OK

:'')

_Ckao cậu!

cái bạn này hay nhỉ

thành viên mới thì kệ bạn, đăng làm gì cho mệt, có ai quan tâm đâu

kb vs mk đi

mình nè

11)\(\dfrac{3x+1}{x-5}+\dfrac{2x}{x-5}=\dfrac{3x+2x+1}{x-5}=\dfrac{5x+1}{x-5}\)

12)\(\dfrac{4-x^2}{x-3}+\dfrac{2}{x^2-9}=\dfrac{4-x^2}{x-3}+\dfrac{2}{\left(x-3\right)\left(x+3\right)}=\dfrac{\left(4-x^2\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}+\dfrac{2}{\left(x-3\right)\left(x+3\right)}=\dfrac{2+\left(2-x\right)\left(2+x\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\)

13)

\(\dfrac{3}{4x-2}+\dfrac{2x}{4x^2-1}=\dfrac{3}{2\left(2x-1\right)}+\dfrac{2x}{\left(2x-1\right)\left(2x+1\right)}=\dfrac{3\left(2x+1\right)}{2\left(2x-1\right)\left(2x+1\right)}+\dfrac{2.2x}{2\left(2x-1\right)\left(2x+1\right)}=\dfrac{6x+3+4x}{2\left(2x-1\right)\left(2x+1\right)}=\dfrac{10x+3}{2\left(2x-1\right)\left(2x+1\right)}\)

14)

\(\dfrac{2x+1}{2x-4}+\dfrac{5}{x^2-4}=\dfrac{2x+1}{2\left(x-2\right)}+\dfrac{5}{\left(x-2\right)\left(x+2\right)}=\dfrac{\left(2x+1\right)\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}+\dfrac{5.2}{2\left(x-2\right)\left(x+2\right)}=\dfrac{2x^2+5x+12}{2\left(x-2\right)\left(x+2\right)}\)

giúp j vậy bn

Đề ?_?

@Cpr

#Forever

giải phân thức ra là xong

chào bn

_Vg thành viên mới

Bớt nhảm hộ tao cái

\(a)7x-21=0.\\ \Leftrightarrow x=3.\)

\(b)3x-5=2x+7.\\ \Leftrightarrow x=12.\)

\(c)6x+18=0.\\ \Leftrightarrow x=-3.\\ d)5x+2=4x-1.\\ \Leftrightarrow x=-3.\)

Bài 1: 

a: 7x-21=0

=>7x=21

hay x=3

b: 3x-5=2x+7

=>3x-2x=7+5

=>x=12

c: 6x+18=0

=>6x=-18

hay x=-3

d: 5x+2=4x-1

=>5x-4x=-1-2

=>x=-3