a) 140

b) 1,4

`a,182:1,3`

`=182×10:13`

`=182:13×10`

`=14×10=140`

`b,18,2:13`

`=182:13:10=14:10=1,4`

Đặt \(x=\sqrt[3]{182+\sqrt[]{33125}}+\sqrt[3]{182-\sqrt[]{33125}}\)

\(\Rightarrow x^3=364+3\sqrt[3]{182^2-33125}.\left(\sqrt[3]{182+\sqrt[]{33125}}+\sqrt[]{182-\sqrt[]{33125}}\right)\)

\(\Rightarrow x^3=364+3.\left(-1\right).x\)

\(\Rightarrow x^3+3x-364=0\)

\(\Rightarrow\left(x-7\right)\left(x^2+7x+52\right)=0\)

\(\Rightarrow x-7=0\) (do \(x^2+7x+52>0;\forall x\))

\(\Rightarrow x=7\)

nỏ biết

Ai giúp mk đi😂😂😂😂

182 x 29 + 182 x 45 - 182 x 4 + 182 x 30

= 182 x ( 29 + 45 - 4 + 30 )

= 182 x 100

= 18200

nếu mk đúng mk nhé thanks mn nhìu ạ kb đi

 = 182 x (29+45-4+30)

 = 182 x 100 = 18200

k mk nha

    /-28/ + (129 - 182 + 99) - (129 + 199 - 182)

= 28 + 129 - 182 + 99 - 129 - 199 + 182

= 129 - 129 + 182 - 182 + 99 - 199 + 28

= 0 + 0 + (-100) + 28

= -72

\(\left|-28\right|+\left(129-182+99\right)-\left(129+199-182\right)\)

\(=28+129-182+99-129-199+182\)

\(=28+129+\left(-182\right)+99+\left(-129\right)+\left(-199\right)+182\)

\(=\text{ }\left[129+\left(-129\right)\right]+\text{ }\left[\left(-182\right)+182\right]+\text{ }\left[99+\left(-199\right)\right]+28\)

\(=0+0+\left(-100\right)+28\)

\(=\left(-100\right)+28\)

\(=-72\)

26 x 182 + 182 x 47 + 91 x 27 x 2

=26 x 182 + 182 x 47 +(91x2)x27

=26 x 182 + 182 x 47 + 182x27

= 182x(26+47+27)

=    182x100

=18200

26 x 182 + 182 x 47 + 91 x 27 x 2

= 26 x 182 + 182 x 47 +  ( 91 x 2) x 27

= 26 x 182 + 182 x 47 + 182 x 27

= 182 x ( 26 + 47 + 27 )

= 182 x 100

= 18200

182 x 13 + 91 x 28 + 182 x 73 

= 182 x 13 + 91 x 2 x 14 + 182 x 73 

= 182 x 13 + 182 x 14 + 182 x 73 

= 182 x ( 13 + 14 + 73 ) 

= 182 x 100 

= 18200

= 182 x 13 + 91 x 2 x 14 + 182 x 73 

= 182 x 13 + 182 x 14 + 182 x 73 

= 182 x ( 13 + 14 + 73 ) 

= 182 x 100 

= 18200

HT

a) 4600.              b) 1100.

c) 8100.              d) 7200.

Ta có \(A=\sqrt[3]{182+\sqrt{33125}}+\sqrt[3]{182-\sqrt{33125}}\)

\(\Rightarrow A^3=364+3.\sqrt[3]{182+\sqrt{33125}}.\sqrt[3]{182-\sqrt{33125}}.A\)

\(\Leftrightarrow A^3=364-3A\)

\(\Leftrightarrow\left(A-7\right)\left(A^2+7A+52\right)=0\)

Vì \(A^2+7A+52=\left(A^2+7A+\frac{49}{4}\right)+\frac{159}{4}=\left(A+\frac{7}{2}\right)^2+\frac{159}{4}>0\)

Do đó A - 7 = 0 => A = 7