tìm x ko âm bt
\(\sqrt{x}=1-\sqrt{3}\)
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\(\left(a+1\right)\left(a+2\right)\left(a+3\right)\left(a+4\right)+1\\ =\left[\left(a+1\right)\left(a+4\right)\right]\left[\left(a+2\right)\left(a+3\right)\right]+1\\ =\left(a^2+5a+4\right)\left(a^2+5a+6\right)+1\\ =\left(a^2+5a+4\right)\left(a^2+5a+4\right)+2\left(a^2+5a+4\right)+1\\ \left(a^2+5a+4\right)^2+2\left(a^2+5a+4\right)+1\\ =\left(a^2+5a+5\right)^2\)
It was a long time before we came _____to_____ the truth.
(come to: đạt được, phát hiện ra điều gì đó)
The dog came _____at_____ us with teeth bared.
(come at: tiếp cận với thái độ hung hăng hoặc thù địch)
Come _____on_____ ! We are late for the bus.
(come on: đây là lời thúc giục di chuyển: nhanh lên)
How is your English coming ____along______ ?
(come along: phát triển, tiến đến)
I was picking up the teapot when it came __apart________ in my hands.
(come apart: rơi ra, tách ra, rời rạc)
She has been very ill, but now she is coming ___round_______ fine.
(com round: hồi phục, khôi phục)
We must not let this silly quarrel come ___between_______ us.
(come between: gây cản trở, tạo ra rào cản)
I come _____from_____ Liverpool, but I have spent most of my life in Scotland.
(come from: đến từ)
John has come __into________ the money; he inherited £5,000.
(come into: thừa kế)
The town came _____into_____ sight when we turned the bend.
(come into: xuất hiện)
The hook came ____off______ the wall when I hung up my coat
(come off: bong ra, rời ra)
This tool will come ____in______ very handy for my uncle.
(come in handy: có ích)
Snails come ____out______ as soon as it rains.
(come out: xuất hiện)
When did you first come ____over______ to Europe?
(come over: di chuyển)
Your talk came ______to____ very well.
(come to: kết quả là, dẫn đến)
It has come _____to_____ my attention that he is very short-tempered.
He came ______to____ the conclusion that someone was having an affair with his wife.
He came _______up___ and asked me if I had the time.
(come up: xảy ra, xuất hiện)
Much of the tea consumed in England comes __from________ Sri Lanka.
(come from: đến từ)
He comes ____from______ an interesting family.
How’s your orchard coming _____along_____ ?
Sometimes it’s very difficult to come ___to_______ the truth.
He never lets anything come ______between____ him and his morning paper.
It was a long time before we came ___to_______ the truth.
The dog came _____at_____ us with teeth bared.
Come ____on______ ! We are late for the bus.
How is your English coming ____along______ ?
I was picking up the teapot when it came ______âpart____ in my hands.
She has been very ill, but now she is coming ______round____ fine.
We must not let this silly quarrel come ____between______ us.
I come ______from____ Liverpool, but I have spent most of my life in Scotland.
John has come _____into_____ the money; he inherited £5,000.
The town came ______into____ sight when we turned the bend.
