\(\dfrac{4}{7}+\dfrac{3}{4}+\dfrac{2}{7}\\ =\dfrac{6}{7}+\dfrac{3}{4}\\ =\dfrac{24}{28}+\dfrac{21}{28}=\dfrac{45}{28}\\ ------------\\ \dfrac{1}{6}+\dfrac{5}{24}+\dfrac{2}{3}\\ =\dfrac{4}{24}+\dfrac{5}{24}+\dfrac{16}{24}=\dfrac{25}{24}\\ ---------\\ \dfrac{1}{2}+\dfrac{5}{16}-\dfrac{1}{4}\\ =\dfrac{8}{16}+\dfrac{5}{16}-\dfrac{4}{16}=\dfrac{9}{16}\)

\(----------\\ 1-\left(\dfrac{1}{5}+\dfrac{1}{2}\right)\\ =\dfrac{10}{10}-\dfrac{2}{10}-\dfrac{5}{10}=\dfrac{3}{10}\\ ---------\\ \dfrac{2}{3}+\dfrac{1}{2}-\dfrac{5}{6}\\ =\dfrac{4}{6}+\dfrac{3}{6}-\dfrac{5}{6}=\dfrac{2}{6}=\dfrac{1.}{3}\\ --------\\ \dfrac{5}{12}+\dfrac{5}{6}-\dfrac{3}{4}\\ =\dfrac{5}{12}+\dfrac{10}{12}-\dfrac{9}{12}=\dfrac{6}{12}=\dfrac{1}{2}\\ ---------\)

\(\dfrac{7}{5}-\dfrac{4}{15}-\dfrac{2}{3}\\ =\dfrac{21}{15}-\dfrac{4}{15}-\dfrac{10}{15}=\dfrac{7}{15}\)

\(\dfrac{4}{7}+\dfrac{3}{4}+\dfrac{2}{7}=\left(\dfrac{4}{7}+\dfrac{2}{7}\right)+\dfrac{3}{4}=\dfrac{6}{7}+\dfrac{3}{4}=\dfrac{24}{28}+\dfrac{21}{28}=\dfrac{45}{28}\)

\(\dfrac{1}{6}+\dfrac{5}{24}+\dfrac{2}{3}=\dfrac{4}{24}+\dfrac{5}{24}+\dfrac{16}{24}=\dfrac{25}{24}\)

\(\dfrac{1}{2}+\dfrac{5}{16}-\dfrac{1}{4}=\dfrac{8}{16}+\dfrac{5}{16}-\dfrac{4}{16}=\dfrac{9}{16}\)

\(1-\left(\dfrac{1}{5}+\dfrac{1}{2}\right)=1-\left(\dfrac{2}{10}+\dfrac{5}{10}\right)=1-\dfrac{7}{10}=\dfrac{10}{10}-\dfrac{7}{10}=\dfrac{3}{10}\)

\(\dfrac{2}{3}+\dfrac{1}{2}-\dfrac{5}{6}=\dfrac{4}{6}+\dfrac{3}{6}-\dfrac{5}{6}=\dfrac{2}{6}=\dfrac{1}{3}\)

\(\dfrac{5}{12}+\dfrac{5}{6}-\dfrac{3}{4}=\dfrac{5}{12}+\dfrac{10}{12}-\dfrac{9}{12}=\dfrac{6}{12}=\dfrac{1}{2}\)

\(\dfrac{7}{5}-\dfrac{4}{15}-\dfrac{2}{3}=\dfrac{21}{15}-\dfrac{4}{15}-\dfrac{10}{15}=\dfrac{7}{15}\)

\(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\)

\(=\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}\)

\(=\dfrac{3+2+1}{6}\)

\(=\dfrac{6}{6}\)

\(=1\)

\(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}=\dfrac{5}{6}+\dfrac{1}{6}=1\)

Cách 1:

Tổng số kg giấy vụn và báo cũ lớp 4A thu gom được là:

