giúp mình với

\(A=\frac{7x\left(2x2\right)^5x3^{11}+2^{13}x\left(3x3\right)^5}{\left(2x3\right)^{10}+2^{12}x3^{10}}\)

\(A=\frac{7x2^{10}x3^{11}+2^{13}x3^{10}}{2^{10}x3^{10}+2^{12}x3^{10}}\)

tự làm tiếp

\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=6^x\)

\(\Rightarrow\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}=6^x\)

\(\Leftrightarrow\dfrac{3^{29}\left(11-3\right)}{2^2.3^{28}}=6^x\)

\(\Leftrightarrow\dfrac{3.8}{4}=6^x\)

\(\Leftrightarrow6^1=6^x\)

\(\Leftrightarrow x=1\)

Vậy..

11x 3^22 x 3^7 - (3^2)^15 / 2^2 x 3^28 

11x 3^29 - 3^30 / 4 x 3^28 

11x 3^29 ( 1-3) / 4 x 3^28 

11x 3^29 .2 / 4 x 3^28

11x3/ 2 = 33/2

\(a,x^{10}=1\Leftrightarrow x=1\)

b, 2^x = 256 <=> 2^x = 2⁸ <=> x = 8

c, x¹⁰ = x

<=> \(x^{10}-x=0\)

<=> \(x\left[x^9-1\right]=0\)

<=> x = 0 hoặc x = 1

d, \((2x-15)^5=(2x-15)^3\)

<=> \((2x-15)^5-(2x-15)^3=0\)

<=> \((2x-15)^2.\left[1-(2x-15)^3\right]=0\)

<=> \(\orbr{\begin{cases}2x-15=0\\1-(2x-15)^3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{15}{2}\\2x-15=\pm1\end{cases}}\)

Tìm nốt x đi .

Lâu lâu chưa dạng gặp dạng này

e) \(\frac{11.3^{22}.9.35-9.15}{\left(2.3^{14}\right)^2}\)

\(=\frac{11.3^{22}.3^2.5.7-3^2.3.5}{2^2.3^{28}}\)

\(=\frac{3^3.5.\left(11.3^{20}.7-1\right)}{2^2.3^{28}}\)

\(=\frac{5.\left(11.3^{20}.7-1\right)}{2^2.3^{25}}\)

Đề bài sai ko vậy ?? kết quả ko có ra phân số hoặc số nguyên mà là số mà bạn chưa học đâu

a, \(4\times\left(-\dfrac{1}{2}\right)^3-2\times\left(-\dfrac{1}{2}\right)^2+3\times\left(-\dfrac{1}{2}\right)+1\)

\(=\left(-\dfrac{1}{2}\right)\left[\left(4\times-\dfrac{1}{2}\right)-\left(2\times-\dfrac{1}{2}\right)+3\right]+1\)

\(=\left(-\dfrac{1}{2}\right)\left(-2+1+3\right)+1\)

\(=\left(-\dfrac{1}{2}\right)2+1\)

\(=-1+1\)

\(=0\)

@Trịnh Thị Thảo Nhi

a,

a.. A = 3¹⁰ × 11 + 3¹⁰ × 5 / 3⁹ × 2⁴

A = 3¹⁰ × (11 + 5) / 3⁹ × 2⁴

A = 3¹⁰ × 16 / 3⁹ × 2⁴

A = 3¹⁰ × 2⁴ / 3⁹ × 2⁴

A = 3

C = 11 × 3²² × 3⁷ - 9¹⁵ / (2 × 3¹⁴)²

C = 11 × 3²⁹ - (3²)¹⁵ / 2² × 3²⁸

C = 11 × 3²⁹ - 3³⁰ / 2² × 3²⁸

C = 3²⁹ × (11 - 3) / 2² × 3²⁸

C = 3²⁹ × 8 / 2² × 3²⁸

C = 3²⁹ × 2³ / 2² × 3²⁸

C = 3 × 2

C = 6

\(E=\dfrac{11.3^{29}-3^{2^{15}}}{2.3^{14}.2.3^{14}}\)

\(=\dfrac{11.3-3^{30}}{2^2}=\dfrac{33-3^{30}}{4}\)