a) $-(2x-4)(x+2)+(x+2)^2+(x-2)^2-4x^2-1-4x=-3$
$\Leftrightarrow (x-2)^2-2(x-2)(x+2)+(x+2)^2-4x^2-4x+2=0$
$\Leftrightarrow (x-2+x+2)^2-4x^2-4x+2=0$
$\Leftrightarrow (2x)^2-4x^2-4x=-2$
$\Leftrightarrow -4x=-2$
$\Leftrightarrow x=\frac12$
b) $(4x-1)^2-16(x+1)(x+3)=25$
$\Leftrightarrow (4x)^2-2.4x.1+1^2-16(x^2+4x+3)=25$
$\Leftrightarrow 16x^2-8x+1-16x^2-64x-48=25$
$\Leftrightarrow -72x-47=25$
$\Leftrightarrow -72x=72$
$\Leftrightarrow x=-1$
c) $(3x-7)^2=9(3x-7)(x+5)+694$
$\Leftrightarrow (3x)^2-2.3x.7+7^2=9(3x^2+8x-35)+694$
$\Leftrightarrow 9x^2-42x+49=27x^2+72x-315+694$
$\Leftrightarrow 18x^2+114x+330=0$
$\Leftrightarrow 9x^2+57x+165=0$
$\Leftrightarrow 9\left(x+\frac{19}{6}\right)^2+\frac{299}{4}=0$ (vô lí)
=> Pt vô nghiệm
d) $(2x-1)^2+(x+3)^2=5(x+7)(x-7)-3x$
$\Leftrightarrow 4x^2-4x+1+x^2+6x+9=5(x^2-49)-3x$
$\Leftrightarrow 5x^2+2x+10=5x^2-3x-245$
$\Leftrightarrow 5x=-255$
$\Leftrightarrow x=-51$
#$\mathtt{Toru}$
a: \(-\left(2x-4\right)\left(x+2\right)+\left(x+2\right)^2+\left(x-2\right)^2-4x^2-1-4x=-3\)
=>\(-2\left(x^2-4\right)+x^2+4x+4+x^2-4x+4-4x^2-1-4x=-3\)
=>\(-2x^2+8-2x^2-4x+7+3=0\)
=>\(-4x^2-4x+18=0\)
=>\(x=\dfrac{-1\pm\sqrt{19}}{2}\)
b: \(\left(4x-1\right)^2-16\left(x+1\right)\left(x+3\right)=25\)
=>\(16x^2-8x+1-16\left(x^2+4x+3\right)-25=0\)
=>\(16x^2-8x-24-16x^2-64x-48=0\)
=>-72x-72=0
=>x=-1
c: \(\left(3x-7\right)^2=9\left(3x-7\right)\left(x+5\right)+694\)
=>\(9\left(3x^2+15x-7x-35\right)+694=9x^2-42x+49\)
=>\(27x^2+72x-315+694-9x^2+42x-49=0\)
=>\(18x^2+114x+330=0\)
=>\(x\in\varnothing\)
d: \(\left(2x-1\right)^2+\left(x+3\right)^2=5\left(x+7\right)\left(x-7\right)-3x\)
=>\(4x^2-4x+1+x^2+6x+9=5\left(x^2-49\right)-3x\)
=>\(5x^2+2x+10-5x^2+245+3x=0\)
=>5x+255=0
=>x+51=0
=>x=-51
Bài 7
1)
\(A=8\left(3^2+1\right)\left(3^4+1\right)...\left(3^{16}+1\right)\\ =\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)....\left(3^{16}+1\right)\\ =\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\\ =\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\\ =\left(3^{16}-1\right)\left(3^{16}+1\right)\\ =3^{32}-1\)
2)
\(B=\left(1-3\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{16}+1\right)\\ =-\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{16}+1\right)\\ =-\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{16}+1\right)\\ =-\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\\ =-\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\\ =-\left(3^{16}-1\right)\left(3^{16}+1\right)\\ =-\left(3^{32}-1\right)\\ =1-3^{32}\)
When I have free time, I usually read books. Except school time, books live with me for almost the rest of the day. There are some reasons why I love reading. The first reason is that it helps widen knowledge. I can access a wide range of knowledge such as literature, science, biology, … Next, I can reduce stress by reading funny stories. I have collected many comic books since I was 6. Moreover, it can give me an unlimited imagination, so I can write books in the future. I can learn the different cultures and customs of other countries in the world too. I read books at least one hour every day. I wish I could read all kinds of books over the world.
a: Ta có: \(AK=KB=\dfrac{AB}{2}\)
\(DI=IC=\dfrac{DC}{2}\)
mà AB=CD
nên AK=KB=DI=IC
Xét tứ giác AKCI có
AK//CI
AK=CI
Do đó: AKCI là hình bình hành
=>AI//CK và AI=CK
b: Xét ΔDNC có
I là trung điểm của DC
IM//NC
Do đó: M là trung điểm của DN
=>DM=MN
Xét ΔBAM có
K là trung điểm của BA
KN//AM
Do đó: N là trung điểm của BM
=>BN=NM
=>BN=NM=DM
c: Xét tứ giác BKDI có
BK//DI
BK=DI
Do đó: BKDI là hình bình hành
=>DK//BI
=>EK//FI
ta có: AI//CK
=>IE//KF
Xét tứ giác EKFI có
EK//FI
EI//KF
Do đó: EKFI là hình bình hành
\(\sqrt{x}=1-\sqrt{3}\)
Nhận xét:
\(\sqrt{3}>\sqrt{1}=1\)
\(\Rightarrow1-\sqrt{3}< 0\)
\(\Rightarrow\sqrt{x}< 0\) (vô lí)
Vậy không tìm được giá trị x thoả mãn đề bài