   108 + 72 = 180 (kg)

Mỗi bạn thu gom được số kg là:

  180 : 36 = 5 (kg)

Cách 2:

Mỗi bạn thu gom được số kg giấy vụn là:

  108 : 36 = 3 (kg giấy vụn)

Mỗi bạn thu gom được số kg báo cũ là:

   72 : 36 = 2 (kg báo cũ)

Vậy mỗi bạn thu gom được số kg vừa báo cũ vừa giấy vụn là:

  3 + 2 = 5 (kg)

\(3-\dfrac{16}{11}=\dfrac{33}{11}-\dfrac{16}{11}\\ =\dfrac{33-16}{11}=\dfrac{17}{11}\)

.

\(\dfrac{9}{8}-1=\dfrac{9}{8}-\dfrac{8}{8}=\dfrac{9-8}{8}\\ =\dfrac{1}{8}\)

\(3-\dfrac{16}{11}=\dfrac{33-16}{11}=\dfrac{17}{11}\)

\(\dfrac{9}{8}-1=\dfrac{9-8}{8}=\dfrac{1}{8}\)

\(\dfrac{19}{5}-\dfrac{3}{15}\)

\(=\dfrac{19}{5}-\dfrac{1}{5}\)

\(=\dfrac{19-1}{5}\)

\(=\dfrac{18}{5}\)

19/5 - 3/15

= 57/15 - 3/15

= 54/15

= 18/5

a) \(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{3}{4}\right)\le x\le\dfrac{1}{24}-\left(\dfrac{1}{8}-\dfrac{1}{3}\right)\)

\(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{3}{4}\le x\le\dfrac{1}{24}-\dfrac{1}{8}+\dfrac{1}{3}\)

\(\dfrac{6}{12}-\dfrac{4}{12}-\dfrac{9}{12}\le x\le\dfrac{1}{24}-\dfrac{3}{24}+\dfrac{8}{24}\)

\(-\dfrac{7}{12}\le x\le\dfrac{6}{24}\)

\(-\dfrac{7}{12}\le x\le\dfrac{1}{4}\) 

Giá trị x nguyên thỏa mãn là: 0  

b) \(-\dfrac{1}{2}-\dfrac{3}{4}+\dfrac{1}{3}\le x\le\dfrac{5}{6}-\left(-\dfrac{3}{4}\right)+\dfrac{7}{12}\)

\(\dfrac{-6}{12}-\dfrac{9}{12}+\dfrac{4}{12}\le x\le\dfrac{5}{6}+\dfrac{3}{4}+\dfrac{7}{12}\)

\(-\dfrac{11}{12}\le x\le\dfrac{10}{12}+\dfrac{9}{12}+\dfrac{7}{12}\)

\(-\dfrac{11}{12}\le x\le\dfrac{26}{12}\)

\(-\dfrac{11}{12}\le x\le\dfrac{13}{6}\)

Các giá trị x nguyên thỏa mãn là: 0; 1; 2

a) Ta có : 

\(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{3}{4}\right)\le x\le\dfrac{1}{24}-\left(\dfrac{1}{8}-\dfrac{1}{3}\right)\)

\(\Leftrightarrow\dfrac{1}{2}-\dfrac{13}{12}\le x\le\dfrac{1}{24}-\dfrac{-5}{24}\)

\(\Leftrightarrow\dfrac{-7}{12}\le x\le\dfrac{1}{4}\)

mà \(x\in Z\)

\(\Rightarrow x=0\)

Vậy \(x=0\)

b) Ta có : 

\(\dfrac{-1}{2}-\dfrac{3}{4}+\dfrac{1}{3}\le x\le\dfrac{5}{6}-\left(\dfrac{-3}{4}\right)+\dfrac{7}{12}\)

\(\Leftrightarrow\dfrac{-6}{12}-\dfrac{9}{12}+\dfrac{4}{12}\le x\le\dfrac{5}{6}+\dfrac{3}{4}+\dfrac{7}{12}\)

