sung sướng nhé

A.Sung sướng là đáp án đúng

Toại nguyện đồng nghĩa với mãn nguyện, viên mãn

Phúc hậu là nhân hậu, hiền từ

Giàu có đồng nghĩa với Phú Quý, Giàu sang

`B=\frac{7}{40}+\frac{7}{88}+\frac{7}{154}+\frac{7}{238}+\frac{7}{340}`

`=\frac{7}{5.8}+\frac{7}{8.11}+\frac{7}{11.14}+\frac{7}{14.17}+\frac{7}{17.20}`

`=\frac{7}{3} . \left ( \frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}+\frac{3}{17.20} \right )`

`=\frac{7}{3}. \left ( \frac15-\frac18+\frac18-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+\frac{1}{17}-\frac{1}{20} \right )`

`=\frac{7}{3} .\left( \frac15-\frac{1}{20} \right )`

`=\frac{7}{3} .\frac{3}{20}=\frac{7}{20}`

Hình vẽ đâu vậy bạn?

12 số

@kurumicute mik cam on!

Tìm các số tự nhiên thỏa mãn số đó không vượt quá 10 nhưng lớn hơn 0.

a) \(S_{EAG}=\dfrac{1}{2}\times AG\times ED=\dfrac{1}{2}\times2\times3=3\left(cm^2\right)\)

\(S_{PBC}=\dfrac{1}{2}\times BC\times DC=\dfrac{1}{2}\times5\times5=12,5\left(cm^2\right)\)

b) Ta có:

\(S_{EBC}=\dfrac{1}{2}\times BC\times EC=\dfrac{1}{2}\times5\times8=20\left(cm^2\right)\)

\(S_{PEC}=S_{ECB}-S_{PBC}=20-12,5=7,5\left(cm^2\right)\)

Vậy nên:

\(PD=\dfrac{2\times S_{PEC}}{EC}=\dfrac{2\times7,5}{8}=1,875\left(cm\right)\)

c) Ta thấy:

\(\dfrac{IM}{IP}=\dfrac{S_{MIG}}{S_{IPG}}=\dfrac{S_{MIE}}{S_{IPE}}\) nên \(\dfrac{IM}{IP}=\dfrac{S_{MGE}}{S_{GPE}}=\dfrac{\dfrac{1}{2}\times MG\times3}{\dfrac{1}{2}\times GP\times3}=\dfrac{MG}{GP}\)

Kéo dài AD cắt EF tại K.

Ta có \(S_{AKM}=\dfrac{1}{2}\times3\times2=3\left(cm^2\right)\)

nên \(S_{EKM}=S_{AKE}-S_{AKM}=\dfrac{1}{2}\times3\times5-3=4,5\left(cm^2\right)\)

Vậy \(FM=\dfrac{2\times S_{EKM}}{KE}=1,8\left(cm\right)\)

Thế thì \(MG=3-1,8=1,2\left(cm\right)\)

Lại có \(GP=3-1,875=1,125\left(cm\right)\)

Vậy nên:

\(\dfrac{IM}{IP}=\dfrac{MG}{GP}=\dfrac{1,2}{1,125}=\dfrac{16}{15}\).

Tttt

Ggghghnkhg

a: ABCD là hình vuông

=>AB=BC=CD=DA=5cm

DEFG là hình vuông

=>DE=EF=FG=GD=3cm

Ta có: DG+GA=DA

=>GA=DA-DG=5-3=2(cm)

Diện tích tam giác EAG là:

\(S_{EGA}=\frac12\times ED\times GA=\frac12\times3\times2=3\left(\operatorname{cm}^2\right)\)

Vì GD//BC

nên \(\frac{EP}{PB}=\frac{ED}{DC}=\frac35\)

=>\(\frac{BP}{BE}=\frac58\)

CE=CD+DE=5+3=8(cm)

ΔBCE vuông tại C

=>\(S_{BCE}=\frac12\times BC\times CE=\frac12\times5\times8=5\times4=20\left(\operatorname{cm}^2\right)\)

Vì \(BP=\frac58\times BE\)

nên \(S_{BPC}=\frac58\times S_{BCE}=20\times\frac58=\frac{100}{8}=12,5\left(\operatorname{cm}^2\right)\)

b: Ta có: \(S_{BPC}+S_{EPC}=S_{BCE}\)

=>\(S_{EPC}=20-12,5=7,5\left(\operatorname{cm}^2\right)\)

=>\(\frac12\times PD\times EC=7,5\)

=>\(\frac12\times8\times PD=7,5\)

=>PD=7,5:4=15/8(cm)

c: Vì M,I,P thẳng hàng

nên \(\frac{S_{GMI}}{S_{GPI}}=\frac{IM}{IP};\frac{S_{EMI}}{S_{EPI}}=\frac{IM}{IP}\)

Do đó: \(\frac{IM}{IP}=\frac{S_{GMI}+S_{EMI}}{S_{GIP}+S_{EIP}}=\frac{S_{GME}}{S_{GPE}}=\frac{\frac12\cdot FE\cdot MG}{\frac12\cdot ED\cdot GP}=\frac{MG}{GP}\)

Vì MG//ED

nên \(\frac{MG}{ED}=\frac{AG}{AD}\)

=>\(\frac{MG}{3}=\frac25\)

=>\(MG=2\times\frac35=1,2\left(\operatorname{cm}\right)\)

Ta có: GP+PD=GD

=>GP=GD-PD=3-15/8=9/8=1,125(cm)

Do đó: \(\frac{IM}{IP}=\frac{GM}{GP}=\frac{1.2}{1.125}=\frac{16}{15}\)

a: 11+13+15+17+19

=(11+19)+(13+17)+15

=30+30+15

=75

b: \(122+2116+278+84\)

=(122+278)+(2116+84)

=400+2200

=2600

c: \(12\times125\times54\)

=1500x54

=81000

d: \(27\times36+27\times64=27\times\left(36+64\right)=27\times100=2700\)

e: \(25\text{x}37+25\text{x}63-150\)

=25x(37+63)-150

=25x100-150

=2500-150

=2350

f: \(425\text{x}74-27\text{x}425-1\)

=425x(74-27-1)

=425x46=19550

g: \(8\text{x}9\text{x}14+6\text{x}17\text{x}12+19\text{x}4\text{x}18\)

=14x72+17x72+19x72

=72x(14+17+19)

=50x72=3600

a) $11+13+15+17+19$

$=(11+19)+(13+17)+15$

$=30+30+15$

$=60+15=75$

b) $122+2116+278+84$

$=(122+278)+(2116+84)$

$=400+2200=2600$

c) $12\times125\times54$

$=3\times4\times125\times2\times27$

$=(4\times2)\times125\times(3\times27)$

$=8\times125\times81$

$=1000\times81=81000$

d) $27\times36+27\times64$

$=27\times(36+64)$

$=27\times100=2700$

e) $25\times37+25\times63-150$

$=25\times(37+63)-150$

$=25\times100-150$

$=2500-150=2350$

f) $425\times74-27\times425-425$

$=425\times(74-27-1)$

$=425\times(47-1)$

$=425\times46=19550$

g) $8\times9\times14+6\times17\times12+19\times4\times18$

$=(8\times9)\times14+(6\times12)\times17+(4\times18)\times19$

$=72\times14+72\times17+72\times19$

$=72\times(14+17+19)$

$=72\times(31+19)$

$=72\times50=3600$

$\mathtt{Toru}$

1 cach:

3+2+1+3+1

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