Tìm x , biết

a) x . \(3\frac{1}{4}\)+( \(-\frac{7}{6}\)) .x - \(1\frac{2}{3}\)= \(\frac{5}{12}\)

b) \(5\frac{8}{17}\): x + (\(-\frac{4}{17}\)) : x + \(3\frac{1}{7}\):\(17\frac{1}{3}\)= \(\frac{4}{11}\)

(Trình bày cách tìm x ra :>)

1)Cho A=\(\frac{196}{197}\)+\(\frac{197}{198}\)

B=\(\frac{196+197}{197+198}\)

So sánh A và B

2)Cho B=\(\frac{1}{4}\)+\(\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+...+\frac{1}{19}\).Chứng minh B>1

3)Tính nhanh

\(\frac{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{11}}\)

Bài 1:Tìm \(x\in Z\)biết

\(A=\frac{3}{x-1}\)\(B=\frac{x-2}{x+3}\)\(C=\frac{2x+1}{x-3}\)

Bài 2:Chứng tỏ rằng:

\(A=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{63}>2\)\(B=\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+\frac{1}{5^2}+\frac{1}{6^2}+\frac{1}{7^2}+\frac{1}{8^2}< 1\)

Bài 3:Tính hợp lí

\(A=\frac{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{11}}\)

\(B=\frac{7}{4}\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)

bài 1

a,\(\frac{x}{5}\)=\(\frac{2}{3}\)

b,\(\frac{x}{3}\)-\(\frac{1}{2}\)=\(\frac{1}{5}\)

c,\(\frac{x}{5}\)+\(\frac{1}{2}\)=\(\frac{6}{10}\)

d,\(\frac{x+3}{15}\)=\(\frac{1}{3}\)

e,\(\frac{x-12}{4}\)=\(\frac{1}{2}\)

h,\(\frac{4}{5}\)+x=\(\frac{2}{3}\)

i,\(\frac{3}{4}\)-x=\(\frac{1}{3}\)

k,\(\frac{-5}{6}\)-x=\(\frac{2}{3}\)

l,x-\(\frac{5}{9}\)=\(\frac{-2}{3}\)

m,\(\frac{1}{2}\)x+\(\frac{1}{2}\)=\(\frac{5}{2}\)

n,\(\frac{-2}{3}\)-\(\frac{1}{3}\)(2x-5)=\(\frac{3}{2}\)

p,(3x-1)(\(-\frac{1}{2}\)x+5)=0

q,\(3\frac{1}{3}\)+\(\frac{5}{6}\)x=\(3\frac{1}{2}\)

s,\(\frac{1}{2}\)-\(\frac{2}{3}\)x=\(\frac{7}{12}\)

t,\(\frac{3}{4}\)x+\(\frac{1}{5}\)=\(\frac{1}{6}\)

u,\(\frac{3}{8}\)-\(\frac{1}{6}\)x=\(\frac{1}{4}\)

mn ơi'-' xin hãy giúp mk với ạ>^<,mk cần rất gấp,mai nộp r ạ,mong mn giúp mk với ạ:(( huhuhu r mk tik cho:<<

+) A = ( 1,11 + 0,19 - 2,6 ) : ( 2,06 + 0,54 ) - ( \(\frac{1}{2}\) + \(\frac{1}{3}\) ) : 2

+) Tìm x :

a, (1,16 - x ) . 2,25 / 10 \(\frac{5}{9}\) - 7\(\frac{1}{4}\) . 2\(\frac{2}{11}\) = 75%

b) x + 25% .x = -1,25

c) x - 75% x = \(\frac{1}{4}\)

+) Tính nhanh nếu có thể :

a) 1\(\frac{1}{2}\) - 3\(\frac{3}{4}\) b) -8\(\frac{1}{6}\) - 7\(\frac{3}{2}\) c) 0,15 - 4,8 + 1,3 d) ( 2\(\frac{1}{3}\) + 3,5 ) : (-4\(\frac{1}{6}\) + 3\(\frac{1}{7}\) ) + 7,5

e) 11\(\frac{1}{4}\) + (2\(\frac{5}{7}\) + 5\(\frac{1}{4}\) ) f) \(\frac{4}{9}\) : ( \(\frac{1}{-7}\) + 6\(\frac{5}{9}\) :(-\(\frac{1}{7}\))

a,{3849-2.[146-(2.14+6:2)]}.32

b,134-2.{156-6[54-2.(9+6)]}

c,\(\frac{5}{7}\).\(\frac{12}{11}\)+\(\frac{5}{7}\).\(\frac{17}{11}\)-\(\frac{5}{7}\).\(\frac{18}{11}\)+2\(\frac{1}{3}\)

d,\(\frac{2}{3}\)+\(\frac{3}{5}\)+\(\frac{5}{3}\)-\(\frac{1}{5}\)+1

e,\(\frac{1}{6}\)+\(\frac{1}{12}\)+\(\frac{1}{20}\)+\(\frac{1}{30}\)+\(\frac{1}{42}\)+\(\frac{1}{56}\)+\(\frac{1}{72}\)(Lưu ý chỉ phân số \(\frac{1}{72}\)mới có thể quy đồng)

a) \(Cho\)\(S=\frac{1}{31}+\frac{1}{32}+\frac{1}{33}+.....+\frac{1}{60}\)

\(Chứng\) \(minh\) \(\frac{3}{5}< S< \frac{4}{5}\)

b) \(Chứng\)\(minh\)\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+.....+\frac{1}{100}>\frac{7}{10}\)

c) \(Chứng\)\(minh\)\(\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}\) không là số tự nhiên

d) \(Chứng\)\(minh\)\(\frac{1}{5}< D< \frac{1}{10}\) \(với\)\(D=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}.....\frac{99}{100}\)

Tìm x biết:   \(\frac{3}{2x+1}\)+ \(\frac{10}{4x+2}\)- \(\frac{6}{6x+3}\)=\(\frac{12}{26}\)

Chứng minh rằng:      \(\frac{1}{5^2}\)+ \(\frac{1}{6^2}\)+...+ \(\frac{1}{2007^2}\)> \(\frac{1}{5}\)

rút gọn:  M = ( 1+\(\frac{1}{3}\)+ \(\frac{1}{5}\)+ ... + \(\frac{1}{999}\)) : (\(\frac{1}{1.999}\)+ \(\frac{1}{3.997}\)+...+\(\frac{1}{997.3}\)+\(\frac{1}{999.1}\))

Giúp mình nha!!!