\(\Leftrightarrow\dfrac{-11}{12}\le x\le\dfrac{10}{12}+\dfrac{9}{12}+\dfrac{7}{12}\)

\(\Leftrightarrow\dfrac{-11}{12}\le x\le\dfrac{26}{12}\)

\(\Leftrightarrow\dfrac{-11}{12}\le x\le\dfrac{13}{6}\)

mà \(x\in Z\)

\(\Rightarrow x\in\left\{0;1;2\right\}\)

Vậy \(x\in\left\{0;1;2\right\}\)

Số số hạng là: ( 2025 - 5 ) : 5 + 1 = 405

Tổng của dãy số trên là: ( 2025 + 5 ) x 405 : 2 = 411075

Đ/s : 411075

Công thức tính tổng dãy số cháu chưa học rất khó giải thích ah.

\(\dfrac{4}{18}-\dfrac{1}{9}\)

\(=\dfrac{4}{18}-\dfrac{2}{18}\)

\(=\dfrac{4-2}{18}\)

\(=\dfrac{2}{18}\)

\(=\dfrac{1}{9}\)

\(\dfrac{4}{18}-\dfrac{1}{9}\)

\(=\dfrac{2}{9}-\dfrac{1}{9}\)

\(=\dfrac{2-1}{9}\)

\(=\dfrac{1}{9}\)

\(\dfrac{9}{5}+\dfrac{5}{8}=\dfrac{72}{40}+\dfrac{25}{40}=\dfrac{97}{40}\)

\(\dfrac{3}{5}+\dfrac{13}{9}=\dfrac{27}{45}+\dfrac{65}{45}=\dfrac{82}{45}\)

\(\dfrac{2}{3}+\dfrac{11}{2}=\dfrac{4}{6}+\dfrac{33}{6}=\dfrac{37}{6}\)

\(\dfrac{9}{4}+\dfrac{17}{20}=\dfrac{45}{20}+\dfrac{17}{20}=\dfrac{62}{20}=\dfrac{31}{10}\)

\(\dfrac{43}{6}+\dfrac{45}{8}=\dfrac{172}{24}+\dfrac{135}{24}=\dfrac{307}{24}\)

\(\dfrac{5}{9}+\dfrac{7}{15}=\dfrac{25}{45}+\dfrac{21}{45}=\dfrac{46}{45}\)

\(\dfrac{9}{5}+\dfrac{5}{8}\\ =\dfrac{72}{40}+\dfrac{25}{40}\\ =\dfrac{97}{40}\\ ----------\\ \dfrac{3}{5}+\dfrac{13}{9}\\ =\dfrac{27}{45}+\dfrac{65}{45}\\ =\dfrac{92}{45}\\ --------\\ \dfrac{2}{3}+\dfrac{11}{2}\\ =\dfrac{4}{6}+\dfrac{33}{6}\\ =\dfrac{37}{6}\\ --------\\ \dfrac{9}{4}+\dfrac{17}{20}\\ =\dfrac{45}{20}+\dfrac{17}{20}\\ =\dfrac{62}{20}=\dfrac{31}{10}\\ ----------\\ \dfrac{43}{6}+\dfrac{45}{8}\\ =\dfrac{172}{24}+\dfrac{135}{24}\\ =\dfrac{307}{24}\)

\(-----------\\ \dfrac{5}{9}+\dfrac{7}{15}\\ =\dfrac{25}{45}+\dfrac{21}{45}\\ =\dfrac{46}{45}\)

\(\dfrac{8}{3}+\dfrac{10}{7}=\dfrac{56}{21}+\dfrac{30}{21}\\ =\dfrac{56+30}{21}=\dfrac{86}{21}\)

\(\dfrac{8}{3}+\dfrac{10}{7}\)

\(=\dfrac{56}{21}+\dfrac{30}{21}\)

\(=\dfrac{56+30}{21}\)

\(=\dfrac{86}{21}\)