a) 11/12 + 5/6 x 3/2 - 2/3 

= 11/12 + 15/12 - 2/3

= 26/12 - 2/3

= 26/12 - 8/12

= 18 /12 = 3/2

b) 4/9 : 4/6 x 3/4 +5/3 

= 4/9 x 6/4 x 3/4 + 5/3

= 2/3 x 3/4 + 5/3 

= 6/12 + 5/3 

= 6/12 + 20/12

= 26/12 = 13/6

c) 5/7 : 11/14 : 15/22 x 3/5 

= 5/7 x 14/11 x 22/15 x 3/5 

= 10/11 x 22/15 x 3/5 

= 4/3 x 3/5 = 20/15 = 4/3

a. \(\dfrac{11}{12}+\dfrac{5}{6}\)x\(\dfrac{3}{2}-\dfrac{2}{3}\) \(=\)\(\dfrac{11}{12}+\dfrac{5}{4}-\dfrac{2}{3}=\dfrac{11}{12}+\dfrac{15}{12}-\dfrac{8}{12}=\dfrac{11+15-8}{12}=\dfrac{18}{12}=\dfrac{3}{2}\)

b. \(\dfrac{4}{9}:\dfrac{4}{6}\)x\(\dfrac{3}{4}+\dfrac{5}{3}\)  \(=\dfrac{4}{9}:\dfrac{1}{2}+\dfrac{5}{3}=\dfrac{8}{9}+\dfrac{5}{3}=\dfrac{8}{9}+\dfrac{15}{9}=\dfrac{8+15}{9}=\dfrac{23}{9}\)

c. \(\dfrac{5}{7}:\dfrac{11}{14}:\dfrac{15}{22}\)x\(\dfrac{3}{5}\) \(=\dfrac{10}{14}:\) \(\dfrac{11}{14}:\dfrac{15}{22}\)x\(\dfrac{3}{5}\) \(=\dfrac{10}{11}\)\(:\dfrac{15}{22}\)x\(\dfrac{3}{5}\) \(=\dfrac{20}{22}:\dfrac{15}{22}\)x\(\dfrac{3}{5}\) \(=\dfrac{4}{3}\)x\(\dfrac{3}{5}=\dfrac{4}{5}\)

5/6x3/5=1/2

5/6 x 3/5

=15/30=3/7

7

\(\dfrac{5}{6}\times3+\dfrac{20}{6}\times2-1:\dfrac{6}{5}\)
\(=\dfrac{5}{6}\times3-\dfrac{5}{6}+\dfrac{20}{6}\times2\)
\(=\dfrac{5}{6}\times\left(3-1\right)+\dfrac{20}{6}\times2\)
\(=\dfrac{5}{6}\times2+\dfrac{20}{6}\times2\)
\(=\left(\dfrac{5}{6}+\dfrac{20}{6}\right)\times2\)
\(=\dfrac{25}{6}\times2\)
\(=\dfrac{25}{3}\)

#DatNe

\(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{20}{6}\) \(\times\) 2 - 1 : \(\dfrac{6}{5}\)

= \(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{20}{6}\) \(\times\) 2 - \(\dfrac{5}{6}\)

= \(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{5}{6}\) \(\times\) 8 - \(\dfrac{5}{6}\) \(\times\)1

= \(\dfrac{5}{6}\) \(\times\) ( 3 + 8 - 1)

= \(\dfrac{5}{6}\) \(\times\)10

= \(\dfrac{25}{3}\)

B.6x3-12x2+3x

chac zay

4/6x1/5+4/6x3/5+2/6x4/5

=4/6.(1/5+3/5)+2/6.4/5

=4/6.4/5+2/6.4/5

=4/5.(4/6+2/6)

=4/5.6/6

=4/5.1 = 4/5

\(=12x^3-10x+18x^2-15\)

\(\left(6x^3-7x^2-x+2\right):\left(2x+1\right)\\ =\left[\left(6x^3-6x^2\right)-\left(x^2-x\right)-\left(2x-2\right)\right]:\left(2x+1\right)\\ =\left[\left(x-1\right)\left(6x^2-x-2\right)\right]:\left(2x+1\right)\\ =\left\{\left(x-1\right)\left[\left(6x^2+3x\right)-\left(4x+2\right)\right]\right\}:\left(2x+1\right)\\ =\left[\left(x-1\right)\left(3x-2\right)\left(2x+1\right)\right]:\left(2x+1\right)\\ =\left(x-1\right)\left(3x-2\right)\)

câu 1 bạn lm rõ hơn đc ko ạ

Trl:

3 x 9 + 6 x 3 + 5 : 2 - 6 + 9 x 3 - 2

= 27 + 18 + 2,5 - 6 + 27 - 2

= 66,5

#HuyềnAnh#

Trl :

    3 x 9 + 6 x 3 + 5 : 2 - 6 + 9 x 3 - 2

= 27 + 18 + 2,5 -  6 + 27 - 2

= 45 + 2,5 - 6 + 27 - 2 

= 66,5

_ Jie _

\(P\left(x\right)=5^6-6.5^5+6.5^4-6.5^3+6.5^2-6.5+1=5^6-6\left(5^5-5^4-5^3-5^2-5\right)+1=1556\)

mình quên là k dùng máy tính bỏ túi nha

a) ( x 2  – 4x + 1)( x 2  – 2x + 3).

b) ( x 2  + 5x – 1)( x 2  + x – 1).