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Chữ số hàng phần chục nghìn là 5 nên làm tròn chữ số trước đó lên 1 đơn vị và toàn bộ các chữ số còn lại ở bên phải đều trở thành số 0

\(5^{\left(x-1\right)\left(x+2\right)}=2024^0\\ =>5^{\left(x-1\right)\left(x+2\right)}=1\\ =>5^{\left(x-1\right)\left(x+2\right)}=5^0\\ =>\left(x-1\right)\left(x+2\right)=0\\ TH1:x-1=0\\ =>x=1\\ TH2:x+2=0\\ =>x=-2\)

Vậy: ... 

Ta có: 

\(5y=7z+5z=-30\\ =>5y=12z=-30\\ =>\left\{{}\begin{matrix}5y=-30\\12z=-30\end{matrix}\right.\\ =>\left\{{}\begin{matrix}y=-\dfrac{30}{5}=-6\\z=-\dfrac{30}{12}=-\dfrac{5}{2}\end{matrix}\right.\)  

\(2x=3y=3\cdot\left(-6\right)=-18\\ =>x=\dfrac{-18}{2}=-9\)

Vậy: ... 

1,5 = 30/20 = 60/40 = 90/60

cảm ơn

1 That man is so tall that he can almost touch the ceiling

2 The coffee is so strong that I can't go to sleep

3 My mother was so busy that she couldn't do the housework

4 The shirt is so small that I can't wear it

5 My house is so large that it can hold 100 people

6 She told such interesting stories that they all like her

7 I have such a difficult exercise that I couldn't do it

8 They pictures are so beautiful that everybody will want one

9 Day is so hot that we decided to stay indoors

10 The speaker gave such a long talk that most of the audience felt sleepy

1. That man is so tall that he can almost touch the ceiling
2. The coffee is so strong that I can't go to sleep
3. My mother was so busy that she couldn't do the housework
4. The shirt is so small that I can't wear it.
5. My house is so large that It can hold 100 people.

Ta có:

\(\left|x-5\right|+\left|2-4x\right|=\left|x-5\right|+\left|\dfrac{1}{2}-x\right|+3\left|\dfrac{1}{2}-x\right|\)

Mà \(\left|x-5\right|+\left|\dfrac{1}{2}-x\right|\ge\left|x-5+\dfrac{1}{2}-x\right|=\dfrac{9}{2}>4\)

\(\Rightarrow\left|x-5\right|+\left|2-4x\right|\ge4+3\left|\dfrac{1}{2}-x\right|>4>3\)

Vậy pt đã cho vô nghiệm

a: Trên cùng một nửa mặt phẳng bờ chứa tia Ox, ta có: \(\widehat{xOt}< \widehat{xOy}\left(50^0< 100^0\right)\)

nên tia Ot nằm giữa hai tia Ox và Oy

=>\(\widehat{xOt}+\widehat{tOy}=\widehat{xOy}\)

=>\(\widehat{tOy}=100^0-50^0=50^0\)

b: 

Vì tia Ot nằm giữa hai tia Ox và Oy

và \(\widehat{xOt}=\widehat{yOt}\left(=50^0\right)\)

nên Ot là phân giác của góc xOy