3}{5}\right)^7\)

\(\Rightarrow x=\left(\frac{3}{5}\right)^2=\frac{9}{25}\)

\(a.-x+\frac{4}{7}=\frac{1}{3}\)

 \(-x=\frac{1}{3}-\frac{4}{7} \)

  \(-x=\frac{7}{21}-\frac{12}{21}\)

 \(-x=\frac{-5}{21}\)

    \(x=\frac{5}{21}\)

\(b.x:\left(\frac{-1}{3}\right)^2=\frac{-1}{3}\)

\(x=\frac{-1}{3}.\left(\frac{-1}{3}\right)^2\)

\(x=\frac{-1}{3}.\frac{-1}{3}.\frac{-1}{3}\)

\(x=\frac{-1}{27}\)

\(c.\left(\frac{3}{5}\right)^5.x=\left(\frac{3}{5}\right)^7\)

\(x=\left(\frac{3}{5}\right)^7:\left(\frac{3}{5}\right)^5\)

\(x=\left(\frac{3}{5}\right)^2\)

\(x=\frac{3}{5}.\frac{3}{5}\)

\(x=\frac{9}{25}\)

\(x-40\%x=3,6\)

\(\Rightarrow100\%x-40\%x=3,6\)

\(\Rightarrow60\%x=3,6\)

\(\Rightarrow\frac{60}{100}x=3,6\)

\(\Rightarrow x=6\)

\(3\frac{2}{7}x-\frac{1}{3}=-2\frac{3}{4}\)

\(\Rightarrow\frac{23}{7}x-\frac{1}{3}=-\frac{11}{4}\)

\(\Rightarrow\frac{23}{7}x=-\frac{33}{12}+\frac{4}{12}\)

\(\Rightarrow\frac{23}{7}x=\frac{29}{12}\)

\(\Rightarrow x=\frac{29}{12}:\frac{23}{7}=\frac{203}{276}\)

a.

\(\frac{4}{7}x-\frac{2}{3}=\frac{1}{5}\)

\(\frac{4}{7}x=\frac{1}{5}+\frac{2}{3}\)

\(\frac{4}{7}x=\frac{3+10}{15}\)

\(\frac{4}{7}x=\frac{13}{15}\)

\(x=\frac{13}{15}\div\frac{4}{7}\)

\(x=\frac{13}{15}\times\frac{7}{4}\)

\(x=\frac{91}{60}\)

b.

\(\frac{2}{9}+\frac{7}{8}x=\frac{1}{3}\)

\(\frac{7}{8}x=\frac{1}{3}-\frac{2}{9}\)

\(\frac{7}{8}x=\frac{3-2}{9}\)

\(\frac{7}{8}x=\frac{1}{9}\)

\(x=\frac{1}{9}\div\frac{7}{8}\)

\(x=\frac{1}{9}\times\frac{8}{7}\)

\(x=\frac{8}{63}\)

Chúc bạn học tốt

b) \(\frac{2}{9}+\frac{7}{8}.x=\frac{1}{3}\)

\(\frac{1}{3}-\frac{2}{9}=\frac{7}{8}.x\)

\(\frac{7}{8}.x=\frac{1}{9}\)

\(x=\frac{1}{9}:\frac{7}{8}\)

\(x=\frac{8}{63}\)

c) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{3}\)

\(\frac{5}{7}:x=\frac{1}{3}-\frac{4}{5}\)

\(\frac{5}{7}:x=\frac{-7}{15}\)

\(x=\frac{5}{7}:\frac{-7}{15}\)

\(x=\frac{75}{-49}\)

b) \(\frac{2}{9}+\frac{7}{8}x=\frac{1}{3}\)

\(\frac{7}{8}x=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)

\(x=\frac{1}{9}:\frac{7}{8}=\frac{8}{63}\)

c) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{3}\)

\(\frac{5}{7}:x=\frac{1}{3}-\frac{4}{5}=-\frac{7}{15}\)

