Trả lời:

Chàoo pạnk ^~^

Chúc mừng pạnk đã qay trở lại nka~

Mà lần sau đừng đăng linh tinh nữa nhé ~

@Candy Candy

>333

report lun .

sao nó lại mờ thế?

nhiều thế này ai mà làm nổi

có quy tắc cho mấy cái này hết đó, e đọc xong là hiểu cách làm

Bài 3: 

2) Ta có: \(B=2x\left(y-z\right)+\left(z-y\right)\left(x+t\right)\)

\(=2x\left(y-z\right)-\left(x+t\right)\left(y-z\right)\)

\(=\left(y-z\right)\left(x-t\right)\)

\(=\left(24-10,6\right)\left(18,3+31,7\right)\)

\(=13,4\cdot50=670\)

3) Ta có: \(C=\left(x-y\right)\left(y+z\right)+y\left(y-x\right)\)

\(=\left(x-y\right)\left(y+z\right)-y\left(x-y\right)\)

\(=z\left(x-y\right)\)

\(=1.5\left(0.86-0.26\right)\)

\(=0,9\)

(D) bạn nhé mình ko nói dối  ko tin có thể thử lại

d

Hi my name is Linh and currently I’m 12 years of age. I have a nice personality and am very easy to get along with. This is my first semester of secondary school a lot of other people. What I to do in my spare time is to play video games and just relax with friends and family. People may see that as somewhat weird to play video games as a hobby, but it’s what I really to do. I prefer to enjoy things at my own space. This whole blogging thing is new to me and I really it. It could probably make me new friends and people that have common interests with me.

Kẻ AH⊥BC

ta có: \(VP=AB^2+BC^2-2.AB.BC.cosB=AB^2+BC^2-2.AB.BC.\dfrac{BH}{AB}=AB^2+BC^2-2.BH.BC=AB^2-BH^2+BC^2-2.BH.BC+BH^2=AH^2+\left(BC-BH\right)^2=AH^2+CH^2=AC^2=VT\)

-công,nhiệt,sự nổi

-gương

-1 ; -3; -7; -21; 1; 3 ; 7 ; 21

Ư(-21)={-21, -7, -3, -1, 1, 3, 7, 21}  

b a b b a

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