\(x=\frac{5}{7}:\left(-\frac{7}{15}\right)=-\frac{75}{49}\)

|\(\frac32x\) + \(\frac12\)| = |4\(x\) - 1|

\(\left[\begin{array}{l}\frac32x+\frac12=-4x+1\\ \frac32x+\frac12=4x-1\end{array}\right.\)

\(\left[\begin{array}{l}\frac32x+4x=1-\frac12\\ \frac32x-4x=-1-\frac12\end{array}\right.\)

\(\left[\begin{array}{l}\frac{11}{2}x=\frac12\\ -\frac52x=-\frac32\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12:\frac{11}{2}\\ x=-\frac32:\frac{-5}{2}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12\times\frac{2}{11}\\ x=-\frac32\times\frac{-2}{5}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{1}{11}\\ x=\frac35\end{array}\right.\)

Vậy \(x\in\) {\(\frac{1}{11};\frac35\)}

|\(\frac54x\) - \(\frac72\)| - |\(\frac58x\) + \(\frac35\)| = 0

|\(\frac54x\) - \(\frac72\)| = |\(\frac58x\) + \(\frac35\)|

\(\left[\begin{array}{l}\frac54x-\frac72=-\frac58x-\frac35\\ \frac54x-\frac72=\frac58x+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac54x+\frac58x=\frac72-\frac35\\ \frac54x-\frac58x=\frac72+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac{15}{8}x=\frac{29}{20}\\ \frac58x=\frac{41}{10}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{29}{10}:\frac{15}{8}\\ x=\frac{41}{10}:\frac58\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{116}{75}\\ x=\frac{164}{25}\end{array}\right.\)

Vậy \(x\in\) {\(\frac{116}{75}\); \(\frac{164}{25}\)}

a) \(\frac{9}{20}\)                                                   c) \(\frac{-55}{4}\)                                                                                                                                 

b) \(\frac{116}{75}\)                                                d) \(\frac{-76}{45}\)

đúng hết đấy nhé mình tính kĩ lắm ko sai đâu

       chúc may mắn

a)\(\frac{3}{4}+\frac{1}{4}:x=-3\)

                \(\frac{1}{4}:x=-3-\frac{3}{4}\)

                 \(\frac{1}{4}:x=\frac{-15}{4}\)

                        \(x=\frac{1}{4}:\frac{-15}{4}\)

                        \(x=\frac{-1}{15}\)

b)         \(\frac{-5}{x}=\frac{20}{28}\)

 \(\Rightarrow\)\(-5:x=\frac{20}{28}\)

                   \(x=-5:\frac{20}{28}\)

                   \(x=-7\)

c)\(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)

   \(\frac{2}{3}x\)          \(=\frac{1}{10}+\frac{1}{2}\)

   \(\frac{2}{3}x\)          \(=\frac{6}{10}\)

        \(x\)          \(=\frac{6}{10}:\frac{2}{3}\)

        \(x\)          \(=\frac{9}{10}\)

d)\(1\frac{2}{9}x+\frac{8}{3}=\frac{-2}{3}\)

   \(1\frac{2}{9}x\)        \(=\frac{-2}{3}-\frac{8}{3}\)

   \(1\frac{2}{9}x\)        \(=\frac{-10}{3}\)

           \(x\)        \(=\frac{-10}{3}:1\frac{2}{9}\)

           \(x\)        \(=\frac{-30}{11}\)

Câu Cuối)\(\frac{x}{2}-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)

\(\Rightarrow\)     \(x:2-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)

              \(x:2-\frac{11}{5}=\frac{448}{392}\)

              \(x:2\)           \(=\frac{448}{392}+\frac{11}{5}\)

              \(x:2\)           \(=\frac{117}{35}\)

              \(x\)               \(=\frac{117}{35}.2\)

              \(x\)               \(=\frac{234}{35}\)

Bạn cho mình 1 .

Chúc bạn học tốt .

đếch giúp!ai bảo câu hỏi của ngọc trả lời ko tử tế cơ!thằng nào ngu như mày thì thằng đó chết nhe răng giống mày!